Correction Questions No 17 52:41 Check Here Correct Answer Since 52 - 33 =19, 78 - 59 = 19, 117 - 98 = 19 We see that the remainder in each case is less than the divisor by 19. Hence, if 19 is added to the required number, it becomes exactly divisible by 52, 78 and 117. Therefore, the required number is 19 less than the LCM of 52, 78 and 117. The LCM of 52, 78 and 117 = 468 the required number =468 - 19 =449 Sum 4+4+9= 17
1. 964-41=923 1238-31=1207 and 1400-51=1349 Now greatest no. Of HCF is 71 2. 30pineapple tree,45orange tree and 60mango tree (30+45+60)=135 total tree . Now HCF of all trees is 15 When 135/15=9 Its been good always solving problems with u sir 🙏🙏🙏 Love nd respect from western odisha (Kalahandi dist.)
1 . ANS - 71. 2. ANS - 9. Chimmay Sir 😍 is a teacher who has no ego, no attitude, no jealousy and a man with zero hatters❤. Who always cares for everyone and wins heart of every student. Love and respect for you from the core of my heart. I'M FROM GANJAM ❤.
Thank you so much sir....Aponanko Asirbad au Way of teaching pain aji mu first time Reasoning re 20 ru 20 Rakhichhi Ignou BED re....Thank u so much sir.....Blessings me sir for RI Entrance 🙏🙏🙏🙏
Ans - Q-(1)=71 & Q(2)=9 Chinmaya sir is the great inspiration of all odiaha aspirants who are want to crack govt exams and became like Chinmay sir . Really Chinmay sir is a great teacher ❤❤❤❤❤. Dilse love you sir .❤❤❤❤
Pranam sir.bahut sundar class.mote emiti feel hauchhi apna mora ati nijar sir.apananka math au reasoning class mote bahut vala laguchhi.apana asirbad karantu samasthe emiti agaku jaantu. 1.ANS 71 2. ANS 9 THANK YOU SO MUCH SIR.I REALLY LIKE YOU SIR
Sir tk late re class dekhili 1-71 2-9 Sir math ହେଉ କି motivation ଆପଣ ସବୁବେଳେ ଆଗରେ ରହିବେ sir ଆପଣଙ୍କ class ଦେଖିଲେ ମତେ ଲାଗେ ମୁଁ ପୁଣି ସ୍କୁଲ ରେ ଜଣେ ଆଦର୍ଶ ଗୁରୁ ଙ୍କ ଆଗରେ ବଶି ପଢୁଛି 🙏
Sir mu apanankara besi class dekhini but jetiki dekhichhi mote feel hua ki mote mora tution sir padhauchhanti... Bahuta apana ra laganti... Sir..... Ame sabu adhanya sir apana nka bhali teacher paiki...( Pranam)
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Correction Questions No 17 52:41
Check Here Correct Answer
Since 52 - 33 =19, 78 - 59 = 19, 117 - 98 = 19
We see that the remainder in each case is less than the divisor by 19.
Hence, if 19 is added to the required number, it becomes exactly divisible by 52, 78 and 117.
Therefore, the required number is 19 less than the LCM of 52, 78 and 117.
The LCM of 52, 78 and 117 = 468
the required number =468 - 19 =449
Sum 4+4+9= 17
Sir option re 17 sankhya nahi
Seti to 17 nai sir option re
17କେମିତି ହେଲା
Sir video re sound asuni
R8 ,mu seya comment Debi boli dekhila belaku apana correction Kari lekhisarichhanti
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Dear Chinmay Sir, You r really a gem for all aspirants 💎;
କିନ୍ତୁ ଆଜି morning ରୁ ହଠାତ୍ ଦେଖି ମୋତେ ବହୁତ୍ ଦୁଃଖ ଲାଗିଲା ଯେ, ଆପଣଙ୍କ channel ଏପର୍ଯ୍ୟନ୍ତ monetize ହୋଇନି। ସମସ୍ତଙ୍କୁ ବ୍ୟକ୍ତିଗତ ଭାବେ ଅନୁରୋଧ କରୁଛି କି kindly views ଓ subscriber ବଢାଇ ସାରଙ୍କ channel କୁ ଶୀଘ୍ର monetize ହେବାରେ ସହଯୋଗ କରନ୍ତୁ । ଯେଉଁମାନେ ମୋ କଥାରେ ଏକମତ ଗୋଟେ like କରନ୍ତୁ।❤❤👍
1. 964-41=923 1238-31=1207 and 1400-51=1349
Now greatest no. Of HCF is 71
2. 30pineapple tree,45orange tree and 60mango tree (30+45+60)=135 total tree .
Now HCF of all trees is 15
When 135/15=9
Its been good always solving problems with u sir 🙏🙏🙏
Love nd respect from western odisha (Kalahandi dist.)
Sir your math is awesome ❤❤❤
25:11
Best
Hi Jitu, Can you please explain how is the answer is 71
@@tpuspabati4831 HCF of 923,1207 and 1349 is 71 brother
Thank you bro
1 . ANS - 71.
2. ANS - 9.
Chimmay Sir 😍 is a teacher who has no ego, no attitude, no jealousy and a man with zero hatters❤. Who always cares for everyone and wins heart of every student.
Love and respect for you from the core of my heart.
I'M FROM GANJAM ❤.
Hello bhai computer computer darkar ki
😅
2no ta 15 heba
A :- 71
B :- 9
Your great sir
ଜୟ ଶ୍ରୀଜଗନ୍ନାଥ*🙏/ପ୍ରଣାମ ସାର୍🙏/ସାର୍ ଆପଣଙ୍କୁ ବହୁତ ବହୁତ ଧନ୍ୟବାଦ, ପିଲାମାନଙ୍କ ମନ କଥା ବୁଝିଥିବାରୁ.👍👍
Thank you so much sir....Aponanko Asirbad au Way of teaching pain aji mu first time Reasoning re 20 ru 20 Rakhichhi Ignou BED re....Thank u so much sir.....Blessings me sir for RI Entrance 🙏🙏🙏🙏
Ahita odisha ra no 1 chennal jaha free re sabu knowledge miliparuchhi
Ans - Q-(1)=71 & Q(2)=9
Chinmaya sir is the great inspiration of all odiaha aspirants who are want to crack govt exams and became like Chinmay sir . Really Chinmay sir is a great teacher ❤❤❤❤❤. Dilse love you sir .❤❤❤❤
A great facilitator n a good human being,down to earth person i have ever seen in my whole life. 🙏🙏🙏🙏🙏🙏
Hello
Sir you are teaching like my father ❤🙏🏻😊.
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To aap uncle se padhai karo na 😁
Sir emiti sabu chapter ru karantu
@@Titli-e4iyou from??
@@chinmayapanda7226sir difficult laguchhi written lagaiba
Pranam sir.bahut sundar class.mote emiti feel hauchhi apna mora ati nijar sir.apananka math au reasoning class mote bahut vala laguchhi.apana asirbad karantu samasthe emiti agaku jaantu.
1.ANS 71
2. ANS 9 THANK YOU SO MUCH SIR.I REALLY LIKE YOU SIR
Any one in 2024❤❤ Assemble here❤️❤️❤️
Jai Jagannath,Sir, Pranam,Bhagaban aapankara ,aapanka paribarara mangala karantu .Aapana Dirghajibi huantu Odishara pratyekti student nischaya Toper hebe boli Jagannath Mahaprabhunka pakhare ammara prathana.
Thank you so much,, if possible kindly provide us on daily basis
1-71
2-9
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1.71
2.15
Thank you Sir for this wonderful teaching
1) 71
2) 9
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Dhanya bada
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1-71
2-9
Sir math ହେଉ କି motivation ଆପଣ ସବୁବେଳେ ଆଗରେ ରହିବେ sir ଆପଣଙ୍କ class ଦେଖିଲେ ମତେ ଲାଗେ ମୁଁ ପୁଣି ସ୍କୁଲ ରେ ଜଣେ ଆଦର୍ଶ ଗୁରୁ ଙ୍କ ଆଗରେ ବଶି ପଢୁଛି 🙏
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Hw- Qtn 1- 71
Qtn 2- 9
Thank you Sir 😊
Amazing Session 🙏
From Dhenkanal ♥️
HW
1.71
2.P-2+O-3+M-4(Each row contain 15trees)=9
Real educator. ❤❤❤
Your Techniques of studying is nice..
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Sir mu apanankara besi class dekhini but jetiki dekhichhi mote feel hua ki mote mora tution sir padhauchhanti... Bahuta apana ra laganti... Sir..... Ame sabu adhanya sir apana nka bhali teacher paiki...( Pranam)
Thank you sir. Sir 449 is correct Ans. If 19 is added with 468 then 19 is remainder for all 3 Divisors.
Sir... 🙏... You are very motivated.
Thank u so much sir... Emiti Class sabubele anantu sir..
Basic concept clear hebapain... Apananka Class amapain bahut helpful heuchhi...
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(Q1) b-71
(Q2) b-15
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Answer will be
a)71
b)9
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Weak
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1.71
2.9
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1-71
2-9
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1. 71
2. 9
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bahut badhiya lagila class
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1-71
2-15
(1)=71
(2)=9
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1-71
2-9
Thank you sir
Thank you for the valuable motivation sir
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Ans,
1---72
2---15
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my favorite sir 🙏
🙏🙏sir 🎉 ans 1-71,2-9 thank you sir🎉🎉
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