... and fours and sixes can be ruled out of the circles for almost same reason as fives --- each are a knights move away from two (or more) that see each other (=same box/column/line) so cannot be done.
I got in only 1.3x Sleuth time so I am happy. After getting the 9s in I coloured everything including grey/red and grey/blue. Then I stared at it for a long time thinking how is this enough information to get all the numbers in. Great puzzle and Video Sleuth.
I too thought that there wasn't enough info to solve the puzzle. I kept rereading the rules thinking that I must have missed one. I got there eventually. Terrific puzzle and solve
I love a puzzle that looks so far beyond what I can do but then unlocks through simple logic (colouring for me). Took me long enough but I didn’t get stuck. Fun times!
Wow what a puzzle! I had a different break-in. I knew it had to be near-extreme digits in the circles, and since I started the puzzle well over an hour ago (solve time 78:45), I don't exactly remember how I eliminated 8 as the large digit, but once 9 was determined, 3 was quickly eliminated because it would have broken box 1. Then I went on a goodliffing adventure, found the 5's and most of the 7's until I got stuck disambiguating the 1,2 circles. It was your clever deduction at 25:58 that unstuck me! It's the mark of a great puzzle in my book when I persist for over an hour without giving up in frustration
19:53 for me. I enjoyed this one. After I finished colouring, somehow the most time-consuming part of this puzzle was the sudoku on pairs. Scanning is hard...😢🤣
21:58 for me. Funny thing you said in beginning no possible boxes, rows or columns where to place 5 but your mouse was located in box 6 really close to that 5 what is forced to place. Very interesting was that ou said in some point you dont see enough restrictions to solve sudoku and same time i was like looking for final break in for low digits :D.
18:42 How I solved it: we have 5 ways do to 12: 129, 138, 147, 237, 246 We can't have either 4 or 6 because Knight's move are in the same box/row/column 129, 138, 237 We can't have a 237 because some circles are a Knight's move apart and we only have 2 twos for at least 3 sevens. 129,138 The middle circle can't be a low digit because we will need to place a 8 or a 9 in the R3C6 and boxes 3 and 8 couldn't have the high digit. Then after placing 89 in the middle, I could see that, because of the Knight's move we can't use 3 at all. So it is 129!! After that I coloured all the Knight's move cells related to 9 and all the other ones (2 colours here). I found some 5s and saw that either box 1 or 3 can have the 1. So in box 9 we have a 2 in the circle. Sudoku to finish. I like the way you coloured a lot of cells first and then tought about the logic. Very smart from you! 🧐 Thanks! 😀
Oh, he missed the 5 in box 6 with his first shading, and then forgot that the circles indicate how many times in a circle rule. That automatically puts 9 in all the pink/purple circles. It was easy to rule out 3 in the green circles after that.
took me 42:39 solver 379, i was slow with the low digits in the end! Even though i was so far "ahead" in the beginning of your solve! Fantastic puzzle!
Why couldnt the blue circles be 3???? And the combo be 93 rather than 912? I havent solved it today since i know i wont have time.. But stuck on that portion of uour solve trying to figure out why?
Sometimes watching another person solve a puzzle reveals a mistake in my own solve. When I saw you listing out all the possible options, you went for 3- and 4-digit suns to 12, but didn't consider a 2-digit sum, 39, which at least theoretically could have worked. Then I thought about how I figured out the digits, and realized that I hadn't considered that either. Fortunately, this is a lucky mistake, since making the green cells 3 would have placed 89 pairs in some places that would already see another 9, breaking the puzzle. I took a different approach to figuring out the 12 sum, looking specifically at the circles that see one another. I found one pair and two trios, which meant that I must have both low and high digits in the circles. But I couldn't have more than one high digit, because 6+7 is already greater than 12. Then I started working my way up through the high digits, looking to eliminate possibilities. Having 6 would mean a minimum of of three circles would need to be a 1, so that's out. A 7 would give a little more freedom, but it would still be limited to 1 and 2 as links, and 7+1+2 is less than 12, so that's out. That left (as I imagined it) either 831 or 921. Only after doing the coloring and finding that there were just three digits in one of the shades did I eliminate 831. And from there, my solve followed a similar path to yours. My time today was 25:55, solver number 308.
@@SudokuSleuthI thought it was odd that you neglected 9/3 as an option too but very quickly 3 wouldn’t work as it had to be a knights move from only 8 and 9
Oh dear Sleuth! There was only one spot for a 5 in box 6 when you first shaded! but the purple/green was very helpful! Thanks :)
I don’t know I missed it first time round!
If I improve my Sudoku scanning, my game would improve to no end!
I think your green/purple shading helped heaps more anyway 😊
... and fours and sixes can be ruled out of the circles for almost same reason as fives --- each are a knights move away from two (or more) that see each other (=same box/column/line) so cannot be done.
Although it’s trivial, you should also rule out 3s in the remaining circles after placing the 9s.
Good shout
I got in only 1.3x Sleuth time so I am happy. After getting the 9s in I coloured everything including grey/red and grey/blue. Then I stared at it for a long time thinking how is this enough information to get all the numbers in. Great puzzle and Video Sleuth.
😃
I think I questioned the limited info to solve like 5 times in that video
I too thought that there wasn't enough info to solve the puzzle. I kept rereading the rules thinking that I must have missed one. I got there eventually. Terrific puzzle and solve
I love a puzzle that looks so far beyond what I can do but then unlocks through simple logic (colouring for me). Took me long enough but I didn’t get stuck. Fun times!
Nicely done!
29:25 ... I found this incredibly satisfying to solve because it was such a challenge for me.
Wow what a puzzle! I had a different break-in. I knew it had to be near-extreme digits in the circles, and since I started the puzzle well over an hour ago (solve time 78:45), I don't exactly remember how
I eliminated 8 as the large digit, but once 9 was determined, 3 was quickly eliminated because it would have broken box 1. Then I went on a goodliffing adventure, found the 5's and most of the 7's until I got stuck disambiguating the 1,2 circles. It was your clever deduction at 25:58 that unstuck me! It's the mark of a great puzzle in my book when I persist for over an hour without giving up in frustration
very clever - the setting AND the solve 👏👏👏. I appreciated a little nudge a couple of times!
Glad you enjoyed it!
36:19 for me. Very clever setting! 😄
What a puzzle! Absolutely stunning setting.
We agree!
19:53 for me. I enjoyed this one. After I finished colouring, somehow the most time-consuming part of this puzzle was the sudoku on pairs. Scanning is hard...😢🤣
I’m 100% with you!
I see that Jolly Rogers has published Counting on Quiet Knights (#2) on LMD 🙂
21:58 for me. Funny thing you said in beginning no possible boxes, rows or columns where to place 5 but your mouse was located in box 6 really close to that 5 what is forced to place. Very interesting was that ou said in some point you dont see enough restrictions to solve sudoku and same time i was like looking for final break in for low digits :D.
😂
I needed a little help on this one.
Great puzzle though.
Glad I could help!
18:42
How I solved it: we have 5 ways do to 12: 129, 138, 147, 237, 246
We can't have either 4 or 6 because Knight's move are in the same box/row/column
129, 138, 237
We can't have a 237 because some circles are a Knight's move apart and we only have 2 twos for at least 3 sevens.
129,138
The middle circle can't be a low digit because we will need to place a 8 or a 9 in the R3C6 and boxes 3 and 8 couldn't have the high digit.
Then after placing 89 in the middle, I could see that, because of the Knight's move we can't use 3 at all. So it is 129!!
After that I coloured all the Knight's move cells related to 9 and all the other ones (2 colours here). I found some 5s and saw that either box 1 or 3 can have the 1. So in box 9 we have a 2 in the circle. Sudoku to finish.
I like the way you coloured a lot of cells first and then tought about the logic. Very smart from you! 🧐
Thanks! 😀
Nicely done!
Oh, he missed the 5 in box 6 with his first shading, and then forgot that the circles indicate how many times in a circle rule. That automatically puts 9 in all the pink/purple circles. It was easy to rule out 3 in the green circles after that.
Indeed
@SudokuSleuth your first shading helped me so much with the 5's, and those helped so much with the second shading. Thanks for this!
Glad you’ve found helpful!
@36:15 you say one of these is a 6 but why isn't row 2 a possible 6?
Sorry, can you confirm the time again?
36 is the end of the video!
@24:30 you're wondering where the 2 and 1 are and obviously don't see the 6 in box 6 that is staring at the circle you highlighted 😅
😉
took me 42:39 solver 379, i was slow with the low digits in the end! Even though i was so far "ahead" in the beginning of your solve! Fantastic puzzle!
Brilliant solve Sleuth 👋👋 Amazing puzzle that was beyond my capabilities. Happy weekend to everyone!
Happy weekend Jon!
Why couldnt the blue circles be 3???? And the combo be 93 rather than 912?
I havent solved it today since i know i wont have time..
But stuck on that portion of uour solve trying to figure out why?
That is what I tried first and you run into conflicts quickly but I needed to try it to see it did not work.
You can use row 1 to eliminate 3. There be no where you can have 6 or 7
Sometimes watching another person solve a puzzle reveals a mistake in my own solve. When I saw you listing out all the possible options, you went for 3- and 4-digit suns to 12, but didn't consider a 2-digit sum, 39, which at least theoretically could have worked. Then I thought about how I figured out the digits, and realized that I hadn't considered that either. Fortunately, this is a lucky mistake, since making the green cells 3 would have placed 89 pairs in some places that would already see another 9, breaking the puzzle.
I took a different approach to figuring out the 12 sum, looking specifically at the circles that see one another. I found one pair and two trios, which meant that I must have both low and high digits in the circles. But I couldn't have more than one high digit, because 6+7 is already greater than 12. Then I started working my way up through the high digits, looking to eliminate possibilities. Having 6 would mean a minimum of of three circles would need to be a 1, so that's out. A 7 would give a little more freedom, but it would still be limited to 1 and 2 as links, and 7+1+2 is less than 12, so that's out. That left (as I imagined it) either 831 or 921. Only after doing the coloring and finding that there were just three digits in one of the shades did I eliminate 831. And from there, my solve followed a similar path to yours.
My time today was 25:55, solver number 308.
Good point.
Row 1 still helps eliminate the 3 very quickly!
@@SudokuSleuthI thought it was odd that you neglected 9/3 as an option too but very quickly 3 wouldn’t work as it had to be a knights move from only 8 and 9