My math book taught me nothing. Your videos have been brilliant, explaining everything. I can't even say how thankful I am for your style of teaching here. Well done.
your tutorials are making me understand calculus in a different way,,,,,, actually u have taught me a lot i dindn't know raising my positive attitude towards mathematics,,, just amazing thanks very much
@Darkness- not exactly sure which bit you mean at 11:00 - if you are referring to the h on the bottom x(x+h) this will only equal zero if the x value is zero. Otherwise there will be a number eg x=1 ; 1(1+0) = 1x1 = 1
At the end there when you are left with (1/(2sqrtx)), why is it that you only plug in 1/2 for x and not set the whole thing to -1? The graph of f(x)=sqrtx doesn't even have a point at (1,-1) so how are you trying to find a tangent line to a point that doesn't exist?
Apalion41 The point (1,-1) lies on the line f(x) = plus and minus sqrt(x). He has the two confused. I was puzzled, as it would have to have a negative gradient due to the shape of the graph, but he has found the wrong derivative and so the gradient is wrong. It should be plus and minus 1/2 if he had the correct line. Of course this gets us two different gradients, because f(x) = plus and minus sqrt(x) is not a function (which refers to a line with only one y value for any given x value). The point also lies on f(x) = -sqrt(x), which is a function, and only has one gradient for that point. He is just missing a minus, and has found the mirrored graph's gradient for that x value, if that makes any sense.
How to solve this sums below 1) dx/dy = xy 2) (1+cos 2¤) dx/dy = 2, at y =1 when ¤ = #/4 3) A rumour spreads through town at a rate which is proportional to the product of the number of people who have not heard it and those who heard it. Given that x is a fraction of the town who have heard the rumour after time t A) Form a differential equation x,t and a constant K B) If initially a fraction C of the population had heard the rumour, deduce that x= C/C+(1-C)e^-Kt C) Given that 15% had heard the rumour at 9:00am and another 15% by noon. Find what further fraction of the population would have heard the rumour at 3:00pm Those ones👆👆👆👆👆👆👆👆
you have taught me more in 20 minutes than i have learned in 3 weeks
same here man
My math book taught me nothing. Your videos have been brilliant, explaining everything. I can't even say how thankful I am for your style of teaching here. Well done.
Thanks everyone for your kind words. Much appreciated :)
I have an exam tomorrow and you saved me, thank you
your tutorials are making me understand calculus in a different way,,,,,, actually u have taught me a lot i dindn't know raising my positive attitude towards mathematics,,, just amazing thanks very much
Thanks. You're helping a complete calculus novice here.
Awesome video
Thnx teacher... Your explanation is so simple
@Darkness- not exactly sure which bit you mean at 11:00 - if you are referring to the h on the bottom x(x+h) this will only equal zero if the x value is zero. Otherwise there will be a number eg x=1 ; 1(1+0) = 1x1 = 1
Keep going on u help people's of world
thank god i found your channel man
Nice video.
Very nice
Good video
Great video for Calculus noobs. Thanks!
Helped a lot thanks 👌
this helped me a lot thanks for making this video
Great video, thanks a lot
thx man...helped a lot
Great
Terrific..i love that
this is good despite the complications
10x +5h-1
Where did you get the -1 in your answer?
-h divided by h would give -1
you deserve a million views!!!!!
so you mean it depends with question asked or you just apply differentiating from first principles
At the end there when you are left with (1/(2sqrtx)), why is it that you only plug in 1/2 for x and not set the whole thing to -1? The graph of f(x)=sqrtx doesn't even have a point at (1,-1) so how are you trying to find a tangent line to a point that doesn't exist?
Apalion41 The point (1,-1) lies on the line f(x) = plus and minus sqrt(x). He has the two confused. I was puzzled, as it would have to have a negative gradient due to the shape of the graph, but he has found the wrong derivative and so the gradient is wrong. It should be plus and minus 1/2 if he had the correct line. Of course this gets us two different gradients, because f(x) = plus and minus sqrt(x) is not a function (which refers to a line with only one y value for any given x value). The point also lies on f(x) = -sqrt(x), which is a function, and only has one gradient for that point. He is just missing a minus, and has found the mirrored graph's gradient for that x value, if that makes any sense.
How to solve this sums below
1) dx/dy = xy
2) (1+cos 2¤) dx/dy = 2, at y =1 when ¤ = #/4
3) A rumour spreads through town at a rate which is proportional to the product of the number of people who have not heard it and those who heard it. Given that x is a fraction of the town who have heard the rumour after time t
A) Form a differential equation x,t and a constant K
B) If initially a fraction C of the population had heard the rumour, deduce that x= C/C+(1-C)e^-Kt
C) Given that 15% had heard the rumour at 9:00am and another 15% by noon. Find what further fraction of the population would have heard the rumour at 3:00pm
Those ones👆👆👆👆👆👆👆👆
In example 3, why do you have to multiply the equation by 1/h?
ANDY JR Instead of dividing a fraction by a fraction (divide by h) I multiplied by the reciprocal of h which is 1/h.
Ohh right, I missed that. Thanks :)
Divide by zero. XD Good tutorial, man.
I am fourteen, have not even started Calculus / First Principle yet, It is Four im the morning and I am bloody tired.
Thanks very much
awesome :)
thank you so much for this
Did anyone else work out example 4 before watching the explanation and get 1/2i??
lol same here
Life saver
why not -1+h in eg2
thanks tho this is helpful
sussy McSus burger
on example 3 why h =0
What's that? What country are you from with that pronunciation of "h"?
What if x was -1 would the answer be 2i ?
I don´t really think "math-spays" thought their name though :P
the way h is pronounced just bothers me so much lol haha
Haych minus Haych
Mujha nhi aaya samajh ma😭😭😭😭
HEITCH