the line you have assumed to be the y-t+1=0 line is actually y-t-2=0 that's where you got stuck. That aside a great lecture Mr Strang. You made me fall in love with math. Greetings from India. God bless you.
I think there is an error in 9:20, y(t) should be 1/(1-Ce^(-t)) rather than 1/(1+Ce^(-t)). I have used both old fashions integral and integration factor that professor Strang has taught, both answers are 1/(1-Ce^(-t)).
Long life Professor Gilbert Strang. I hope you understand that the college and education at a terrible place is also terrible. Our physic professor here does not know vector component, and they even put it in the exam. People are either failing and end up homeless or cheating in the exam to transfer. If you are not that "race", you need to face racism issue by those professors. Years by Years, failing and failing. I am an East Los Angeles College student here. Thus, I really thank Gilbert Strang teaches Differential Equations so deeply and explains the heart concept. This is a gift for the poor people and minority living like a jewish in the United States.
Yes, solve them and the solution (as long as you don't have any initial conditions) will be a family of curves, you can see their behavior by plotting them as you would a first order one, I believe.
the line you have assumed to be the y-t+1=0 line is actually y-t-2=0 that's where you got stuck. That aside a great lecture Mr Strang. You made me fall in love with math. Greetings from India. God bless you.
It's great explanation. Sir 1+t -y =-1 is not on right of y=t it is on left side of it . Thank you.
Thank you, prof. Gilbert Strang
whooop.. I wasn't expecting that. Professor Gilbert Strong said. He was humerous
I think there is an error in 9:20, y(t) should be 1/(1-Ce^(-t)) rather than 1/(1+Ce^(-t)). I have used both old fashions integral and integration factor that professor Strang has taught, both answers are 1/(1-Ce^(-t)).
It's just an integration constant. You can take your solution, define a new constant D=-C and end up with the solution in the video.
We use this for numerical de solutions?
Long life Professor Gilbert Strang. I hope you understand that the college and education at a terrible place is also terrible. Our physic professor here does not know vector component, and they even put it in the exam. People are either failing and end up homeless or cheating in the exam to transfer. If you are not that "race", you need to face racism issue by those professors. Years by Years, failing and failing. I am an East Los Angeles College student here.
Thus, I really thank Gilbert Strang teaches Differential Equations so deeply and explains the heart concept. This is a gift for the poor people and minority living like a jewish in the United States.
at 18.00 the 3rd line is wrongly described
Assuming these pictures are correct, they are helpful in understanding the concepts.
There is a way to see the behavior of solutions using second order?
Yes, solve them and the solution (as long as you don't have any initial conditions) will be a family of curves, you can see their behavior by plotting them as you would a first order one, I believe.
the line he was referring to was f(t,y)=2, not f(t,y)=-1.
ok