@@harsh01draw graph of |x| and cos(x) ,their graph will intersect at 2 points.. one side in positive x axis and other side at negative x axis . So the sol is 2
And if u don't know about plotting of graph (suppose). Then |x|= Cosx And modulus will open with +&- sign Therefore x= + Cosx And x=-Cosx And hence there is two soln satisfying the eqn
Nahhh bro For some there can be two roots or maybe no roots we can't say that's why we use graphical approach and can only tell abt number of roots can't solve them 😅😊@@e-learningqueriessolver7078
One more important conclusion is that where graph of two functions intersect coordinates are equal .... It is simple observation but in pressure students can't even spot this...😅
First squaring on both sides then cos² x = 1- sin²x then send 1 the other side then from the interval of sin x put them in the equation you will get 0 and 1 so two solutions.
indeed this graphical method is super cool and easy but I thought it in another way please let me know if I'm right: |x|=cosx cosx > 0 cosx is positive only in 1st and 4th quadrant x = cosx where x belongs to 1st or 4th quadrant thus, for same x there will be two angles (value x) each in 1st and 4th qd So, 2 solutions
Bhaiya one doubt is: How to fill numerical in jee mains suppose 6 box hai or mera ans. 5 aya to vo 6 box me last box me 5 likhna hota hai ya 1st box plzzz reply ........
Solution smaj aane k baad question easy hi lagta hai. To kya brahma ji question bna kr bhjte hai. Or tune khud se solve Kiya tha??? Agar nhi to easy mat bol....😡😡😡🤬🤬🤬🤬
Yaar what i thought was ki jab 1 side se mod Hatate hain toh dusri side plus aur minus lagate hain jisse ki 2 solution niklenge toh 2 solution hue yeh sahi approach thi yaa glt?😂
![Balbir Yadav - [IITB]](http://yt3.ggpht.com/7tDuGXAo4raM3IMg_AF2OauslYNe_yVQpE1S5rMUd-VzCtWiBMNrfT5T97cCME5Q6X0-mdtSiw=s48-c-k-c0x00ffffff-no-rj)
![Tricks & Cheat Codes 🔥 Save time in JEE Mains & BITSAT [PCM] 👉 Shreyas Sir | Vedantu Enlite English](http://i.ytimg.com/vi/0nqUfRzAl2I/mqdefault.jpg)
![Tricks & Cheat Codes 🔥 Save time in JEE Mains & BITSAT [PCM] 👉 Shreyas Sir | Vedantu Enlite English](/img/tr.png)
Watch this problem #jee advanced
ua-cam.com/users/shortsWU9380nAdqw?feature=share
2
2
0
2
Bro took the most easy ques of jee mains😂😂
😂🫠
2 solutions simple graphical approach
how?
@@harsh01draw graph of |x| and cos(x) ,their graph will intersect at 2 points.. one side in positive x axis and other side at negative x axis . So the sol is 2
And if u don't know about plotting of graph (suppose).
Then |x|= Cosx
And modulus will open with +&- sign
Therefore x= + Cosx
And x=-Cosx
And hence there is two soln satisfying the eqn
Nahhh bro
For some there can be two roots or maybe no roots we can't say that's why we use graphical approach and can only tell abt number of roots can't solve them 😅😊@@e-learningqueriessolver7078
@@e-learningqueriessolver7078who doesn't know how to draw these basic graphs if they can't draw this how will they do area under the curve?
2, draw modulus and cosine function within the closed interval [-1,1] will give u two solutions
Make more videos like this, please
Bro took the easiest question to show off his skill😂
Tough questions bhi layenge 😂🫠🙂
But logo ko easy pasand hai. Tough kam log pasand krte hai.. 🫠
@@binary01-iitb yeah i know that mate
Afterall you are an iitian, obviously you would know better than me😂
One more important conclusion is that where graph of two functions intersect coordinates are equal .... It is simple observation but in pressure students can't even spot this...😅
Mod hatao + - lagao simple x=+ - cosx
No. Of solution=2
Nv style
|x| = -cos(x) ke nahi hote, even though aapke logic ke hisaab se hone chahiye
Good work bhaiya ❤
Mene kabhi bhi jee nahi diya but fir bhi me jee ke questions solve kar leta hu.
Great 👍
Saath main mains bhi laga na hota hai
jee mains
@@Ay_animeEditZrocked bro
@@Ay_animeEditZ😂😂😂right
To kya nachu
Graphing method will help it => ans is "2"
First squaring on both sides then cos² x = 1- sin²x then send 1 the other side then from the interval of sin x put them in the equation you will get 0 and 1 so two solutions.
Wrong I mean isme theek ans aagaya but squaring se roots gain hoskte h to original eqn me daalna padega finals ans
Nice bro ❤❤
Me 8th class student answering the question
indeed this graphical method is super cool and easy but I thought it in another way please let me know if I'm right: |x|=cosx
cosx > 0
cosx is positive only in 1st and 4th quadrant
x = cosx where x belongs to 1st or 4th quadrant
thus, for same x there will be two angles (value x) each in 1st and 4th qd
So, 2 solutions
Yeah
Without modules sign , x = ± cosx
Automatically 2 solutions
Correct
Amezing🎉😊
😮
Bro aisa ques schme ata ha kya like mera dekte hi hogya tha toh schme ata ha ye jee mains me?
I think Jo serious aspirant h use ye pata hoga
Agree 💯💯
Easy question brooo i am truee jee aspirant 2024❤
@@itz_anuj5861 Nice bro
Serious ka toh pata nahi par easy tha yeh
Ye to dekhte hi khatam hogya😂
Second q ka ans c hai 2
Just take x= cosx and x=-cosx=> x=cos(pi-x) number of solurion 2
Bro ,eise hi shorts banaiye ❤️👍
yess starting... soon
@@binary01-iitb hamara jee tomorrow ko hai
@@bajarang-dal All the best.
Juniors ko kaam aayegaa
Graphs are the best hacks for calculus and trigo
C is correct [ 1 -1 ]
2 simple make graph and find intersection
Square on both sides then 2 on the power of x
Bhaiya one doubt is:
How to fill numerical in jee mains suppose 6 box hai or mera ans. 5 aya to vo 6 box me last box me 5 likhna hota hai ya 1st box plzzz reply ........
Bhaiya pls keep uploading pyqs...
2 solutions simple graphicl approach
Graph comparison 2 solutions per jee me itna easy nahai ane vala😢
Solution smaj aane k baad question easy hi lagta hai. To kya brahma ji question bna kr bhjte hai. Or tune khud se solve Kiya tha??? Agar nhi to easy mat bol....😡😡😡🤬🤬🤬🤬
@@PrashantVats1234 ha mei kud solve Kiya 😐 bakne ke pehle Jan na hei bro aur jee ka saval is se bhi tough Ane wala😭
|x|=cosx therefore x=±cosx simple
❤❤❤
Cos x axis is 0 because it is present in center graphical
2 easy easy draw curve 😊
In place of that qution , polynomials are present
Then how to find sir ,
I though that to find roots . Roots solutions right sir
Graphically 😊
no. of soln. 2, by compare it's Range. only one 0 and 1
What? Ye 0 aur 1 kya bola aapne?
Uske soln
X = +cosx and - cosx
Very easy
2 modules break in 2 ways -ve and +ve
Ye kb poochha gya😂😂
B
Please koncham slow ga cheppande
its easy, just grapichs
Boowwwwww very butiful very dangarous quesion I yam scar
😂
|x|= + if x>0
|X|=. - if x
2 solution by graphical approach
itne easy svaal kb aaye
What’s the trick in these isn’t this the basic approach of doing this type of questions ?..
Please tell me kl mera jee mains ka paper h mai ky kru maine kuch nhi padha h
Kuch toh padha hoga 😢, Agar NCERT bhi acche se aata hai and calmly paper attempt kiya toh you can score 90 percentile easily.
Best of luck 👍
Yaar what i thought was ki jab 1 side se mod Hatate hain toh dusri side plus aur minus lagate hain jisse ki 2 solution niklenge toh 2 solution hue yeh sahi approach thi yaa glt?😂
Yes 2 solution .
What a simple question 😂
bro mera kal paper h but. mujhe formula learn karne ke baad bhi question karte time yaad nahi aata ...plz give me some tips
Last moment pr toh ek baar formulas revise kr lo 2-3 baar
Okk thanks
kaisa gaya bro
@@kashyaptandel5212 thik tha
Me in 9th : and solved jee mains question by prasant sir tuka trick🗿🌑
How?
Howw?
None ....because I'm a commerce student 😂
Ye to 10th class wala bacha bhi krlega 💀💀😂
Bhai phele graph pata hona chaiye tabhi kr payega na by the way question is simple 😂
@@sumanchetry986 baat to sahi hai 🤣
2 simple graph laga dala life jigalala 😂😂😂
Mod hatakar bhi to kar sakte hai
1❤
Question is more interesting if |x| = 10|cosx|😅
Cos x range = [0,1] , |x|≤1 so 2 solution
Wrong logic, Check your concepts
Bhayya but question me x ki range bhi di hui honi chahiye thi 😢😢😢😢😢😢
Agar range nahi diya Hota hai toh range all real numbers assume krte haj
B/c
Is it really JEE Main question?
Wo bhi maths me 😅
2 solutions
What pure questions maths( 2024)Mai statistic Ke the kya😅😅
Bro in Maine we don't get like that of questions right, I rare cases it will be given.
You might not get direct question. You should have idea about graphical method. It helps indirectly many times
@@binary01-iitb yeah after watching this vid I started understanding the graphs ( I used to neglect them 💀)
C by graph
The answer is 2
Yeh jee mains ka question h😂😂 I solved this question in a fraction of sec I am in class 11
Next question 2 soln
2
Mod hatakar cox-x and cox x ke value same home , 2 solution
Wrong logic
Agar yeh meri shift me aata toh me pakka clear kardeta
Bhai boards toh ho Gaye😂
Ye PYQ hain kya?
Itna ashan puche to maja hi aa jaye
😂😂
Bro this is not hack this 8s a concept ❤😂
Bro if we open the modulus
We will get x =+-cosx
Cosx + and - ko kha jata h to x = cosx ho jayega
Iska matlab one solution
No,
Check your concepts.
Graph ki jarurat bhi nhi hai bhai ye aise hi solve hojayegi Mod hatao toh [-1,1] yahi do solution aayega .no of solutions 2
Are you sure??
@@binary01-iitb 10000000% sure brother concept galat ho hi nahi sakti
Centre fruit
Sir 2
How is this a jee question. Its easy
2 solution
Solution 2
Are bhaiya waise |x| open hoga to ±cosx ho sakta hai kya ?? Just I want to confirm
2 ye nursery ka hai
1
dout clear !!!
K I'm failing jee 😭
2 soon avg jee aspirant can do that
Ye ese bhi ho sakta he kya
|X|=cosx
+X=COSX
-X=cosx
So no
. Of solutions is 2
Not a right approach to solve these types of problems
1...
2 is solution of this question
2 solution bro
2 sol^n
A
mene to + or - khol ke pta kar duya tha 😂😂
Esaaa nhii hota hai brooo
Bhai Bina grap ke x ki value +cosx and -cosx aa jati
No, It's not the right approach to solve these kind of problems.
@@binary01-iitb okay bhai thanks 😊