For that 2nd problem, we are revolving the area around the y-axis, so the boundaries of integration have to be the smallest y-value to the largest y-value of the area. The smallest y-value is 1, and the largest y-value is 5. If you look at the picture (8:23), you can see that bottom of the solid is at 1, and the top of the solid is at 5.
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thank you so much for doing unit 8 - i just went through your whole playlist and everything is completely clear!!
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Same, his voice is so soothing and he really knows his stuff! 🙂🤯
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Thank you so much! It makes so much sense now!
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Was 5 and 1 choose randomly cause if I try find the y intercepts its 2 and 1
For that 2nd problem, we are revolving the area around the y-axis, so the boundaries of integration have to be the smallest y-value to the largest y-value of the area. The smallest y-value is 1, and the largest y-value is 5. If you look at the picture (8:23), you can see that bottom of the solid is at 1, and the top of the solid is at 5.
thnks
2:43 ONE PICE
i don't understand why you take 1 and 5
Very noice