At (1:00) I just hoped for the natural logarithm of a complex number z: ln(z) = ln|z|+i * Arg(z). If we put for z=i, the lengt |z|=1 and the argument Arg(z) = pi/2 But your version contains the entire family of solutions
Yes cool but I'm not sure about my family of solutions because if it is a function then the solution has to be one (like in your method)... But it could be a multivalued function.... I think that it just depends upon the definition....😉🤗
Yes, think about it... If your imagination is exponentially large and you're also irrational just getting a little bit forward by adding 1 gets you back at 0!!! 😅🤣🤣🤣 e^(iπ)+1=0
Haha, I think ud love a question about an infinite series of cosx and i sinx. It converges to a nice value and u can also split it into it real and imaginary parts too!!
Complex numbers are weird!!!😅
At (1:00) I just hoped for the natural logarithm of a complex number z:
ln(z) = ln|z|+i * Arg(z).
If we put for z=i, the lengt |z|=1 and the argument Arg(z) = pi/2
But your version contains the entire family of solutions
Yes cool but I'm not sure about my family of solutions because if it is a function then the solution has to be one (like in your method)... But it could be a multivalued function.... I think that it just depends upon the definition....😉🤗
Should use base i for log too, just for good measure. :)
Yes why not!!!😅🤣🤣
Really good video
Thank you so much!!!🤗🤗
:)@@JonnyMath
Thanks!!!🤗
Ig too much imagination is real
Yes, think about it... If your imagination is exponentially large and you're also irrational just getting a little bit forward by adding 1 gets you back at 0!!! 😅🤣🤣🤣 e^(iπ)+1=0
Or we could use the video and realise its pi/2 +2pik :D
Remarkable jokes!!!😅🤣🤣 Gotta take a screenshot!!!😅🤗🤗
Haha, I think ud love a question about an infinite series of cosx and i sinx. It converges to a nice value and u can also split it into it real and imaginary parts too!!