+Sachin Pandy اريد ان أسألك يامستر ساشين هل يمكن استنتاج المنظور من مسقطين على برنامج الاوتوكاد مباشرة مع تمنياتي لك ولأسرتك بالتوفيق والنجاح المستمر وأكرر شكري وتقديري لشخصكم الكريم
A straight line PQ, equally inclined to the HP and the VP, has its end P in front of the VP and 20 mm above the HP. End Q is behind the VP and 40 mm below the HP. A point on this line is in the VP and 10 mm below the HP. Draw the projection and finds TL and inclination of line with HP, if the distance between the projections ends is 60 mm.
Hola, tengo muchas ganas de hacerlo en más idiomas, pero no estoy seguro sobre el traductor de Google, así que no lo haré, pero veamos si lo estoy haciendo en un futuro cercano, se lo haré saber gracias
Sachin Pandya Yes I came across many questions which two views will be given and I am asked to draw a third view, without knowing what the object looks like.I had trouble "visualising" the object
Sir job ka second part vaala hissa base SE 15 mm uppar ki taraf hai aap bhul gaye aur side se 15 mm andar hai vo correct hai but second part job ka base SE uppar vaala kaam reh Gaya by mistake aapse incomplete 😂😂😂
crank OA rotates about O and the rod AB which is connected to crank OA at A is concentrated and to pass through the guide at p trace the locus of point B for complete revolution of the crank OA. OA =40 AB=120 OP=60
The same video in Hindi with better sound and editing ua-cam.com/video/-KVhMAILAVs/v-deo.html Length = 120mm Width = 60mm and Height = 75mm
This guy teaches so much content in such short time, also no compromise on the explanation,his explanations are right on the point
:)
Excellent Teacher. Has ruler for hands.
thanks sir you are a talented drawer, pretty quick and accurate! Thanks for sharing your procedure
اشكرك سيد ساشين من كل قلبي على ماتبذله لتعليم ونشر هذه العلوم
اشكرك
+Sachin Pandy
اريد ان أسألك يامستر ساشين هل يمكن استنتاج المنظور من مسقطين على برنامج الاوتوكاد مباشرة
مع تمنياتي لك ولأسرتك بالتوفيق والنجاح المستمر وأكرر شكري وتقديري لشخصكم الكريم
شكرا لكم الهند نحن لا تزال تفعل صياغة ذلك أنا لم مع الطريقة التقليدية في المستقبل وأنا سوف تستخدم نذل السيارات أشكر كذلك لكم مرة أخرى لرغباتكم
A straight line PQ, equally inclined to the HP and the VP, has its end P in front of the VP and 20 mm above the HP. End Q is behind the VP and 40 mm below the HP. A point on this line is in the VP and 10 mm below the HP. Draw the projection and finds TL and inclination of line with HP, if the distance between the projections ends is 60 mm.
Very good work sir I Appreciate
Delivery Case :)
thank you so much sir this video was so helpful!
great job,my easy way of studying
Michael kibe 😊
شرحك جميل ياخواجه
شكرا جزيلا
thank you very much for all your videos you are awsome !
:)
thanks it helped me a lot
Thank you sir 💙
thank you for this video
The circle is incomplete. So if you r watching it please don't copy as it is 🤷♀️✔️
Can you explain more
Thank you sir it was very useful
:)
Thank u so much this que is ask in my exams for 12mark
And l prepare this before the exam
Amar Naik I am happy for you 😊
Good job sir
:)
wow great jop
Amani Mansour :)
Thank you very much Sir! This playlist has been super helpful to me:)
respect
GOOOOOOOOD
soufiane el annaoui :)
Clarity
Nice I'm also D.M
very nice trick
Pandurang Damargide 😊
Great videos sir!
:)
When you're in Year 9 and watch this video. Brain seizure
:)
Beautiful problem
Sachin sir
Explanation is excellent
How can draw any picture
Rahul Reddy picture? Can you explain more thank you 😊
@@technicaldrawing xloyrw 43790sghmvxxe by see
Do a at
nice trics
Far better than my Teacher
Me gusto mucho el video, es muy preciso, el detalle que no me gusto es que el video es en ingles, pero de resto esta bien para mi, saludossssss
Hola, tengo muchas ganas de hacerlo en más idiomas, pero no estoy seguro sobre el traductor de Google, así que no lo haré, pero veamos si lo estoy haciendo en un futuro cercano, se lo haré saber gracias
Ohhhhhh
nyc vdo
Mujahid Sayyed :)
Length = 120 width = 60 and height = 75
6:24 that line definitely isn't in 30º
tizam0 It is vertical line
so I'm correct haha
How do I draw if I am not given the Isometric picture?
are u talking about question ?
Sachin Pandya Yes I came across many questions which two views will be given and I am asked to draw a third view, without knowing what the object looks like.I had trouble "visualising" the object
see Missing view in my playlist you will get help from there and i will upload few more in that list which would be sufficent
Sachin Pandya Thank you sir
Thnxx sir
:)
Good sir
:)
Hands down 😇
good sir
Good
thank you sir ji
:)
Sir can you do more isometric sums
Yash Unavane Sure i will
Wow, very complicated I just want to better my art work
aprende a hablar español porfavor 7w7 bueno te dejare mi like de resto es un buen tu tutorial agradable tienes buena precision
si o ke :v jajajaja
Mi hijo está aprendiendo en la escuela. Tomaré lecciones de el
super
:)
Jai balayya babu
sir side view le kar ak drawing banaye
SANJAY MAHTO sure
hitting brain
Sai Eswar 😊
Sachin Pandya
better than others videos
Thank you
Dimage ka bharta Ban gaya!!
When a teacher in UA-cam teaches better than my teacher🙄
Sir job ka second part vaala hissa base SE 15 mm uppar ki taraf hai aap bhul gaye aur side se 15 mm andar hai vo correct hai but second part job ka base SE uppar vaala kaam reh Gaya by mistake aapse incomplete 😂😂😂
Typical teacher response would be " I wanted to see how many of you can see the mistake " 😉
Sir middle width in T.V is 18 ... Not 16
Ok
@@technicaldrawing Today was My caed exam... And I prepared from your videos. My caed paper was too easy for me😀👍👍thank you sir ❤️
I am happy for you ☺️
Sir kya aap locas of point sikha sakte hai pizzz
Yes send me questions
crank OA rotates about O and the rod AB which is connected to crank OA at A is concentrated and to pass through the guide at p trace the locus of point B for complete revolution of the crank OA. OA =40 AB=120 OP=60
clean af!!!
6
:)
In the very beginning u have written H=60,W=75...... where as H=75 and W=60
Yes you are right my mistake thank you
@@technicaldrawing But thank you for making all this video's for students... it's really helping us a lot😊😊😊
That half circle doesn't come properly
Try once again or send me your answer on sachinpandya2602@gmail.com
Ok
@@technicaldrawing I am taking x axis on right side
@@LoveIsLifeTurkishIndia can you send me your answer will guide you accordingly
@@technicaldrawing sended , by email I'd vdedavat@gmail.com
Kuch bhi samaj nahi AA Raha hai 😢
good sir
:)