Hi, I graduated high school three years ago, but did not take math beyond grade 11 college as other things got in the way and I wanted to finish easily. Since August, I have decided to back to adult school to upgrade credits and go to university for computer science and/or math. Six months ago, I was in a position where I had forgotten how to add fractions and basic high school math curriculum. I always had an interest in math and learning it so that I can try and help teach others. I'm also really pleased that I have been able to learn so much over the last 6 months, and your videos are one of my most valuable resources. I recommended the videos to my class as well, so hopefully they can use it too.
Well, isn't that a lovely note for me to read today! For some unknown reason it was in a folder called "likely spam" which I have just discovered. This is in NO way spam. I am so proud of you for getting back into studying mathematics and SO happy that I have been able to be a good resource for you. Keep it up! and thanks for recommending me to your colleagues.
Hello again Ms Havrot! These practice tests help so much so Thank you! I was able to get a 95% on my chapter 1 test with the help of your videos and im hoping for a similar outcome tomorrow with my chapter 2 test. Your videos are the best and we as a community honestly cannot thank you enough! Cairine Wilson was very lucky to have had you and all of us here at St Peter are very grateful for this channel!
Professor Havrot's, thank you for an excellent Chapter Two Practice Test in Calculus One. The problems on the Practice Test outline all the Derivative Rules in Calculus and how to use them in different cases. As a former Electrical Engineering student at the University of Maryland College Park, in the early 1990's, every course from year one and two at the Community College to year three and four at the University of Maryland uses Calculus. This is an error free video on UA-cam.
Hi Ms.Havrot, I just wanted to say your videos have been extremely helpful. Calculus is a pretty tough course for me and your channel has been the most valuable resource for navigating this course and I literally cannot stress enough how much my math improved with the assistance of your videos. You are truly great at teaching . Thanks a ton!
Can't thank you more than enough! I can't afford a tutor, so this has been so great for me while im studying. Your explanations are very detailed and easy to understand, better than my own teacher!! Just wanted to share a message of appreciation as a student of yours.
You are exactly the reason for my channel. I hoped to reach students such as yourself who needed this kind of help. Tutors are very expensive and math help, for those who want to learn, should be readily accessible. Thanks for your comment and I wish you all the success you deserve and a scholarship to keep you learning ❤️
I certainly hope that I’ve helped others pass and do better than they would have without watching it but I lay no claim to anyone’s success. It all up to you! 😊
Hey Miss Havrot, I have a bit of an off topic question, but would you reccomand taking a private school if you are in grade 12 for physics( obviously you teach math so maybe unrelated) But I am just asking you for general advice .
Do you mean going to a private school for your grade 12? I’m sure there are some private schools that purport to have better teachers than the public schools but I have taught many students who have had amazing success in all fields (doctors, nurses, musicians, physicists, accountants etc) who didn’t “waste” money in private schools. Better to save your money for university, work hard in high school and get the grades to receive scholarship money. (My personal opinion, obviously)
@shalinisapra2400 No as you approach the y axis your ruler would have to be turning to reach zero slope. There is a point (called an inflection point) where there is a change in direction and that is where I am showing you the slope is the steepest. It’s a point where the graph goes from being concave up to concave down (or vice versa). Hope this helps. Remember that this is just an approximation of the slope.
Thanks for this (I'm trying to refresh my aging calculus brain and your videos are exceptional)! I noticed in 14:45 - 15:10 you scrubbed the calculation with the "original" equation and went to use the second equation. However, since you were calculating their intersection point, either method would work correctly and give you the same result.
At that point I was trying to find the y coordinate. The equation that I scrubbed was the derivative and that would have given me zero. So, I needed to use the function where the tangent was touching the curve in question.
@@mshavrotscanadianuniversit6234 f(x) = x^2 - 8x + 14 was the original function I think. It gives f(-1) = 7, just as -(-1)^2 - 4(-1) + 4 also equals 7. Am I seeing it incorrectly? Thanks for all this great material!
3:25 for the derivative of the equation, why didn't you to the derivative for (5x-3)? Aren't you supposed to find the derivative for that and then write out g prime then do vice versa for the next part?
Hi,
I graduated high school three years ago, but did not take math beyond grade 11 college as other things got in the way and I wanted to finish easily. Since August, I have decided to back to adult school to upgrade credits and go to university for computer science and/or math. Six months ago, I was in a position where I had forgotten how to add fractions and basic high school math curriculum. I always had an interest in math and learning it so that I can try and help teach others. I'm also really pleased that I have been able to learn so much over the last 6 months, and your videos are one of my most valuable resources. I recommended the videos to my class as well, so hopefully they can use it too.
Well, isn't that a lovely note for me to read today! For some unknown reason it was in a folder called "likely spam" which I have just discovered. This is in NO way spam. I am so proud of you for getting back into studying mathematics and SO happy that I have been able to be a good resource for you. Keep it up! and thanks for recommending me to your colleagues.
Hello again Ms Havrot! These practice tests help so much so Thank you! I was able to get a 95% on my chapter 1 test with the help of your videos and im hoping for a similar outcome tomorrow with my chapter 2 test. Your videos are the best and we as a community honestly cannot thank you enough! Cairine Wilson was very lucky to have had you and all of us here at St Peter are very grateful for this channel!
How sweet of you to comment. I’ll sleep well tonight with this wonderful thank you note on my mind ❤️ Good luck tomorrow!
Professor Havrot's, thank you for an excellent Chapter Two Practice Test in Calculus One. The problems on the Practice Test outline all the Derivative Rules in Calculus and how to use them in different cases. As a former Electrical Engineering student at the University of Maryland College Park, in the early 1990's, every course from year one and two at the Community College to year three and four at the University of Maryland uses Calculus. This is an error free video on UA-cam.
Hi Ms.Havrot, I just wanted to say your videos have been extremely helpful. Calculus is a pretty tough course for me and your channel has been the most valuable resource for navigating this course and I literally cannot stress enough how much my math improved with the assistance of your videos. You are truly great at teaching . Thanks a ton!
That’s wonderful to hear ❤️
This is exactly what I needed!!!! I have a test on this tomorrow
aha same loll
There's a practice test for every chapter ... enjoy!
How did you do on it?
@@mahathirmohammed6986 How did you do?
Can't thank you more than enough! I can't afford a tutor, so this has been so great for me while im studying. Your explanations are very detailed and easy to understand, better than my own teacher!! Just wanted to share a message of appreciation as a student of yours.
You are exactly the reason for my channel. I hoped to reach students such as yourself who needed this kind of help. Tutors are very expensive and math help, for those who want to learn, should be readily accessible. Thanks for your comment and I wish you all the success you deserve and a scholarship to keep you learning ❤️
exactly what I needed, I have a test on this next week
Excellent! I was thinking you would be ready. 😊
How did you do?
This was four years ago. I’m sure this person would be graduating from university this year.
@@mshavrotscanadianuniversit6234 Yes I understand, but who knows what if they remembered how it went? Thanks for responding Ms. Havrot!
Thank you so much for your video! :) I have a quiz and test in a week and your videos help me a lot
So you're telling me that, if not for this video over two thousand people would've failed their calculus test!!!
I certainly hope that I’ve helped others pass and do better than they would have without watching it but I lay no claim to anyone’s success. It all up to you! 😊
Hey Miss Havrot, I have a bit of an off topic question, but would you reccomand taking a private school if you are in grade 12 for physics( obviously you teach math so maybe unrelated) But I am just asking you for general advice .
Do you mean going to a private school for your grade 12?
I’m sure there are some private schools that purport to have better teachers than the public schools but I have taught many students who have had amazing success in all fields (doctors, nurses, musicians, physicists, accountants etc) who didn’t “waste” money in private schools. Better to save your money for university, work hard in high school and get the grades to receive scholarship money. (My personal opinion, obviously)
I didn't get question 2 . How did you get the slope for both graphs ? Slope zero is easy to find ,but how to find for other point using ruler?
Im simply approximating the slope so that I can sketch the derivative function.
Thank you so much for your reply. Is there any other way to sketch . Because to find slope using ruler is tricky .
Because for the second part, I feel the steepest is when we are very, very near to the y axis .
@shalinisapra2400 No as you approach the y axis your ruler would have to be turning to reach zero slope. There is a point (called an inflection point) where there is a change in direction and that is where I am showing you the slope is the steepest. It’s a point where the graph goes from being concave up to concave down (or vice versa). Hope this helps. Remember that this is just an approximation of the slope.
Thanks for this (I'm trying to refresh my aging calculus brain and your videos are exceptional)!
I noticed in 14:45 - 15:10 you scrubbed the calculation with the "original" equation and went to use the second equation. However, since you were calculating their intersection point, either method would work correctly and give you the same result.
Thank you! Enjoy!!
At that point I was trying to find the y coordinate. The equation that I scrubbed was the derivative and that would have given me zero. So, I needed to use the function where the tangent was touching the curve in question.
@@mshavrotscanadianuniversit6234 f(x) = x^2 - 8x + 14 was the original function I think. It gives f(-1) = 7, just as -(-1)^2 - 4(-1) + 4 also equals 7. Am I seeing it incorrectly?
Thanks for all this great material!
@@stevelarocque f(-1) = (-1)^2 - 8(-1) +14 But we want to know where this tangent touches the 2nd curve. f(x) = - x^2 - 4x + 4
= 1 + 8 + 14
= 23
As Homer says, "Doh!" Thanks!
Thank you, Ms Havrot!!!!
At 32:00 what happened to the 2 squared next to the first function
Keep watching as I do correct that at 32:05
Oh I see thank you@@mshavrot_math
3:25 for the derivative of the equation, why didn't you to the derivative for (5x-3)? Aren't you supposed to find the derivative for that and then write out g prime then do vice versa for the next part?
since isn't it f(prime) g(x) + f(x) g(prime)?
You can do it in either order. I always do the first times the derivative of the second plus the second times the derivative of the first.
thank you very much!!
You’re most welcome!
thank you! i was having so much trouble with #6, until i realized i wrote f'(x)=3ax+b and not f'(x)=3ax^2+b. oops!
Most homework errors are simply copying mistakes. (That and negative signs!) 😊
thanks miss
So happy to have helped you understand. Please tell all your friends and share my link so others can join in on the “fun”! 😊
Thank you so much!!! I love you so much!!!It would be great if you were my wife and teacher!!!
Well, my partner would be very unhappy if I left him, but I’d be happy to be your teacher 🤣