Volt Drop Part 3

Поділитися
Вставка
  • Опубліковано 29 бер 2020

КОМЕНТАРІ • 27

  • @jasonh8542
    @jasonh8542 Рік тому

    I've been away from home for a few days and instead of wasting my time watching garbage TV, I dedicated hours and hours of watching just Schulerruler videos. Schuler will give the Question to work out than I would pause each one to work it out on my own than unpause to see how I did. The more I watch your content, the more I see myself improving and becoming more confident. Thank you once again. Look forward to seeing more videos for the CEC 2021 25th edition.

  • @davemembrere2160
    @davemembrere2160 Рік тому

    Thank you, this is helping a lot!

  • @roryfitzsimmons8773
    @roryfitzsimmons8773 3 роки тому

    Thanks for the videos Chris! They really help!!!

    • @schulerruler
      @schulerruler  3 роки тому

      Glad to hear that! Thanks for watching!

  • @manuelcuellar1738
    @manuelcuellar1738 3 роки тому

    You are the best!!!! Thanks for your help with these videos

  • @Al-wu8is
    @Al-wu8is 2 роки тому

    Thanks a lot.

  • @abelz7273
    @abelz7273 2 роки тому +1

    awesome video, very well explained. thank you

    • @schulerruler
      @schulerruler  2 роки тому

      Thanks for watching!

    • @abelz7273
      @abelz7273 2 роки тому

      @@schulerruler im a bit confused, what does the 10.29 m represent? since you have the 152 m from the beginning.

  • @kylesmith5970
    @kylesmith5970 3 роки тому +2

    this is an amazing video though I'm looking for more information on the feeder side of things. I was curious how you would go about calculating say 300 meter run, with 400 amp service. I was wondering if you had an videos explaining that side fo things. As the values are not in D3. I know it says there is a relationship with in the chart but still don't no how to calculate the answer I was looking for. Thanks a lot love your videos

    • @alhassanabuyousef2005
      @alhassanabuyousef2005 2 роки тому

      Hi, I have the same question here... what if we have a load that is greater than 320 Amp, and what formulas regulating the voltage drop in this case... thanks in advance much appreciated

  • @taghvaee
    @taghvaee 2 роки тому

    Perfect

  • @leandrofreitas9287
    @leandrofreitas9287 2 місяці тому

    Thanks!

    • @schulerruler
      @schulerruler  2 місяці тому

      Thank you! Hopefully it was helpful! I will be updating these sometime soon to reflect the new method in the 2024!

    • @leandrofreitas9287
      @leandrofreitas9287 2 місяці тому

      You are very welcome. It's just a token to show how much I appreciate your work, which has been of great value to me. I am in the process of preparing for the C of Q and your videos are helping me to refresh topics I have learned throughout trade school. I wish more people take the initiative to show generosity towards you as you have shown towards us with your time. Thank you, and may your work bring you prosperity and happiness.

  • @kamalshabani4007
    @kamalshabani4007 2 роки тому

    why you do not use D.F.C for calculating the first D3 value(10.133m) because I think if calculate the D3 value with D.F.C the new answer would become bigger and conductor #4 would not work? thanks so much

  • @larryteslaspacexboringlawr739
    @larryteslaspacexboringlawr739 4 роки тому

    first human to make comment, thank you for video about electricity

  • @syarkawihananrambe3587
    @syarkawihananrambe3587 4 роки тому

    May you explain to me about vector transformers DY0Y6 ?

  • @briannepark1555
    @briannepark1555 3 роки тому

    120v 7amp load 450m away what size conductor ?

  • @moesadr3342
    @moesadr3342 11 місяців тому

    Would anyone be able to recommend a video for 3-phase systems and CEC (Canadian Electrical Code) , please?

  • @ROBEL-TS
    @ROBEL-TS Рік тому

    Thank you
    What about vd for aluminum wire please

    • @schulerruler
      @schulerruler  11 місяців тому

      Same calculations as copper, just bump up two awg sizes.

  • @caseyscott6755
    @caseyscott6755 3 роки тому

    When does the 3 Phase come into play with Voltage drop?? as I have seen (2/R3) included in the formula.

    • @schulerruler
      @schulerruler  3 роки тому

      Three phase allows for an increase in distance of 1.155.

    • @caseyscott6755
      @caseyscott6755 3 роки тому

      @@schulerruler so would that change the outcome of the answer to the above video as its 3 Phase ?

    • @schulerruler
      @schulerruler  3 роки тому +1

      @@caseyscott6755 in this example, it is still a single phase load (line 1 and line 2). We apply the 1.155 of it is a three phase load. As table D3 is based off of two wires, we do not apply in this example.