Field of fractions, Noetherian rings 1

Lecture 20
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[@dipsacedemy]

Thank you

[@tomandjerry7524]

Amazing sir
Thank you so much 🥰

[@amitpandey6628]

Thanku so much

[@raphner2759]

13:15 Z(x1,...,xn)=Q(x1,...xn) since you can multiply both bumerator and denominator of a rational function over Q by the common denominators to get a rational function over Z.(I don't see qhy write it with Q)

[@rajtutions1986]

Z[1/2] is polynomial evaluation at x=1/2?

[@ashishraj7536]

Thank you