Preparation of alcohols using NaBH4 | Alcohols, ethers, epoxides, sulfides | Khan Academy

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  • Опубліковано 22 жов 2024

КОМЕНТАРІ • 10

  • @evanscami
    @evanscami 10 років тому

    u can't believe what u did 4 me....thanksssss alot !!!!!!!!!!!!1

  • @tarirochihota8073
    @tarirochihota8073 8 років тому

    Khan academy for life

  • @darkfeather111
    @darkfeather111 6 років тому +1

    7:58 why in this reaction do we use methanol unlike the first reactions when we used H+? like how did you know to just use methanol

    • @sindhu...18
      @sindhu...18 4 роки тому

      I think,to reduce ketones alcohol should be used as a solvent

  • @shiveshkumar890
    @shiveshkumar890 9 років тому

    sir in da abv rxn 'H' [BH4] has positive charge ,hw can it attach to the carbo cation .please clear my doubt,sir

  • @cartoonjoystick
    @cartoonjoystick 8 років тому

    Is this a SN2 mechanism? I need fast answer :)

    • @mistersirisaacnewton
      @mistersirisaacnewton 8 років тому

      +Cartoonjoystick nah it's not SN2. If it was SN2 that would indicate that the BH4 would stay bonded and the oxygen would leave (which wouldn't happen since SN2 reactions normally have halides as leaving groups)

  • @equfrj2296
    @equfrj2296 11 років тому

    Is this mechanism a consequence of the oxymercuration of an alkene?

  • @alesgrundzi791
    @alesgrundzi791 8 років тому +1

    anyone stuck confused on how to do the LiAlH4 + Aldehyde? :(

  • @tonydanis1480
    @tonydanis1480 9 років тому +2

    Simply too fast....much better videos with good pacing and far more
    sophisticated diagrams available on UA-cam..............