I think he is confused between k and K, k is the number of bits shifted into the encoder at one time. Generally, k = 1 . n is the number of encoder output bits corresponding to information bits. The code-rate, Rc = k/n . The encoder memory, a shift register of size K , is the constraint length.
What is m? and how does output depend on (m-1) digits?. If m is the total number of bits in the shift register then the definition would be true but only for this specific case. So is m and K the same thing?. Please provide proper and dont just copy the definition from elsewhere. Its confusing.
aapne yeh toh bataya hi nahi ki x2 mien m0 and m2 kyon ja raha hai ...bas aapne simple likh diya jaise books mien hai..but uske peeche ka logic naih daala hai ..woh bhi bataiye...
I think he is confused between k and K,
k is the number of bits shifted into the encoder at one time. Generally, k = 1 . n is the number of encoder output bits corresponding to information bits. The code-rate, Rc = k/n . The encoder memory, a shift register of size K , is the constraint length.
Superb sir.....ur videos r simple and easy understanding....thank u
Sir kal exam h 😊
Ha bhaii Kal mere bhaii exam hai
Great.. I have cleared. Hope you too
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@@ShahidOfficial1 thanks brother
Thank you sir
Sir... explanation sahi nhi h...samaj hi nhi aa rha kehna kya chahte ho...but anyway for your hardwork Thank you ❤️🙏
Kal exam hai😭
Super explanation...
Explained very well
thanks sir this was really required
Itc kii full syllabus video hh
What is m? and how does output depend on (m-1) digits?. If m is the total number of bits in the shift register then the definition would be true but only for this specific case. So is m and K the same thing?. Please provide proper and dont just copy the definition from elsewhere. Its confusing.
aapne yeh toh bataya hi nahi ki x2 mien m0 and m2 kyon ja raha hai ...bas aapne simple likh diya jaise books mien hai..but uske peeche ka logic naih daala hai ..woh bhi bataiye...
bhai jesa pdha rhe h likh dio bs marks se mtlb rkho :P
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