Simple Supported Beam With UDL(Problem-1)(हिन्दी)

[@jaskamboj11]

Very nice sir pehli baar smjh aya ye thank you sir🎉🎉🎉

[@LEARNANDGROW]

Glad to help you

[@sakshimishra7114]

Fantastic sir apki vedio 100%shu hoti h..... dhnybad

[@LEARNANDGROW]

Glad to help you

[@Techmulla146]

Great explanation. After searching lot of videos. Got a golden one. Thank you so much❤.

[@LEARNANDGROW]

Thanks for your words

[@ananthakrishnanm5684]

Thank you ji🙏🏻

[@LEARNANDGROW]

Welcome

[@arghagan.6565]

love you sir

[@LEARNANDGROW]

Thanks for your words

[@sourav0327]

Love you sir you are great 🤞🤞🤞

[@LEARNANDGROW]

Thanks for your words

[@arghagan.6565]

thanks a lot sir

[@LEARNANDGROW]

Glad to help you

[@anilkumarhm1175]

Thanks sir this videos made more useful got practical knowledge thanks sir make more videos related practical executed loads on building

[@LEARNANDGROW]

Thanks for your words and glad to help you

[@Pankajkumar-ot7su]

Jab ek support hinge hota h aur dusra roller to bhi aise hi krte h lekin isme dono hinged support h kya isko bhi aise hi kr skte h

[@erhimanshupal2038]

Thanks sir g your method is good

[@LEARNANDGROW]

Thanks for your words

[@Cyrus6545]

Can you make a video for
Simply supported beam of length 4 metre carrying point load of 10KN at mid point and carrying UDL of 5KN/metre over full length

[@manishamathpati317]

Nice sir easy che samjaya

[@LEARNANDGROW]

Thanks

[@cric8097]

Fantastic explain sir..
I was studying before 3 year lern and grow 🤗🤗🤗

[@LEARNANDGROW]

Thanks for your words and support. glad to help you

[@bhupendrakhatti1085]

Bhut bdiya bhai

[@LEARNANDGROW]

Thanks

[@piyushraikwar744]

Thquuu so much bro 🙏

[@LEARNANDGROW]

Glad to help you

[@Er.shivamyadav8732]

Thank u bhai

[@LEARNANDGROW]

Glad to help you

[@furqannazir8160]

Thank you ❤🙏

[@LEARNANDGROW]

Glad to help you

[@sarojsahu6703]

Sir please make a video on sfd and bmd on overhanging beam..

[@BhanuPrakash-uo2vp]

Bending moment center is 18

[@technicalprotips9529]

Nicely Explained👍

[@LEARNANDGROW]

Thanks

[@arghyaghosh7781]

Bhai BMD me aise hi curve bann.jaega?slope kaha pe 0 ho rha hai us hisaab se curve banega to.

[@manas8730]

Moment = length×force to jahirsi baat he length jahnape 0 hogaga uhnape BMD 0 hoga kunki 0 se kisiko bhi multiple karnepar 0 hotahe

[@yuvarajvishalmaurya1762]

Wo BMD ka curve wrong bana hai .BMD ka curve 1/x^2 ki tarah banega

[@baapkomatsikha3887]

Thanks bhai

[@LEARNANDGROW]

Glad to help you

[@salmane7653]

Well teaching sir

[@LEARNANDGROW]

Glad to help you

[@thesoulmateallin1241]

Sir yehan bending moment at c point pe jo last me 3/2...then at A point pe 6/2 ye q kia ja rha hai mtlb thora samj ni aa rha

[@prankrishnamandal9779]

Awaz acha hai

[@amekatozhimomi8814]

One question,you only take 6KN for A right (when there is a udl and RB)but take all the forces when calculating B left.why ??

[@souvikg347]

Same question bro , did you get the answer then plz tell me bro

[@banner_hulk]

@@souvikg347 he didn't mention the whole process, Actually, we divide the section as two region, 1st from A to middle, and middle to B. Then firstly, only in region A to middle we apply the equation of SF and then secondly from we apply the formula from point A to region between middle and B. (Consider once watching how to calculate SF in general)

[@samjhanaaryal3366]

Sir how to take c right

[@sanishalikram6186]

Thanks sir

[@LEARNANDGROW]

Glad to help you

[@abhayverma3090]

Thanks

[@LEARNANDGROW]

Glad to help you

[@sijanpokhrel9560]

Nice to you but mind your teaching

[@souvikg347]

Sir A right ka value minus 6 kiyu nehi aya ?

[@yaduvanshiak7379]

Nice

[@LEARNANDGROW]

Thanks

[@khageswarnahak8296]

Kya Sir paper khatam ho raha hai kya
Nice explain tha

[@engineermanas2864]

Sir please please please make a video on types of gasification processes... Like Lurgi gasification and kopper totzek gasification...

[@Pankajkumar-ot7su]

Sir ye to indeterminate beam h simple method se kaise solve kr diya apne

[@tapassahoo6300]

🎉🎉🎉🎉

[@LEARNANDGROW]

Thanks

[@rivengpradhan1436]

U did not use -ve sign while considering from ri8 to lef8 in bm

[@roshansharma9533]

in the ( Ma )we have the values Ma= 6×6-2×6×6=0
Then where is the -2????

[@mr.varshney3331]

Is support mein to two side se reaction lagti hain...

[@divianksarmal3700]

I think the shear force diagram is wrong, it should be more like two rectangles up and down, not a triangle. Maybe i'm wrong, please let me know what i'm missing here.
thankyou

[@polytechniceducation5458]

In case of udl, shear force will make Triangle because force is acting per unit length, find the force F = w/l ×l

[@kumarritikroushan012]

U r right bro

[@UAKhan-yw8vq]

It is possible when simply supported beam is having a concentrated load

[@nickboost854]

Sir please eni topic mese video banavo na boy's law .charls law etc plz sir

[@nabamtagi21]

Applause

[@LEARNANDGROW]

Thanks for your words

[@sanishalikram6186]

Horizontal beam lo na yaar

[@anmolrattansetia6234]

i have a load of 19.2 kg and the area is 580x 290 mm. How to calculate the load in Kg/m?