WMA14 01 IAL (Edexcel) P4 Oct 2021 Q5 Parametric Equations, Differentiation, Cartesian Conversion
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- Опубліковано 28 вер 2024
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i have trouble understanding the connection between the y and t graph and the x and t graph...are they the same? are they different? how are they exactly connected?
in part c isnt the first point beyond the origin in the positive x axis?
even though it says -pi/3
That's the value of t not x if you worked out x from x = 5 + 2tan(t) you would get the positive x value
sir I have taken my dy/dx= 8tant to find the minimum where I took t= pi/4 to get 8. is this another way to solve it or did I get lucky?
2:11 can we do the same thing for (sin(x))^2 ???
Yes ... we will then get 2 sin(x) cos(x) which can be expressed as sin(2x)
why is it not between 16 and 32 but rather 8 and 32 i dont understand. we substituted π/4 into y to find the minimum point no?
16 is the value for the other restriction on the right hand side of the graph (that point where it stops) thats not really my range as am not taking the bottom of the curve.
@@acid7347 But shouldn't the range of y is above and equal to 16?
@@fardinzahinfaruquefzf9323 the points he mentioned at 10:12 -pi/3 gave him the point at the top of the graph 32 and pi/4 gave him 16 which is the lower point at the end of the graph therefore if you say 16 to 32 you are neglecting the bottom of the curve hence the correct answer must be 8 to 32 the range of all values of this graph. hope this helps