Euler Paths & the 7 Bridges of Konigsberg | Graph Theory

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  • Опубліковано 22 січ 2025

КОМЕНТАРІ • 29

  • @baotrantruong4541
    @baotrantruong4541 5 років тому +8

    Thank you so much! Yours is the first video I found that actually breakdown the logic of in-out and why there has to be 2 odd vertices.

  • @6thStringanishmandal
    @6thStringanishmandal 5 років тому +13

    you're going great, the way you give explanation touches the every contents and brings easy to understand

  • @novanuke1356
    @novanuke1356 4 роки тому +3

    I was really hoping this was a computer science channel because this concept was explained so well. Keep up the good work!

    • @jargomanihilda8743
      @jargomanihilda8743 2 роки тому

      Once you get to the theory there is no difference. Math is simply a programming language who's syntax is free written

  • @joneswafula
    @joneswafula 4 роки тому +5

    Trefor: Pause the video and try it out and see
    Me: Pauses videos and struggles to find path for 45 mins
    Trefor: It is impossible!!
    Love you guy! I feel like I owe you tuition fees or something

  • @ArpanDasgupta-q4n
    @ArpanDasgupta-q4n 8 місяців тому

    Suppose I remove one edge connecting AB. Consider path CBDBAC. Isn't this an Euler circuit? Why doesn't this contradict the Theorem at 4:45?

  • @MTHU0080
    @MTHU0080 2 роки тому +2

    It's so interesting that there's an impossibility in human creation. I wonder if they ended up building another bridge to solve the problem.

  • @prithujsarkar2010
    @prithujsarkar2010 3 роки тому

    Can you share me the video link where you told this 5:20
    i am curious to see the proof of the other direction of this statement

  • @nathansudermann-merx4586
    @nathansudermann-merx4586 Рік тому

    Great explanation, great visualization. Thank you.

  • @MagnusTheUltramarine
    @MagnusTheUltramarine 3 роки тому

    At 4:35 you say that if it even has 1 vertex with odd degree, then there is no Euler Circuit, but isn't that contrary to what you said before, that if it starts odd and the last vertex is also odd, but everything in the middle is even, then there is an Euler Circuit.
    For example: Take ABCDE, A and E have 3 vertices, but BCD have two (A:B, A:C, A:D, B:E, C:E, D:E), you can have an Euler Circuit

  • @vaitheeswari8078
    @vaitheeswari8078 2 роки тому +1

    Great work sir

  • @instaminox
    @instaminox 5 років тому +1

    Great job Trefor!

  • @tanug3191
    @tanug3191 4 роки тому +1

    Well explained👏👏
    Thank you so much it was worth watching 😍

  • @amrel-demerdash2369
    @amrel-demerdash2369 4 роки тому +1

    What about If E= {(A,C),(A,B),(B,C),(C,B)} then the degree of A = 2, B = 3, c = 3 and you have a Euler path (C -> A -> B -> C -> B)?
    I googled it and found "if a graph is connected and has exactly 2 odd vertices then it has an Eurlerian path "

    • @KrishnaSingh-mm8hx
      @KrishnaSingh-mm8hx 3 роки тому

      Yeah,but the eulerian path should start from one of the odd vertex and end at the other,in that case.

  • @nitinjuyal7739
    @nitinjuyal7739 3 роки тому

    Superb explanation

  • @prithujsarkar2010
    @prithujsarkar2010 3 роки тому +1

    Great explanation :)

  • @nadred5396
    @nadred5396 Рік тому

    What if you took out two Edges from A to B and B to C, wouldn't some vertices be odd degree and and Euler path be possible? Or does that not count because you went to A twice? But you didn't use the edge twice?

    • @metinunlu_
      @metinunlu_ 7 місяців тому

      I was also thinking on this

  • @austino_climbs
    @austino_climbs 6 років тому

    Really good video and well explained! Thanks!

  • @felipesalvador3722
    @felipesalvador3722 3 роки тому

    In the six-bridge problem as shown by the graph below, how many ways are there of traversing all six bridges (shown as edges here) exactly once?

    • @MagnumCarta
      @MagnumCarta 2 дні тому

      There are seven bridges so it is impossible to go through each bridge exactly once. That is proven because the degree of the graph must be even to contain an Euler Path or its sub-type a Euler Circuit.

  • @pekka8719
    @pekka8719 Рік тому

    great shit bro

  • @nidhinhari8397
    @nidhinhari8397 5 років тому +1

    Amazing💕😍

  • @shrutinehra1104
    @shrutinehra1104 2 роки тому

    solve 👇⬇️
    In seven bridges problem, was it possible for citizen of Konigsberg to make a tour of the city and cross each bridge exactly twice? Give reason

  • @mohokhachai
    @mohokhachai 11 місяців тому

    Thanks

  • @continnum_radhe-radhe
    @continnum_radhe-radhe 8 місяців тому +1

    ❤❤❤

  • @jargomanihilda8743
    @jargomanihilda8743 2 роки тому +1

    He pronounces Euler as oiler, I call it a YOU-ler

  • @Dhjsjebvebehw
    @Dhjsjebvebehw 8 місяців тому

    the mic is bad and too loud