Odds of getting witch thrice in a row. Total cards 109. Probability in 1 match 1/109 Probability in 3 matches (1/109)³ =1/1,295,029. So yeah 1 in a million chance. Considering clash royale gives equal weightage to all cards in randomly generated decks.
actually it’s more like this: - there are 109 cards, 5 champions with means we only have 105 cards to chose from (the 105th card is ANY champion) sooo, imma try and do the math now. I think it’s like this: chance as first card: 1/105, chance as second card: 1/104, … and so on. We have to sum them all up wich comes to 7,88%. Thus to the third power is 0,049%. Let’s take 0.050%, and that is 1/2000 ! edit: when I do it like you do it’s: 8/105 = 7,61% (close enough) and to the third power it’s 0.044%. Don’t know wich one is the most accurate one though 🤨
@@alexandervanhoorick5899 we would have 105 combinations for each match. No need to do 104 and 103 because each match we will have all the 105 cards in our arsenal.
The odds of getting a witch 3 times in a row out of 109 cards is 1 in 15000000000. But the game randomly generated isn’t 100% random. They give you like 1 or 2 spells. 1 or 2 air cards. Etc.
I may be wrong, but I believe the odds of drawing a witch 3x in a row is 1/1,295,029 or quite literally 1-in-a-million. Edit: I was wrong. Forgot to factor in that you have 8 chances to pull the witch since there's 8 card slots in a deck. I still may be wrong cause math is hard, but it should be 0.04% or about 45/125,000 Tl;dr: 0.04% chance, 45/125,000
i think i did the calculations and it said it had a 0.0999% chance of getting witch 3 games in a row because 109 cards and 8 slots in the deck so then each time the witch has around a 7 percent chance of being in your deck lets use the numbers 700 of 10000 but 3 times in a row is like 7 percent of 700 which is 100 and 7 percent of that which 10 so its a 10 in 10000 which is 0.0999%
Answering Hunter's question about chances: What are the odds that two randomly chosen decks repeat at least 1 card? Hey Hunter! Diving into the Clash Royale universe, let's tackle this puzzle. From 109 total cards, picking the first deck of 8 has 109C8 ways (that’s a whopping 379,908,847,539 options - someone's been busy designing cards!). Once you've splashed the first 8 cards on the table, 101 shy cards are left. For a second deck without stealing any of the first deck's thunder, it's 101C8, aka 202,095,455,100. Doing some Clash math: if we allow every card in either deck, there are 109C8 x 109C8 chances. That’s 379,908,847,539 x 379,908,847,539 (sounds like a number the Electro Wizard would zap). But if we're looking for two completely unique decks, it's 109C8 x 101C8, which turns out to be 379,908,847,539 x 202,095,455,100. Crunching those numbers, the odds of both decks being total strangers? 109C8 x 101C8 / (109C8 x 109C8). About 53.19% Flip the script, and the odds of them sharing at least one card is 1 - 0.5319, which gives us a fun 46.81% So not THAT rare. In fact, almost a half chance of at least one card repeating. Cheers!
there are 109 cards in the game, but due to only being allowed 1 champion per deck there are 105 possible cards you can have. in a random deck and for every shuffle you have a 8/105 of getting any card, so the odds of getting witch 3 times in three matched in a row are 512/1157625
@@loplaynstyle3641 That makes the calculation a bit more complicating but i'm gonna do it as simply as possible. Becuz we can only use 1 champion in a deck so the first slot, we can choose 1 of 109 cards, but the second slot only 105( cuz we already chose a champion and we cant use the other 4). The third slot is 104 and so on. So the result will be: (109x105x104x103x102x101x100x99)^3 cuz shuffling deck 3 times. And then 1/the result, that's the percentage
8 cards in a deck, 109 cards total. Chance of getting witch in 3 decks in a row = (8/109)^3 = 0.000395357.... = 0.0395357....% = 0.04% (2 decimal places). This is the same chance as it is for you to select 25 people at random and them all having schizophrenia.
How nice of you to play with Ryleys biggest fan 🥰
*boyfriend
Ian even made sure to spend his money on both the goblin hero skins and the goblin base theme in clash of clans. It's true loyalty ngl
@@juicebox682i wish theyd kiss thatd be so hot
Ryley never won best of 5 against Ian 77 what are you talking about ?
@@hakisyt9519 dude ... chill 🫠
4:15 funny the hunter killed the pig. Thought there was a glitch. 😅
Wow, hunter shot, died to become piggie and again died of the bullets released by itself in its past life.
Wow didn't even notice that 😮
Wait just saw this and that was crazy
Was just going to comment this. Man did not want to be a pig so he killed himself 😂
You could do one of this random decks but replace one card with xbow against eragon, could be fun
Good idea fam
this was a really good video idea. nice one. we want more of theses tipe of videos :D
Odds of getting witch thrice in a row.
Total cards 109.
Probability in 1 match 1/109
Probability in 3 matches (1/109)³ =1/1,295,029.
So yeah 1 in a million chance. Considering clash royale gives equal weightage to all cards in randomly generated decks.
Don’t you have to technically divide it by 8 since the witch could have a chance at all the slots?
It’s wrong didn’t divide by 8 the chance is one in 1/127265 which is 0.000785
actually it’s more like this:
- there are 109 cards, 5 champions with means we only have 105 cards to chose from (the 105th card is ANY champion)
sooo, imma try and do the math now.
I think it’s like this: chance as first card: 1/105, chance as second card: 1/104, … and so on. We have to sum them all up wich comes to 7,88%. Thus to the third power is 0,049%. Let’s take 0.050%, and that is 1/2000 !
edit: when I do it like you do it’s:
8/105 = 7,61% (close enough) and to the third power it’s 0.044%. Don’t know wich one is the most accurate one though 🤨
@@alexandervanhoorick5899 we would have 105 combinations for each match. No need to do 104 and 103 because each match we will have all the 105 cards in our arsenal.
Crazy video idea ❤️🔥 i really enjoyed watching every single minute 👏❤️
My two fav clash youtubers lets go!
First game_45s to end_hunter kills himself as a pig😂
everyone gonna steal this idea without giving you credit LMAO
second time refreshing my recommended page and you pop up with 36 seconds ago, what timing
The odds of getting a witch 3 times in a row out of 109 cards is 1 in 15000000000. But the game randomly generated isn’t 100% random. They give you like 1 or 2 spells. 1 or 2 air cards. Etc.
And it also picks 8 times since 8 cards. So just what sort of dumb dumb method did you use to count?
@@minipottu3943Including that its 1/2530ish
But even excluding that its 1/1,295,029 so idk how he got that number
@@lucass4827 I pulled it out of my ass tbh
How about megadraft with another youtuber where opponent chooses few of your cards
Would be sick if you got his commentary also and you could switch between them so we can know what hes thinking too
Asking Hunter to play grave-bow, day 1 😅
Hunter out with another banger
The odds are (109/8)^3 work that out yourself. That is if ever card has the same chance of appearing.
average midladder match:
Man if I had a penny for every time I was early...
11:57 Bro I did the math and it’s literally one in 1/127263 times if you got the witch 3 times in a row😧 which is 0.000785%
woa
I may be wrong, but I believe the odds of drawing a witch 3x in a row is 1/1,295,029 or quite literally 1-in-a-million.
Edit: I was wrong. Forgot to factor in that you have 8 chances to pull the witch since there's 8 card slots in a deck. I still may be wrong cause math is hard, but it should be 0.04% or about 45/125,000
Tl;dr: 0.04% chance, 45/125,000
Ur right! 1 in 2529
Well the random deck generation isnt 100% random
Sheesh
You should do this as a series vs Ryley, eragon, sk_555, Nate, boss, and innvader
Nice video man I haven’t even watched it yet
Mega draft against Ian PLEASEEE
i think i did the calculations and it said it had a 0.0999% chance of getting witch 3 games in a row because 109 cards and 8 slots in the deck so then each time the witch has around a 7 percent chance of being in your deck lets use the numbers 700 of 10000 but 3 times in a row is like 7 percent of 700 which is 100 and 7 percent of that which 10 so its a 10 in 10000 which is 0.0999%
Answering Hunter's question about chances:
What are the odds that two randomly chosen decks repeat at least 1 card?
Hey Hunter! Diving into the Clash Royale universe, let's tackle this puzzle. From 109 total cards, picking the first deck of 8 has 109C8 ways (that’s a whopping 379,908,847,539 options - someone's been busy designing cards!). Once you've splashed the first 8 cards on the table, 101 shy cards are left. For a second deck without stealing any of the first deck's thunder, it's 101C8, aka 202,095,455,100.
Doing some Clash math: if we allow every card in either deck, there are 109C8 x 109C8 chances. That’s 379,908,847,539 x 379,908,847,539 (sounds like a number the Electro Wizard would zap).
But if we're looking for two completely unique decks, it's 109C8 x 101C8, which turns out to be 379,908,847,539 x 202,095,455,100.
Crunching those numbers, the odds of both decks being total strangers? 109C8 x 101C8 / (109C8 x 109C8). About 53.19%
Flip the script, and the odds of them sharing at least one card is 1 - 0.5319, which gives us a fun 46.81%
So not THAT rare. In fact, almost a half chance of at least one card repeating.
Cheers!
sickk, but what about the same one card repeating three times consecutively?
Its 8/109*8/109*8/109
This video is fun
No way hunter put 🤫 in the title
hope you charged your phone after this hunter 😥
I did don’t worry
there are 109 cards in the game, but due to only being allowed 1 champion per deck there are 105 possible cards you can have. in a random deck and for every shuffle you have a 8/105 of getting any card, so the odds of getting witch 3 times in three matched in a row are 512/1157625
that's 0.0442%
@@Starr_BeamI think you should count the champions as one card as you can't get more than one in a deck
@@loplaynstyle3641 ah you're right lemme re-run the numbers
That’s wild
@@loplaynstyle3641 That makes the calculation a bit more complicating but i'm gonna do it as simply as possible. Becuz we can only use 1 champion in a deck so the first slot, we can choose 1 of 109 cards, but the second slot only 105( cuz we already chose a champion and we cant use the other 4). The third slot is 104 and so on.
So the result will be: (109x105x104x103x102x101x100x99)^3 cuz shuffling deck 3 times. And then 1/the result, that's the percentage
nah the Battle Healer is actually midd tier . a worst card is something like Night Witch or Barb Hut .
Fantastic idea
Hunter for the love of god please play the poison directly on top of your tower
If you had just poisoned every GY freeze you would’ve won the last match.
Yes correct
day #2 of asking Hunter to play my main deck
Evo Mortar, Miner, Goblin gang, spear goblin, log, fireball, minion hoard, Cannon cart
Broooo!!! I was literally watching your videos for weeks thinking YOU were Ian😂. You both kinda sound the same
now that is a new level
Wait what😂
Day 2 asking Hunter to play skeleton only deck
Need a vid like this but toxic
W
8 cards in a deck, 109 cards total. Chance of getting witch in 3 decks in a row = (8/109)^3 = 0.000395357.... = 0.0395357....% = 0.04% (2 decimal places). This is the same chance as it is for you to select 25 people at random and them all having schizophrenia.
You should do a best of 15 or something against another cr UA-camr
great idea an hour long best of 73
Day 2 of asking hunter to play my x-bow mortar deck. ( X-Bow, Mortar, bowler, knight, nado, fireball, i-drag, e-wiz)
What's a best OR three??
typo lol
Cool video
Day 3 of asking the icebow god to make an ultimate icebow guide for the new meta
Isn't Prince a win condition though?
No😂
in middladder is .
Slay
How can ian got best cards???
I think hes just lucky
The best player gets the best card
@@hunter_cr no he's using champions and buff cards 😂
Fatherless has officiall father hunter now 😂
3 minutes
The odds of getting Witch 3 times in a row are 1/185.640625
Please correct me if I am wrong :)