Thinking alpha down and beta up is not entirely accurate. That would only apply to D-sugars. The most accurate definition is if the -OH on the anomeric carbon is on opposite planes of the terminal -CH2OH group, that is alpha. If the -OH on the anomeric carbon is on the same plane as the terminal -CH2OH group, then it is a beta sugar.
The chair projection of D-a-Glucose, is the OH equatorial or axial? To me it should be axial since OH is pointing down in Haworth representation. Thanks
hi, this video has been really helpful, but can you pls explain why is it that the O on the 5th Carbon attacks the double bond. Is it impossible for the other oxygens to carry out nucleophilic attack?
You saved my semester, thank you :)
Thank you for posting these Biochem videos! They are helpful!
I'm so glad you find them helpful!
Best,
Dr. G
very lucid in explaining, thanks a lot
Very helpful, thanks!
Thinking alpha down and beta up is not entirely accurate. That would only apply to D-sugars. The most accurate definition is if the -OH on the anomeric carbon is on opposite planes of the terminal -CH2OH group, that is alpha. If the -OH on the anomeric carbon is on the same plane as the terminal -CH2OH group, then it is a beta sugar.
The chair projection of D-a-Glucose, is the OH equatorial or axial? To me it should be axial since OH is pointing down in Haworth representation. Thanks
hi, this video has been really helpful, but can you pls explain why is it that the O on the 5th Carbon attacks the double bond. Is it impossible for the other oxygens to carry out nucleophilic attack?
Why does cyclization of d glucose give two isomers of a and b d glucose?
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