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In force polygon, the scale multiplied must be 200 not 1000, because for 5cm it is 1000N. So for 1cm, it is 200N. Thus, F34 is 1040N.
Yes, but 1050 N
thank u sir for ur videos has helped me alot for this sem ✌
the perpendicular length (arm length) of F32 force from the hook A should be 2 cm and not 1.9 cm otherwise there will be a flaw in our construction of the diagram
Yes correct
T=99750Nmm ✅T=99.75Nm ✅T=99.75Nmm ❌
Sir aapko pata hai padhana bhi hota kaise hua kyu hua kya rule hai sirf khud solve nahi karna hota abhi sir dukhra mera ye video dekhne ke baad
Right
Haha bhai kuch SMj nhi araa 23 ko xm h
@@Nemo-k6f badshah easy hai ho jayega
F34 should be equal to 5250 N, not 1050 N.
Consider scale
oru parim mnsilavnilla nirthi po ....
WHICH IS NOTHING BUT...
In force polygon, the scale multiplied must be 200 not 1000, because for 5cm it is 1000N. So for 1cm, it is 200N. Thus, F34 is 1040N.
Yes, but 1050 N
thank u sir for ur videos has helped me alot for this sem ✌
the perpendicular length (arm length) of F32 force from the hook A should be 2 cm and not 1.9 cm otherwise there will be a flaw in our construction of the diagram
Yes correct
T=99750Nmm ✅
T=99.75Nm ✅
T=99.75Nmm ❌
Sir aapko pata hai padhana bhi hota kaise hua kyu hua kya rule hai sirf khud solve nahi karna hota abhi sir dukhra mera ye video dekhne ke baad
Right
Haha bhai kuch SMj nhi araa 23 ko xm h
@@Nemo-k6f badshah easy hai ho jayega
F34 should be equal to 5250 N, not 1050 N.
Consider scale
oru parim mnsilavnilla nirthi po ....
WHICH IS NOTHING BUT...