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This is for Question 3 part 2. My approach was to find the gradient as they both shared a common point X which is the speed. For the Gradient of the line from 62-48 Seconds I got the coordinates (48, 12.6) and (62,X). Then for the Gradient of the line from 70-62 I got the coordinates (62,X) and (70,0). Then I put the gradient of the first line equal to Two times the gradient of the second line. Getting a value of a=-0.7. Can anyone explain why we cannot use this approach?
you should multiply the gradient of first line by 2 and equate it with the gradient of second line as the second line's gradient is two times the first lines's so if we multiply the gradient of first line by 2 then it will equal to the gradient of second line
why do we have to take deceleration as negative, is it not only the case when its freefall as when its going up a is negative and when the object is coming down a is positive?
We take acceleration as negative when body becomes slow down. In 3rd question there is a cofficient of friction between plane and particle which means plane is rough and particle is going to be slow down
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the goat is backk
can't we use gradient to find a in 3(b)?
This is for Question 3 part 2.
My approach was to find the gradient as they both shared a common point X which is the speed.
For the Gradient of the line from 62-48 Seconds I got the coordinates (48, 12.6) and (62,X). Then for the Gradient of the line from 70-62 I got the coordinates (62,X) and (70,0).
Then I put the gradient of the first line equal to Two times the gradient of the second line. Getting a value of a=-0.7. Can anyone explain why we cannot use this approach?
you should multiply the gradient of first line by 2 and equate it with the gradient of second line
as the second line's gradient is two times the first lines's
so if we multiply the gradient of first line by 2 then it will equal to the gradient of second line
thanks sir! very helpful
Most welcome!
why do we have to take deceleration as negative, is it not only the case when its freefall as when its going up a is negative and when the object is coming down a is positive?
We take acceleration as negative when body becomes slow down. In 3rd question there is a cofficient of friction between plane and particle which means plane is rough and particle is going to be slow down
in question 6b dont we get 2 different values of v, as we have the quadratic equation
Speed has no direction so therefore it cant be - im pretty sure
@@hairlesssheep2805 i noticed few hours after the comment, but thank you anyways
Sir would it be possible for you to solve physics paper 52 of Oct nov 2023, since the Feb mar series exam date for 9702/52 is on the 16th(friday)
I will try!
Hi unrelated but is the DI method allowed for integration in p3?
no only by parts I think
Sir please do v43
Soon!
dude just copy-pastes the MS and then tells it again