So, ermmm ... what are the square roots of 5 and 35 (or, for that matter, sqrt(7)) and what is the result of performing that mathematical jiggery-pokery on them? If any student of mine tried telling me that the solution to the problem is (4 + sqrt(7))/3 they'd be given a sharp lesson on the difference between solve and simplify, then told to go and solve it as they were asked. I wouldn't be tough on them, I'd only want it to two decimal places...
Interesting 🎉
I hate it when they say “solve”, but they mean “simplify”.
Это задача для решения в уме.
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Divide all terms by sqrt(5). Multiply by (sqrt(7) +1)/(sqrt(7) + 1).
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Too easy
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So, ermmm ... what are the square roots of 5 and 35 (or, for that matter, sqrt(7)) and what is the result of performing that mathematical jiggery-pokery on them?
If any student of mine tried telling me that the solution to the problem is (4 + sqrt(7))/3 they'd be given a sharp lesson on the difference between solve and simplify, then told to go and solve it as they were asked. I wouldn't be tough on them, I'd only want it to two decimal places...
0,(3)(4+V7).
Сразу решила 2м способом
I did it in less than a minute.
Too easy to be from Math Olympiad
(4 +✓7)/3.
✓35+✓5 /✓35-✓5 =✓(35+5) / ✓(35-5) = ✓8•5 / 6•5= ✓ 4 / 3 = 2✓1/3.
До этого хрен догадаешься....
(✓35 + ✓5)/(✓35 - ✓5) =
(✓35 + ✓5)^2 / (✓35 - ✓5)(✓35 + ✓5) =
(40 + 10✓7)/30 = (4 + ✓7)/3
(4+{7})/3?
И чем метод 2 отличается от метода 1?
Одно и то же решение , отличается лишь на сокращение корня из 5
Это не олимпиадная задача, слишком просто для олимпиады