I dont know what youre up to now professor, but your videos are still helping people trudging through the muck of college physics!. Thank you! You are one of many selfless online professors that are helping me get my EE degree.
Finally found my Physics Redeemer ... Love,respect and a lot of Prays for you from Pakistan .... May God grant you health and prosperity in life ... Thank you very much for every piece of your Knowledge
Hello, sir, the vector v2-v1 should originate from point 2. In the video at 2:16 it originated from point 1. according to vector addition, v2-v1 should have point 2 as the tail.
I like that you translated "centripetal" as "center-seeking" --- it makes more grammatical sense to translate it that way rather than the seemingly more common "seeking the center".
Excuse me if I am wrong, but I think there is a small graphical misrepresentation in the drawn triangle at 1:30. Vectors v1 and v2 should have equal magnitudes which means that v1 should be drawn longer and not form a right triangle. That way v2 - v1 will point to the center of the circle and not above it which I think happens now if you put v2 - v1 in place "2" at the circle.
No error here. You have to take the limit as the angle approaches zero. That is the principle of all of calculus. It is drawn bigger here so you can see it.
Consider this: When one is on a typical two wheel motorcycle and needs to make a right "turn" (right curve in the road) - which way does he turn his handlebars, to the right or left? If he is moving faster than a slow "crawl", he should turn his handlebars to the LEFT (just a little, but to the left none-the-less) to make a RIGHT turn.
hımm you have replaced old videos with new ones and these is quite good.but there is no upward throw motion, I hope you will add it thx :)... we generally encounter units from of (i,j,k) you know at university.
Sir, thank a billion again. I am having a problem with visualisation, as when you added vector v2 to v1 the direction is east and nit towards the center of the circle?
@@MichelvanBiezen The drawing is wrong, Michael. Because the vectors have equal length the outcome can't be a horizontal line (2:01). Therefore, the difference-vector should be drawn at point 2 on the circle (pointing slightly downwards to the centre).
thank you very much Mr Michel but i have a question:is the velocity is still perpendicular to the path in a curve motion? if there any videos about that please tell me where it , because i need it very much
When using the equations of kinematics, left and down are negative directions. Since the acceleraion due to gravity acts downward, we place a negative sign in front of that.
Maybe a stupid question but if the acceleration is always to the center of curvature why do you experience a force opposed to the center of curvature when you take a sharp bend in a car for instance? F = m a, so the force should have the same direction as the acceleration.
Duranium, That is a very good question. That "force" that you feel pushing you to the right when you make a sharp left turn is not really a force. We call it the "centrifugal force", because it appears to be a force. What is actually happening is that your body wants to obey Newton's first law and continue in a straight path motion. The car moves to the left (because the friction on the tires push the car to the left (centripetal force)), Your body wants to keeps going straight, but the seat belt pushes you to the left which your body interprets as being pushed to the right.
I think I understand what you mean with the centrifugal force not being a force. Because the observer is in a non inertial frame of reference this force appears to be a force. But when you look at the car from the side you'll notice that this force is a reaction force to the centripetal acceleration. But I dont really understand the following thing: "Your body wants to keeps going straight, but the seat belt pushes you to the left which your body interprets as being pushed to the right." Do you mean that if there is a force on your body in a certain direction that you will interpret it in the opposite direction? Thanks for your response by the way
Duranium The seat belt provides the centripetal force by pushing towards the center of the circular motion. You experience the sensation of being pushed into the seat belt. (because your body obeys Newton's first law
If you use the definition of the derivative, dv/dt as dt approaches zero, v2 - v1 will be perpendicular to the circle. (See what happens when you make the angle smaller and smaller. )
Your video is so, so, so, so dark I have to assume that you work in some creepy basement and the other explanation would have to be that you don't have electric lighting despite the fact that it is the 21st century. From time to time you should watch your own videos and if you do you will understand why it is impossible to call the big board a white board instead we should call it a dark grey hard to see anything board. Would it kill you to turn on the background lights?
I dont know what youre up to now professor, but your videos are still helping people trudging through the muck of college physics!. Thank you! You are one of many selfless online professors that are helping me get my EE degree.
Glad to "hear" it. Keep on going.....
Finally found my Physics Redeemer ... Love,respect and a lot of Prays for you from Pakistan .... May God grant you health and prosperity in life ... Thank you very much for every piece of your Knowledge
Thank you and glad to be of help. Welcome to the channel!
We all know you are an amazing person on behalf of every viewers.
Agreed Nazim. Seems like not only an amazing mind but so organized and clearly so generous. Solid man all around!
Nazim,
Thanks for the feedback.
I love your work so much
Thank you
Sincerely a physics student
Jose,
Thanks for the feedback. It is good to see that students around the world are helped by these videos.
Hello, sir, the vector v2-v1 should originate from point 2. In the video at 2:16 it originated from point 1. according to vector addition, v2-v1 should have point 2 as the tail.
wow this is the best channel out there my physics lecturer doesnt stand a chance ......thank you so much for making physics easy for me to understand
Thank you. Glad you found our videos. 🙂
I am just working my midterm exam, Normally ı cannot understand physics but with you ı kind a like it :)
I like that you translated "centripetal" as "center-seeking" --- it makes more grammatical sense to translate it that way rather than the seemingly more common "seeking the center".
Excuse me if I am wrong, but I think there is a small graphical misrepresentation in the drawn triangle at 1:30. Vectors v1 and v2 should have equal magnitudes which means that v1 should be drawn longer and not form a right triangle. That way v2 - v1 will point to the center of the circle and not above it which I think happens now if you put v2 - v1 in place "2" at the circle.
No error here. You have to take the limit as the angle approaches zero. That is the principle of all of calculus. It is drawn bigger here so you can see it.
@@MichelvanBiezen Ah ok, thank you for your reply sir.
Thank you so much sir, you are really great. May you live a happy life :)
" Center seeking ".......I like that! 😊
.
It certainly makes sense that way.
Omg I finally understood it thanks to you!!!
Consider this: When one is on a typical two wheel motorcycle and needs to make a right "turn" (right curve in the road) - which way does he turn his handlebars, to the right or left? If he is moving faster than a slow "crawl", he should turn his handlebars to the LEFT (just a little, but to the left none-the-less) to make a RIGHT turn.
You are INCREDIBLE
This is a very very nice explanation! Thanks! Greetings from Germany!
Welcome to the channel!
Since it's average acceleration, is it wrong to think it emanates from between the two velocity vectors towards the center?
This videos are great! Thank u very much :)
Great videos thanks a lot.
hımm you have replaced old videos with new ones and these is quite good.but there is no upward throw motion, I hope you will add it thx :)... we generally encounter units from of (i,j,k) you know at university.
Sir, thank a billion again. I am having a problem with visualisation, as when you added vector v2 to v1 the direction is east and nit towards the center of the circle?
Note that v1 is subtracted (not added) from v2
@@MichelvanBiezen The drawing is wrong, Michael. Because the vectors have equal length the outcome can't be a horizontal line (2:01). Therefore, the difference-vector should be drawn at point 2 on the circle (pointing slightly downwards to the centre).
thank you very much Mr Michel
but i have a question:is the velocity is still perpendicular to the path in a curve motion?
if there any videos about that please tell me where it , because i need it very much
Amazing video sir! Thank you!
Thank you so much, really helpful!
I think v2-v1 is a resultant vector of v2 and v1 sir
Thankx lecturer but i have question about where minus sign in 4.9t2 is coming from
When using the equations of kinematics, left and down are negative directions. Since the acceleraion due to gravity acts downward, we place a negative sign in front of that.
Thank you for educating us
You're welcome 😊
sir bring a series of jee advanced 2023
Yes, we need to work on that. Thanks for the reminder.
Maybe a stupid question but if the acceleration is always to the center of curvature why do you experience a force opposed to the center of curvature when you take a sharp bend in a car for instance?
F = m a, so the force should have the same direction as the acceleration.
Duranium,
That is a very good question.
That "force" that you feel pushing you to the right when you make a sharp left turn is not really a force.
We call it the "centrifugal force", because it appears to be a force.
What is actually happening is that your body wants to obey Newton's first law and continue in a straight path motion. The car moves to the left (because the friction on the tires push the car to the left (centripetal force)), Your body wants to keeps going straight, but the seat belt pushes you to the left which your body interprets as being pushed to the right.
I think I understand what you mean with the centrifugal force not being a force. Because the observer is in a non inertial frame of reference this force appears to be a force. But when you look at the car from the side you'll notice that this force is a reaction force to the centripetal acceleration.
But I dont really understand the following thing:
"Your body wants to keeps going straight, but the seat belt pushes you to the left which your body interprets as being pushed to the right."
Do you mean that if there is a force on your body in a certain direction that you will interpret it in the opposite direction?
Thanks for your response by the way
Duranium
The seat belt provides the centripetal force by pushing towards the center of the circular motion.
You experience the sensation of being pushed into the seat belt. (because your body obeys Newton's first law
thanks it's clear to me now
interia
How can we prove that v2-v1 is perpendicular to circle
Its not obvious by diagram
If you use the definition of the derivative, dv/dt as dt approaches zero, v2 - v1 will be perpendicular to the circle. (See what happens when you make the angle smaller and smaller. )
really very great videos...
It's great ...
Glad you liked it.
What a min... The average acceleration formula is change in velocity over time and he just changed into sum of velocity over time????
The video is correct.
come teach at ISU lol cause the proffesors here are just collecting a paycheck. i leave stupider than i walk in
nice
you are a wonderful person with perfect bow ties i love you so much
Thanks!
He sounds like Gru from Despicable Me
Your video is so, so, so, so dark I have to assume that you work in some creepy basement and the other explanation would have to be that you don't have electric lighting despite the fact that it is the 21st century. From time to time you should watch your own videos and if you do you will understand why it is impossible to call the big board a white board instead we should call it a dark grey hard to see anything board. Would it kill you to turn on the background lights?
Yes, our earlier videos lacked the proper lighting. Something we learned and corrected along the way. Thanks for writing in.