Electricity - Class 10th Science 🔥| One Shot | Prashant Kirad
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- Class 10th - Electricity Complete Chapter
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#class10science #study #class10 #class10th #motivation #class9
All Formulas of Electricity:
1) I = Q/t
2) Q = ne
3) V = W/Q
4) V = IR
5) R = Rho x L/A
6)Resistance in Series: Rs = R1 + R2 + R3
7)Resistance in Parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3 (» Reciprocal of R1+R2+R3)
8)H = V × Q
i) H = VIt
ii) H = I²Rt
iii) H = V²t/R
9) P = W/t
i) P = VI
ii) P = I²R
iii) P = V²/R
10) E = P × t
S.I. Units:
Current ( I ) - Ampere
Charge ( Q ) - Coulomb
Time ( t ) - Second
Potential Difference or Voltage ( V ) - Volt
Resistance ( R ) - Ohm Ω
Resistivity ( Rho ) - Ohm meter
Power ( P ) - Watt
Heat = Energy = Work = Joule
Measuring Devices:
Ammeter / Milli Ammeter - for measuring current (always connected in series)
Galvanometer - for measuring small/sensitive currents (we can also get the direction of the current)
Voltmeter - for measuring volts (always connected in parallel)
Ohm Meter - Measures the resistivity
Things to remember:
electron charge = (1.6 x 10⁻¹⁹ C)
1kWh= 3.6 × 10⁶J
1Ampere = 1000mA
1 Kilowaat = 1000W
1 Horse Power = 746W
i hope this list will help you! ❤
ek free ka like dete jana
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5:28 Start
5:58 Topics to be covered
10:19 Electric Charge and it's Properties
12:07 Quantisation of Charge
14:29 Question
15:43 Electric Current
18:40 Question
20:32 Potential Difference
23:48 Question
24:40 Trick to do Questions
25:10 Questions
32:27 Electric Circuit
36:21 Ammeter and Voltmeter
37:06 Ohm's Law and Resistance
41:30 Questions
55:57 Resistivity
56:26 Resistance v/s Resistivity
57:55 Questions
1:09:09 Series and Parallel Combination
1:16:30 Questions
1:32:22 Advantages of Parallel Combination
1:33:50 Heating Effect of Electric Current
1:38:02 Applications
1:41:38 Questions
1:44:05 Electric Power
1:47:55 Questions
1:55:00 Electrical Energy
1:57:42 Questions
2:16:14 Outro
Thanksskskskksss
@@Ayush_a_BlackRose thanks bhaiiii it's really helpful..🥲💕
Bhaiya aapse padh ke confidence aata hai hai mujhe physics aata hai
1:08:52 d)4D and 2L
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6:12 Conductors,Insulators, Semiconductors
10:07 Electric Charge
12:08 Quantization of charge
15:51 Electric Current
20:25 Potential Difference
27:28 PRASHU BHAIYA WITH TROPHY 🏆 🏆
32:28 Electric Circuit
36:23 Ammeter v/s Voltmeter
37:07 Ohm's Law
53:20 Factors Effecting Resistance
55:57 Resistivity
56:27 Resistance v/s Resistivity
1:09:10 Series and Parallel Combinations
1:32:25 Advantages of Parallel over Series Combination
1:33:54 Heating Effect of Electric Current
1:38:03 Application
1:37:16 yes bhaiya par aapko bhi experience hai tabhi sab pta h aapko.....❤️🤣
Bhaiya Aaj ki watching dekhke mummy boli esa kya padha rhe ki 750k bacche aa gye unhe nhi pta ki inme bots bhi the...but all apart the lecture is on next level sare doubts clear ho gye❤️🔥🧿
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_#hindi__ __#marathon__ __#hindi__ course A __#class__ 10_
Edit : *please like if agree ..and also request for a good teacher at any cost*...
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2:15:58 Power = 1.25 W
Bhaiya aarambh and abhay mein already solve kiye hue hain 😊😊🙏🙏
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Correct😊
Mine is same!!
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कृष्णाय: वासुदेवाय: हरये प्रमात्मने:
प्रणत: क्लेशनाशय: गोविंदय नमो नमः
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1:08:53
(D) MINIMUM RESISTANCE IS 1/8
2:15:21
(A) 24 OHM
(B)0.25 Ampere
(C) i) 1V ii) 5V
(D) P = 1.25W
Hiiii
❤❤
I wish everyone will score 95+🥰
timestamps
5:28 Start
5:58 Topics to be covered
10:19 Electric Charge and it's Properties
12:07 Quantisation of Charge
14:29 Question
15:43 Electric Current
18:40 Question
20:32 Potential Difference
23:48 Question
24:40 Trick to do Questions
25:10 Questions
32:27 Electric Circuit
36:21 Ammeter and Voltmeter
37:06 Ohm's Law and Resistance
41:30 Questions
55:57 Resistivity
56:26 Resistance v/s Resistivity
57:55 Questions
1:09:09 Series and Parallel Combination
1:16:30 Questions
1:32:22 Advantages of Parallel Combination
1:33:50 Heating Effect of Electric Current
1:38:02 Applications
1:41:38 Questions
1:44:05 Electric Power
1:47:55 Questions
1:55:00 Electrical Energy
1:57:42 Questions
2:16:14 Outro
i want a single like
2:16:00
Ans: (a) R eq = 24 ohm
(b) I = 0.25 A
(c) [i] 5V
[ii] 1V
(d) P= 1.25 Watt
😅🙂🫠🫠🫠🫠🫠
I pray to God 🙏🙏 that nothing wrong happens in your free education ✍️✍️ channels....keep teaching like this all the days and keep moving forward ❤❤
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Easy tricks to remember authors of lessons for class 10:
English:
1. A thief's story - Hari Singh and Anil had a *bond* - Ruskin *Bond*
2. A Question of Trust - Two *cunning* thieves - Victor *Canning*
3. Midnight Visitor - Midnight is when thieves *rob* - *Robert* Arthur
4. Bholi - Bholi *ka appa* Ramlal - *K.A Abbas*
5. The Book that saved the Earth - *Book* - Claire *Boiko*
6. Fog - Fog and *sand* - Carl *Sandburg*
7. The Trees - _A _*_dree_*_ ienne_ Rich - Adrienne Rich
8. Mijbil The Otter - Lutrogale Perspicillata *Maxwelli* - Gavin *Maxwell*
9. Dust of Snow - *Snow* - Robert *Frost*
10. Fire and Ice - *Ice* - Robert *Frost*
11. A Letter to God - Letter L and God G - Reverse is *GL* - *GL* Fuentes
12. How to Tell Wild Animals - Tell rhymes with *Well* - Carolyn *Wells*
13. The Proposal - Lomov and Natalya always fight - They try to *"Checkmate"* each other - Anton *Chekhov*
14. Tiger in the Zoo - Tiger has *less* freedom - *Leslie* Norris
15. The Ball Poem - Ball and *Berry* starts with B - John *Berryman*
16. Tale of Custard the Dragon - Dragon lives in *den* - *Ogden* Nash
17. Amanda! - Freedom - Flying - Bird - *Robin* - *Robin* Klein
18. Footprints without Feet - Griffin - fin is a body part of fish - fish lives in *well* - HG *Wells*
19. Madam rides the Bus - *Valli* - *Vallikannan*
20. Tea from Assam - Tea is *arumai* and Rajvir knew a lot of *data* about Assam and tea plantations - *Arup* Kumar *Datta*
Aise bhi question aayenge??
nhi bro yeh sab 10 saal pehle aate the@@Legend_96
@ayushraj5533 thanks for confirming🙏
Bhai poets ka author yad kar lena poets ka aata h@@Legend_96
1:08:53
D) I/8
2:15:20
A) 24 OHM
B) 0.25 A
C) i) 1V ii) 5V
D) 1.25W
Resistance of the lamp = 20 OHM
External = 4 OHM
[A] = As both are connected in series , So
= R = 20 = 4 = 24 OHM
[B] = I = V/R = 6/24
=0.25 A
[C1] = potential = total voltage/total resistance * R of lamp
= 6/24*20 = 5V
[C2] = total voltage/total resistance * R of conducter
= 6/24 * 4 = 1V
[D] = Power = i^2 * R
= [0.25]^2 * 20
= 1.25 W
2:15:57
Total resistance =24ohm
Current =0.25
Potential difference for lamp=5v
Potential difference for conduter=1v
Power =1.25
Thanks 😊 ❤❤❤❤❤❤❤❤❤
2:15:42
A.. 24 ohm
B.. 0.25 A
C.. 1.. 5v
2.. 1v
D.. 1.25w
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D is wrong
@@udaychauhan888 No it's right bro
Yes d wrong h
@@udaychauhan888 P=VI --- P=5×0.25 ---- P= 1.25w
22:01 भ्राता श्री के 😂expressions
2:15:21 Resistance=24 ohm
Current= 0.25 ampere
Potential difference i) 5V
ii) 1V
Power= 1.25W
1:08:52 d) 4D and 2L
howwww pls explain
2:17:32 Bhaiya last me jo power hai wo ayegi 1.25W
Absolutely right
Thankuu soo muchh bhaiyaa aapne apne channel ke baare m na sochte huye hma pdhana zaruri smjha❤🥺respect for prashant bhaiya❤👍
2:16:14
a=24 ohm
b=0.25A
c. (i)1v
(ii)5v
d=0.25watt
Bhaiya Aaj se pehle kabhi bhi teacher ban ne ka ni socha lekin ab sochti teacher banu, vo bhi aapke jaisi ❤ you all three are the best ❤
Kis kis ko Electricity Ab "Halwaa" lag rhi hai 😂
A) RS=20+4=24𝙤𝙝𝙢𝙨
B)I=6/24=0.25 𝘼𝙈𝙋𝙀𝙍𝙀
C)i) V=0.25×20=5𝙑𝙊𝙇𝙏𝙎
ii) V=0.25×4= 1𝙑𝙊𝙇𝙏𝙎
D) P=5/20=1.25𝙒𝘼𝙏𝙏𝙎
Correct
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Sir we are very grateful to have you in class 10 . You are best teacher of science . Thankyou so much sir for this lecture 🤞
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1:08:57 Option (d) 4D and 2L
2:15:20
a)24ohm
b)1/4 i.e 0.25 Amphere
c)5V
d)1
Q) 1:08:58 Ans d)
Last question answer for power is 1.25W.
Me
Yes
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27:11 Prashant bhaiya bohot ajib tarike se haste hai😂
2:16:09 a) 24 ohm
B) I=0.25A
C) i=5V ii=1V
D) Power= 1.25W
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41:35 d
1.25 W
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1:48:11 option(c)
2:15:41 a.24 ohm
B. 4A
C (i) 5V, (ii) 1V
D. 1.25W
2:15:15 (a) Total Resistance of the Circuit
Rnet= 24 ohm
(b) Current through the Circuit
I = 1/4 = 0.25 A
(c) Potential Difference across the Components
(i) Across the electric lamp: V1= 5v
(ii) Across the conductor: V2=1v
(d) Power of the Lamp
p = 1.25 W
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Home work
1)Option D
2) a)24 ohm
b)0.25 A
c)5v,1v
D)1.25w
2:15:22
Electrical lamp = 20 ohm
Conductor = 4 ohm
a) In series
Req:- R1 + R2
Req= 4+20 = 24 ohm
b) V=IR
6 = I x 24
6/24 = I
1/4 A = I
c) (i) In series Cureent is same:- so
Lamp:- V=IR
V = 1/4 x 20 = 5V
(ii) conductor = V = IR
V = 1/4 x 4 = 1V
d) Power of lamp
P= V^2/R
P= 5^2/20
P= 25/20
P= 5/4 or 1.25 W
Thank you 🙏🏻
2:15:27 (a)Total resistance is 24 ohm
(b)Current is 0.25A
(c)(i) 5V (ii) 1V
(d) 1.25 watt
D ka answer kaise ayega bataona
D ka ans kese aya
There they asked the power of the lamp so the V we found was (ii) is 5V and current we found was 0.25 so by power formula P=VI ( 5x0.25) we get 1.25
I hope it's helpful 🙂
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2:15:56 ans is. 1.25 watt
Wrong hai 😂😂😂
The answer will be 1.25 W
Bhaiya ki cutie 💓 i=Q/T
I=current
Q=charge
T=time
2:14:50
A. 24 ohm
B. 0.25 Amp
C. 5 volt and 1 volt
D. 1.25 Watt
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Jo science ko easy karde
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2:15:17
P=1.25
(a) R net = 24 ohm
(b) Current through circuit=0.25 A
(c ) (1) V through electric lamp = 5V
(2) V through conductor = 1 V
(d) Power (P) = 1.25 W
1:08:52 ans d.4D,and 2L..❤
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0:09 taliya yoo🎉🎉
2:15:00 Answers
A.) R= 24 ohm
B.) I = 0.25 A
C.) i. 5 v ii. 1 v
D.) P= 1.25 watts
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B) D/4 and 4L
Because L is directly proportional to R
if Lenght increase then the Resistance also increse
2:16:00
a) 24 ohm
b) .25 A
c) (i) V=5V , (ii) V=1V
d) P = 1.25 w
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2:15:33
ANSWER:-
a) 24 ohm.
b) 0.25A
c) (i) 5V (ii) 1V
(d) 1.25 watt
❤❤
2:14:49(a) total resistance of the circuit= 24 om (b)the current through the circuit=0.25amphere(c) potential difference electric lamp =5v (ii) conductor=1v (d) power of the lamp = 1.25w
1. 24 ohms
2. 0.25 A
3. 1 v
4. 1.25
❤❤❤
sachi hai bro
4) 1.50 hein na?
@@faheemanees2987 1.25 W correct hai
hi
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Hmmmm
Koi bhi nhiii
1 ) R = 20 ohm ( bulb )
R = 4 ohm ( conductor)
Total resistance= 20 + 4 = 24 ohm
2) V = IR
I = V/R
I = 6/ 24
I = 0.25 A
3) V = 5 v
V = 1v
4) P = I×I ×R
P = 0.25×0.25 ×20
P = 1.25 W
2:15:21 homework question == a)total resistance =24 ohm,b) 0.25A c) i) 5 v, ii) 1 v d) power = 1.25 watt
2:15:00 (a) R = 24 ohm
(b) I = 1/4 = 0.25 A
(c) (i) V across lamp = 5V
(ii) V across conductor = 1V
(d) Power of lamp = 1.25 W
1:15:53 😂😂 maza hi aa gaya
Mujhe nike air force chahiye
2:15:38
TOTAL PESISTANCE = 24 OHM
I = 0.25A
V = 5V
V = 1V
POWER = 1.25W
Hii
23:26❤😊😮🎉😅❤❤
1:15:48 student rocked bhaiya shocked 😂
2:15:53
a) 20+4=24 ohm
b)0.25A
c)i) 5V ii) 1V
d) 1.25W
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1:08:47 D. 4D and 2L
2:17:32 power of lamp is 1.25 W
Voltage of lamp is 5v and conductor is 1v
Total Resistance is 24 ohm
2:15:58
a) total resistance= 24ohm
b) Current = 0.25Ampere
c) (i) 5V
(ii) 1V
d) 1.25 W
Bhaiyaa... This is the answer.... I hope its correct....🥰🎀🍷
2:15:07 a) R=24ohm
b) I=1/4A
c) i)5V ii)1V
d)1.25 watt
Sir session me sab samajh aaya aur maja bhi aaya
Homework solutions:-
1. d. 2L, 4D
2. Power = 1.25 W
Homework done sir 👍
question} 2:16:04
answer
a} resistence = 24 ohm
b} current = 0.25 A
c}i} 5 V
c}ii} 1v
d} p=1.5W
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