Q.1 sps 1 semelparity becoz juvenile death is high due to less parental care and sps 2 is iterioparity beacause death is high at maturity can suggest good parental care. Q.2 sps 1 is shows semelparity because it has stable environment and semelparity sps required unsaturated environment for reproduction and sps 2 shows iterioparity coz it is showing unstable environment and iterioparity can seen in saturated environment . Thanku Sir
Amazing lecture thank you so much sir Q.1species 1 stable environment and semalparity strategy and Q.2 Sp. 2 unstable environment and iteroparity strategy follows
Q1- sp1 -semalparity due juvenile death mean less or no parental care n body size small grow fast sp2- Iteroparity due to more parental care n body size large so growth slowly Q2 - Stable environment - semalparity bcz no competition no disease unstable environment - Iteroparity bcz competition n disease occur.... thanku sir 🙏🙏🙏
in a population they are 100 insects after 3months the number of insects increase 250 calculate the growth rate specific growth rate and percentage growth rate per week . Sir ji ish questions ka solution bataye plz
Q.Initial pop of insects is 100 after 3 months no. increased to 500 , calculate growth rate, specific growth rate and percentage growth rate per week. solution:- 1)Growth rate per week = dN/dt= 400÷12= 33.34 2)specific growth rate= 100=33.34 so, 1=33.34÷100= 0.34 3)percentage growth rate =0.34×100=34
Growth rate-33.3 Stable environment - Iteroparity better because of saturated environment, time taking reproductive process 2.unstabel environment - samelparity better. Because less age jinda rahete hai & progeny number high
Great teacher ....he has comprehensive knowledge of ecologg
...isee khte h ecology pdhana, baki poori duniya pdha hi rh h, kuch v yad ni krna kuch v rtna nhi🙏
Such a wonderful explanation
Q.1 sps 1 semelparity becoz juvenile death is high due to less parental care and sps 2 is iterioparity beacause death is high at maturity can suggest good parental care.
Q.2 sps 1 is shows semelparity because it has stable environment and semelparity sps required unsaturated environment for reproduction and sps 2 shows iterioparity coz it is showing unstable environment and iterioparity can seen in saturated environment .
Thanku Sir
Amazing lecture we require this type of lecture ❤
Thank you so much. Itne acche se padhate hain aap, sab kuch samajh me ata hain.
Thanku so much guru ji 🙏
Mind blowing explanation style 🙏
Nice explanation sir ji.... A great educator ❤😊
33.3 growth rate....Thank you sir...abb mjay ecology samaj aane lagi...warna toh mjay darr lagta tha ecology se...ur teaching style and knowledge is brilliant sir
Thank you so much Sir Ji never found this type of teaching Amazing
Crystal clear explanation with very easy way.......
👍👍👍👍👏👏👏👏
Amazing lecture thank you so much sir
Q.1species 1 stable environment and semalparity strategy and
Q.2 Sp. 2 unstable environment and iteroparity strategy follows
excellent explanation....thankyou so much sir
Best video for population ecology ❤ Really helpful
Thanku so much Sir
Hattsoff sir aaj mei aapki paraye hu ecology samjh paye
You are really a very good teacher sirrr...tqqqq alotttt🙏🙏🙏🙏🙏🙏🙏🙏
Q1-
sp1 -semalparity due juvenile death mean less or no parental care n body size small grow fast
sp2- Iteroparity due to more parental care n body size large so growth slowly
Q2 - Stable environment - semalparity bcz no competition no disease
unstable environment - Iteroparity bcz competition n disease occur....
thanku sir 🙏🙏🙏
Helpfull video
Sach me itte ache se aaj he samjh aaya
Very good presentation, thanks sir
Very easy way explanation thank you sir
Keep watching
Thank you sir ❤...... very helpful video 🙂
Great sir
❤❤❤❤❤
Thank you sir......great lacture 🙏
Thank you so much sir👏👏
Great sir vry nice explanation ❤
Thanks and welcome
Growth rate = 30.8
Specific GR - 0.308
% GR - 30.8
Msc ke liye sir Itta notes enough ??
Thankyou so much sir 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Thankyou sir..
Great analysis,,, Thank you so much
Oswm lecture sir thanks 😊
in a population they are 100 insects after 3months the number of insects increase 250 calculate the growth rate specific growth rate and percentage growth rate per week . Sir ji ish questions ka solution bataye plz
Aapka ans. Aaya h??
Sir can I study for my upsc cse exam through your classes
GREAT ANALYSIS SIR 👍
Thnks guru jii🙏
Thanku sir 🙏
Thank you sir
Thank you sir 🙏
33.3 growth rate, 0.33 specific growth rate
Thank you
Q.Initial pop of insects is 100 after 3 months no. increased to 500 , calculate growth rate, specific growth rate and percentage growth rate per week.
solution:-
1)Growth rate per week =
dN/dt= 400÷12= 33.34
2)specific growth rate= 100=33.34
so, 1=33.34÷100= 0.34
3)percentage growth rate =0.34×100=34
@Rukia kya aap bta sakti hai ki dt ki value 12 kyon li
@@muskansagar7793 months diye hai humen week ke according dekhna hai question mei . Tou 3 months mei 12 weeks hote hai isliye
samajh aa gya thank you Rukia
@@muskansagar77912 week
Tqq so much sir
Good evening sir
33.3 growth rate....
good evening sir!
Good Evening Bhai
1/3 specific growth rate
Kya ye +3 ke liye bhi ?
33.3 %age G. R
Answer species 2 interioro parity
Minimum size kitna hai ek population mein?
sir pdf mil skta hai kya
Nahi
Growth rate-33.3
Stable environment - Iteroparity better because of saturated environment, time taking reproductive process
2.unstabel environment - samelparity better. Because less age jinda rahete hai & progeny number high
Thanku sir.....
Good evening sir