Probability tree diagrams (without replacement) | Higher GCSE | JaggersMaths
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- Опубліковано 4 жов 2024
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How to complete and calculate probabilities from tree diagrams where the counter (etc...) has not been replaced before the second pick.
I was completely clueless about tree diagrams but now I understand it really well. Thank you so much
From the bottom of my heart.. THANKS FOR THIS DIVINE LECTURE..
Love and respect from MAURITIUS 🙏❤️
I thank God I have found your video. . .Great explanation!! You cleared my blurry understanding and made it like crystal clear . . . Good job!
The last question was a tough question but you are a life saver thanks for your help😀
Hello
Thankyou so much, you're a life saver!
Finished a probability test, wasn’t sure on how to do this, came here to make sure I was right
This really helped me a lot thanks so much!
Thanks for the video
I've learned a lot 😊
Thank you so much that was amazing 🤩
Thank you ❤️❤️
Thanks
hey on the last question shouldn't u include P(BW) since you have included P(WB)? Also thank you this video helped me loaaaaads
The last question is asking about an outcome of more black counters than white counters in bag c. Since there is currently an even amount of each this will happen if a black is picked out of bag B and placed into bag C. So it doesn’t matter what colour counter is picked out of bag a but it must be a black from bag b. Hence black black or white black.
Now, what would happen if mrs gold selects 3 children? Would there be 3 branches then?
Hey why do we still multiply if the two events are dependant, I was under the impression we only use P(A and B) = P(A)xP(B) if it is independent events?
Hey I wanted to ask that do we have to further simply our final probability answer or just write as it is
Great question! Unless it says “give your answer in its simplest form”, then no you don’t have to. You can just leave it as it is.
@@Bright-Maths oh ok thanks a lot for this aswell as for the video.It was truly helpful :)
Hi, I like the way you explain.
I only have one question, if Sarah takes a sweet random and eats it the number of sweets goes down to 9, after that Sarah takes another sweet random without replacement, this it means that she took 2 sweets right?. If it's so why the number goes down to 9 and no to 8? and why the number of sweets goes down to one and not to 2?
Hi. The situation you are describing it correct if she was going to pick another sweet. On the first pick, the bag has all ten sweets (denominator 10). On the second pick there are 9 sweets in the bag (denominator 9). This situation is only asking about her picking 2. If she were to pick another then there are 8 left in the bag so the denominator would be 8.
On the last one why don't you include P(BW)
Sihlangule Nkathazo
The question is asking about the outcome that bag C ends up with more black counters than white counters. Since there is currently 5 white and 5 black, a black counter must be moved from bag B to bag C in order to achieve this.
P(B,W) would result in more white counters than black in bag C.
Hi thank u for the video very much appreciated. I’m just confused on last one. It says probability there are now more black counters than white counters so u should pick the one that makes 28/110 why the B and B one?
We need to work out both option where a black counter is placed from bag b into bag c. That is how we will end up with more black than white counters in bag C.
So there are two options for this. Either black from a to b then black from b to c. Or white from a to b but black from b to c. Which are the two options you see in the video. Hope that helps!
Where are the other people in Ms Matthews’s class
Math
You messed up on the second on he takes two socks without replacement u wrote it as if he took one
Taking two socks at the same time is the same thing as taking one sock, not replacing it and then taking a second.
it says he take two socks at random
so why do you always take away one
chiemezue nwamba
Taking two socks at the same time is the same think as taking one sock out, not putting it back in the draw and then taking a second sock out.
Thing*