@@MlungisiNkosi Sir in 21:32......the question says we should calculate the final velocity of the ball 10m below the roof....shouldnt we use ∆y=30m - 10m = 20m ?
Matrics of 2022 are really benefitting from these videos. Sir explains so clearly that even a 5 year old can understand what he's saying. Actually feeling guilty I don't have to pay for these lessons.... top quality stuff
I wrote physics today and I watched almost all your videos, it really helped! I hardly understood physics as much as i do right now. Thank you for the brilliant knowledge you share with others!! You're blessed! 🙏👏🏻
Thank you so much sir your videos helped me a lot 🎉I was able to obtain good marks for matric and pursue a career in medical science in anatomy and they are still very useful even now .Thank you so much
Sir you are honestly God sent, you've helped me so much and i appreciate the time and patience you provided in helping us achieve academic excellence . ❤
Thank you Sir you really helped me understand this chapter . God bless you 💗at first I was lazy to watch your videos because they long 😂 but now I understand why they are long. They have so much info and they are helpful ❤😂 thank you again Malume you are a star ✨
Thank you so much Sir. I had no idea with what was happening with this topic but now I understand everything. Thanks again and we appreciate your efforts 🙏🏾
Thank you so much! The video is very informative because wow both my teachers (extra class and school) taught me vertical projectile motion and I still didn't get it until I watched this video, THANK YOU:)
@@MlungisiNkosi my apologies I think it’s 1:04:33 (I’m confused as to why you used 1.5 instead of 3 seconds when we calculated the time to be 1.5 x 2 = 3🤔🤔)
@@dr_logical_b3a5t63 3s is the time for the ball to return to its original position but in the second question about max height, hence we used half of the time which is 1.5s
Hi For question b What if I first calculated the time between A and B,coz we know that the time AB is the same time as BC...then after I can calculate the time between CD then I add them together
at 28:52 nna i found vinal velocity first then found the distance that way.there were alot of steps involved in your workings. does that mean that a candidate that used your method would get credited more than i would?😭
Hi, sir. For the 2nd question, why do we use the 30m as it is? Wouldn't that imply that the ball was dropped rather than thrown? Meaning that we have to use the max distance
Sir regarding Thembi(question 2), why didn't you include the 5.1m when calculating the time? From my understanding, we start counting from when it was thrown, to the maximum height then to when the ball touched the ground. Please correct me if I'm wrong.
Awesome question... Please remember that the total displacement is taken in straight line from beginning to the end point. The displacement from beginning to the maximum height and from maximum height back to the same position is zero. Thus the total dissplacement to the ground will exclude the 5.1m value. I hope that makes sense
@@zuheylahime1203 Nope i saw it on Facebook page may/june group...we're Starting on 26 may but myself i only write 2 subjects maths paper 1 on 04 june p2 07 june at 14h00 Then for physical science p1 11 june p2 14 june at 14h00 also..u can even Google it already there..
Sir Mlungisi, I know it's late and the video is probably old, but I have a question about a certain Method I used. If you could seek the video to where you solve the 2 second question (minute 25:12) , where you use ∆y = -30m. I solved that question by combining the time from A-B, and from B-D using two different equations and still got 3.7s. I chose downwards as (+) My first equation was : Vf=Vi+a∆t 0 = -10 + 9.8∆t ∆t = 1.02s Secons equation : ∆y = Vi∆t + ½a∆t² 35.1= (0)∆t + ½(9.8)∆t² 4.9∆t² = 35.1 ∆t = 2.62 .°. ∆t = 1.02+2.68 = 3.70s
Hi Sir. At 1:01:48 I got a positive displacement instead of negative. I took upwards as positive direction of motion & you took downwards as negative direction of motion. Please help cause we are supposed to get the same answer regardless of the direction of motion taken according to my understanding. 🙏🙏🙏
Oh sir I just noticed that at the end when we had to add the two in order to get the distance, you didn't consider the signs and we ended up with the same answers so I guess its fine ?
Sir i got 3,9 I first found the time of A toC which was 2.04 then i calculated the time of C to D which was 1,86 then i added both the time loops the answer was 3,9
Sir can I please ask on 1:01:23 On that 🔼t which is equal to 1,53s Isn't that the time for P to R... like iskhathi for P to R mase sisonke Now how come sisebenzisa sona futhi for uP to Q... how come iskhath sakhe silingane neskhath mase sisonke from P to R... yho do I make any sense 😄
mr nkosi ,I am greatful for all these lesson but can kindly do a hot air baloon projectile together with a projectile with 2 object being thrown upwards or downwards .Looking firwad to such session and i blv thst u will un pack them
Thank you. I already covered one with balls thrown upwards and another downwards. Check it on revision series. I will definitely consider your suggestion
Thank you so much Sir. I really appreciate all your efforts. May I please make a video suggestion? May you please film a video on Newton's laws and everything else that falls under that as I am kind of struggling with it. I am not confident in that topic and I want it to be my strongest topic. I hope I am not asking for too much.
Hi Cleooo, This channel is created exactly for that reason, to help you win in Physical Science. The more suggestions you give, the more it will be of helpful to you. So, please keep them coming... Hope I'll be able to impress you with future lessons on Newton's Laws
Sir ok I get you on displacement when they cancelled each other out but with intial velocity of 10m/s I don't get y they don't cancel as they reach a starting point
Sir I find the downwards as positive and determining the sign of the gravitational force confusing. When we take downwards as positive isn't the gravitational force for the ball A and B example going to be - when it goes up?
Can u please print the questions in larger print. It took so long 4 me 2 eventually write the actual question cos u said it in bits & pieces. It was really difficult 2 understand whether ball A was on the ground or on the building. I am really grateful 4 all ur help but we need 2 understand the question b4 u start explaining so that copy is really important 2 our initial understanding of the question.
Thank you for the work sir that's lovely But the thing Is I am in grade 12 and it is hard to read and understand what I am reading I don't know why ❣️❣️😔 I like to be helped pl😢z
you made a mistake by the quadratic formula , you forgot to make the 2(4.9) a negative it's suppose to be ______________________ 10+/-\ / 10² -4 ( -4.9 )(30) -------------------------------------------- 2(-4.9)
@@MlungisiNkosi hi sir but i think you made a mistake by making 4.9 negative cause it ended up being quadratic equation meaning it has changed sign, 4.9-10-30=0 therefore (a) doesn't supposed to be positive?
Thank you so much sir you explained everything in detail.....Sir I think you made a mistake in the question about Thembi: Number 3 more specifically, was it not supposed to be vf=26,23
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@@MlungisiNkosi Sir in 21:32......the question says we should calculate the final velocity of the ball 10m below the roof....shouldnt we use ∆y=30m - 10m = 20m ?
@@UrbanLuxe.Records no…
Matrics of 2022 are really benefitting from these videos. Sir explains so clearly that even a 5 year old can understand what he's saying. Actually feeling guilty I don't have to pay for these lessons.... top quality stuff
Thank you for the compliment... You may always support us financially if you want to.
I wrote physics today and I watched almost all your videos, it really helped! I hardly understood physics as much as i do right now. Thank you for the brilliant knowledge you share with others!! You're blessed! 🙏👏🏻
It's my absolute pleasure...
And how did your , I presume prelims turn out ? Are we popping champagne ?😭
Thank you so much sir your videos helped me a lot 🎉I was able to obtain good marks for matric and pursue a career in medical science in anatomy and they are still very useful even now .Thank you so much
Sir you are honestly God sent, you've helped me so much and i appreciate the time and patience you provided in helping us achieve academic excellence . ❤
I like how u go over each problem slowly to ensure that we understand ❤
thank you … That is my style of teaching
Thank you Sir you really helped me understand this chapter . God bless you 💗at first I was lazy to watch your videos because they long 😂 but now I understand why they are long. They have so much info and they are helpful ❤😂 thank you again Malume you are a star ✨
Thank you so much Sir. I had no idea with what was happening with this topic but now I understand everything. Thanks again and we appreciate your efforts 🙏🏾
You’re welcome
Watching you after 2 years of trying to understand this all I ca. say is we are cruising nicely ❤❤
You're our messi in physics 😅🔥👏👏👏👏👏👏
Thank you so much sir for answering my request am also writing physics June suppl
Awesome... I'm glad I was able to scratch where it itches
Thank you so much! The video is very informative because wow both my teachers (extra class and school) taught me vertical projectile motion and I still didn't get it until I watched this video, THANK YOU:)
You’re welcome 😉
Thank you so much sir for helping us... I wrote a physics test today and all your work was very helpful, and I thank you for that💯
Please share your results 😊
The best tutorial vid I've come accross so far🔥🔥🔥 big ups.
That is great to hear… thank you
I always come to your channel clueless and come back feeling confident that I can be an A student 😭🥺
That’s the best thing I’ve heard today because you are an A-student. Don’t let anyone cause you to doubt that. Take your place 😊
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Wowww VPM at its best 🔥Thank you sir👌
I’m here now… Where have you been? 😃
Hi sir Thembi's questions,number three wasn't the change in displacement supposed to be 20m since we are 10m below the roof?
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Sorry for 1:04:39 why are you not using 3s but 1.5 since 3 is full time
I checked… You probably put a wrong time stamp
@@MlungisiNkosi my apologies I think it’s 1:04:33 (I’m confused as to why you used 1.5 instead of 3 seconds when we calculated the time to be 1.5 x 2 = 3🤔🤔)
@@dr_logical_b3a5t63 3s is the time for the ball to return to its original position but in the second question about max height, hence we used half of the time which is 1.5s
@@MlungisiNkosi you’re a beast man ❤️🔥 thanks so much, wish you were my teacher
This is really helpful as am preparing for final exams🏅
All of God's best for your exams.
Hi For question b
What if I first calculated the time between A and B,coz we know that the time AB is the same time as BC...then after I can calculate the time between CD then I add them together
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at 28:52 nna i found vinal velocity first then found the distance that way.there were alot of steps involved in your workings. does that mean that a candidate that used your method would get credited more than i would?😭
Hi, sir. For the 2nd question, why do we use the 30m as it is? Wouldn't that imply that the ball was dropped rather than thrown? Meaning that we have to use the max distance
We always use displacement for this equations.
Late but hope it helps in future.
Thank you sir your videos really helps I am also re writing my matric on JUNE .PLEASE upload more videos
I'll be tackling graph questions next... Be on the lookout
We use a negative displacement when the object moves from up to down?
it depents wheather you chose up or down as positive or negative
Sir regarding Thembi(question 2), why didn't you include the 5.1m when calculating the time? From my understanding, we start counting from when it was thrown, to the maximum height then to when the ball touched the ground. Please correct me if I'm wrong.
Awesome question... Please remember that the total displacement is taken in straight line from beginning to the end point. The displacement from beginning to the maximum height and from maximum height back to the same position is zero. Thus the total dissplacement to the ground will exclude the 5.1m value.
I hope that makes sense
Xha kuthethwa ngomntu oluncedo kuthethwa ngawe Maneer , enkosi kakhulu sir 👍.
Enkosi... 🤗
Thank you so much sir for all your lessons. It has really been helpful 🙏🙌
It’s always a pleasure
Please Sir don't take too long to post I'm writing exams on June so ur teachings really helps me i wish you could do all physical science Chapters
Do you perhaps have the june timetable exam?
@@zuheylahime1203 Nope i saw it on Facebook page may/june group...we're Starting on 26 may but myself i only write 2 subjects maths paper 1 on 04 june p2 07 june at 14h00
Then for physical science p1 11 june p2 14 june at 14h00 also..u can even Google it already there..
@@tebatjobonolo6417 Thank you so much for replying. I saw the exam timetable . All the best :)
I will try my best
I hope you wrote well
Sir you're Goated 🐐 ❤
Mina nje ngithi qhubeka wenze umsebenzi omuhle mfoka Nkosi
Sir Mlungisi, I know it's late and the video is probably old, but I have a question about a certain Method I used.
If you could seek the video to where you solve the 2 second question (minute 25:12) , where you use ∆y = -30m. I solved that question by combining the time from A-B, and from B-D using two different equations and still got 3.7s.
I chose downwards as (+)
My first equation was : Vf=Vi+a∆t
0 = -10 + 9.8∆t
∆t = 1.02s
Secons equation :
∆y = Vi∆t + ½a∆t²
35.1= (0)∆t + ½(9.8)∆t²
4.9∆t² = 35.1
∆t = 2.62
.°. ∆t = 1.02+2.68
= 3.70s
That is perfectly fine, just longer 😀
@@MlungisiNkosi Ok Thank You 🙏🏽🙏🏽🙏🏽Sir
Hi Sir. At 1:01:48 I got a positive displacement instead of negative. I took upwards as positive direction of motion & you took downwards as negative direction of motion. Please help cause we are supposed to get the same answer regardless of the direction of motion taken according to my understanding.
🙏🙏🙏
Oh sir I just noticed that at the end when we had to add the two in order to get the distance, you didn't consider the signs and we ended up with the same answers so I guess its fine ?
I’m happy to hear that you figured it out
Sir i got 3,9
I first found the time of A toC which was 2.04 then i calculated the time of C to D which was 1,86 then i added both the time loops the answer was 3,9
Good luck to all the matrics writing Physics today ❤ and thank Malumz🙏
You’re welcome
for the question of ball A and B, the delta y that we got,is it the distance it travelled to the maximum height or the max height?
Ijooooooo... This being a 90-minute video, please be try to be specific at which time you are referring to.
@1:01:48
Sir can I please ask on 1:01:23
On that 🔼t which is equal to 1,53s
Isn't that the time for P to R... like iskhathi for P to R mase sisonke
Now how come sisebenzisa sona futhi for uP to Q... how come iskhath sakhe silingane neskhath mase sisonke from P to R... yho do I make any sense 😄
thank you so much for this lesson it helped so much , would you please do another one this year that includes bouncing objects 🙏
We’ll see in the near future
You are the best KING bayede
Sibonge 🙏🏾
Please don't take long to upload
I hope you are happy. I really am trying my best
Why are we not adding the displacement when calculating time
Please show the timestamp
Thank you for the effort sir🙏😭
You're welcome Mpumi
Amazing as always
Thanks a million 🤗
What question paper is this ?
I love you Mr Nkosi💖💖
I love you guys too 😊
59:29 "Am I still doing the right thing?" 😂😂
😂😂😂😂😂
mr nkosi ,I am greatful for all these lesson but can kindly do a hot air baloon projectile together with a projectile with 2 object being thrown upwards or downwards .Looking firwad to such session and i blv thst u will un pack them
Thank you. I already covered one with balls thrown upwards and another downwards. Check it on revision series. I will definitely consider your suggestion
May you please make a video on a ball that reaches the ground and bounces
That's a brilliant suggestion... Thank you
Thank you so much Sir. I really appreciate all your efforts. May I please make a video suggestion? May you please film a video on Newton's laws and everything else that falls under that as I am kind of struggling with it. I am not confident in that topic and I want it to be my strongest topic.
I hope I am not asking for too much.
Hi Cleooo,
This channel is created exactly for that reason, to help you win in Physical Science. The more suggestions you give, the more it will be of helpful to you. So, please keep them coming... Hope I'll be able to impress you with future lessons on Newton's Laws
also how are we going to show that vf at the graph
Make sure to show the direction of Vf when you’re calculating. It will be easer to follow when plotting
1:02:00 ok I used this Equation ∆y=vit+½gt²
But I found -15.45 instead of -11.48
Sir can you please upload a video based on organic chemistry grade 12
I want to master that section in June
Please explain every thing
Coming right up. But let me warn you that it will be several videos because Organic Chem is a huge section.
If we chose our conventional direction as positive,, will our v/t graph start at the top as 15 positive
Absolutely… You are right.
Sir with question 1 why can we not say that vf at any other point except D is 0?
Sir ok I get you on displacement when they cancelled each other out but with intial velocity of 10m/s I don't get y they don't cancel as they reach a starting point
I’m not sure I follow
Sir I find the downwards as positive and determining the sign of the gravitational force confusing. When we take downwards as positive isn't the gravitational force for the ball A and B example going to be - when it goes up?
Please go back to my first video on Projectile Motion. It will make complete sense, I promise
@@MlungisiNkosi thank you sir.
Sir which question paper is this one year and month ? The one with Ball A and Ball B
Yhooooo I forgot yazi 🫣
Eish... okay no problem thanks
Which past year paper did you use for this lesson
Honestly I used a document that has a complication of question papers. I will try to find out and get back to you.
Am writing today this really helped me
I guess this channel is really serving its intended purpose. Thank you 😊
Thank you for everything🙏🏽❤
Hi sir I would like to know if u offer extra classes online but in private?
Yes I do. Please reach me via email: mlungisi.m.nkosi@gmail.com
Can u please print the questions in larger print. It took so long 4 me 2 eventually write the actual question cos u said it in bits & pieces. It was really difficult 2 understand whether ball A was on the ground or on the building. I am really grateful 4 all ur help but we need 2 understand the question b4 u start explaining so that copy is really important 2 our initial understanding of the question.
Noted. These were the days when I started… I didn’t have the best of resources but I tried to make the best of what I had. I hope you understand
I do sir & really appreciate all of ur help...
@@rickasinghbhoola8719 thank you 😊
Thank you so much
Great video
Can you do a video covering newtons 2nd law and calculations please 🙏🙂
Thank you... I agree. That's one of my favorite sections in Physics actually.
Sit can you pls upload a video abt that 5 or 6 mark question only in vertical projectile motion
59:29 me everyday🤣
sir but when it goes up to max it takes time so Im finding it hard to understand why its 30....
Because we are only considering the displacement. Please watch the PLAYLISR i crated on vertical projectile motion
Please whenever you are moving up also move the camera with you
Eish Unfortunately these were recorded last year when I was using the manual system…
Sir Whats the Question paper's date
For which question?
@@MlungisiNkosi last question on the video
Should be q1,2,3 for vertical projectile...
@@gospelradipere3954 I’ll check it out and let you know
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34:14 okay nevermind😭😂🤭 thank you
🎉thank you sir !
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Thank you for the work sir that's lovely
But the thing Is I am in grade 12 and it is hard to read and understand what I am reading I don't know why ❣️❣️😔
I like to be helped pl😢z
Writing physics Friday
All the best 😊
2024❤🎉🎉
Thank you again
My sincerest pleasure 😊
It is not yet uhuruu 😅
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you made a mistake by the quadratic formula , you forgot to make the 2(4.9) a negative it's suppose to be
______________________
10+/-\ / 10² -4 ( -4.9 )(30)
--------------------------------------------
2(-4.9)
Thank you pointing that out 😊. I'm glad you understood though
@@MlungisiNkosi
hi sir but i think you made a mistake by making 4.9 negative cause it ended up being quadratic equation meaning it has changed sign, 4.9-10-30=0 therefore (a) doesn't supposed to be positive?
Thank you so much sir you explained everything in detail.....Sir I think you made a mistake in the question about Thembi: Number 3 more specifically, was it not supposed to be vf=26,23
It's possible that I might have. Thanks for pointing it out
@@MlungisiNkosi really love the content🥺🔥
@@sour_mister thank you... I pray it helps towards the fulfillment of your dreams.
Inshallah, I will get an A this term
My pleasure… Please don’t forget to tell others about this channel.
Congratulations in advance for your A
❤