For personal revesion W=ZQ where w is mass and Z = equivalent weight = molarmass/n factor Erp(value) prop...= oxidising agent = 1/reducing agent 9:07 W=zq formula 10:24 carefully 11:22 electrolysis 18:30 theory cell 24:10 theory 27:35 carefully 30:06 theory 37:34 carefully 40:41 electrolysis 47:41 electrolysis comparission 48:32theory salt bridge 51:46 properties of salt briudge
no ...jiska jada reduction potential hoga wo jada jldi reduce hoga aur jo jada jladi reduce hoga wo dusre ko utna hi jldi oxidise karega therefoe jada acha oxidising agent hoga
Here, I added reduction potential and oxidation potential. Your formula works when reduction potential for both cathode and anode is used. I hope you got the idea.
@@AveshChemistry_ Ohh! Standard Oxidation potential diya hua hai, aur Standard Reduction Potential (SRP) = Standard Electrode Potential (SEP), Isiliye 0.76 ki jagah -0.76 liya. I got it, Thanks a lot!!
sir i think there is a small mistake at 46:30 min they said strongest reducing agent and in the answers they gave us the products of the above given rections so for the products the srp values sign will be reversed so the answer will be option d correct me if i am wrong anyway you are awesome sir
Strongest reducing agent → High affinity of species to loss electron THUS , Sign of electrodes potential accordingly becomes opposite , now Zn(s) highest affinity to loose electron and hence is strongest reducing agent
@Akhauri Kshitiz , @Priya soni -- No. Actually since electrons participating in both half cells are same i.e., 2, we can add them directly. --> E o (Cell) = [2 × Eo (Zn) +2 × Eo (Fe) ] ÷ 2 --> E o (Cell) = Eo (Zn) +Eo (Fe) I hope you both got the idea. Actually when electrons participating are different then we may not add them directly.
this seems gold mine,thanks a lot sir!!plz dont stop uploading content ,dk why the channel isnt growing but let me assure u this is the best thing ii have seen of youutbe on chemistry thanks a lot!!!
Sir I have one doubt in the question. Dilute aq Nacl is given soo in anode OH is oxidises in that case it is exceptional but you can say that Cl- is oxidises . At 15:50
Sir aise video dalte rahiye, thank you sir very much ,abhi views nahi ayenge ,but bad me jarroor views ayenge, continue this upload of previous year question
Yaar dusre channel pe faltu chez padhaye zaati hey tabhi 100- 150 k subscriber hote hey. Haha yitna Aache terh se sir explain karte hey lekin tabhi subscribe Nahi karta channel no Jan se Jan 1m tho hone chaheye Yaar Sab log do subscribe please very quality content is there
Aaj ionic equilibrium ka upload ho jaaega, then polymer ka chapter (NEET - helpful for her mains also), then electrochemistry part 2 for sure. You can join my telegram group also - t.me/Avesh_Chemistry
1 g eq is weight/eq weight .. thought question can b solved but is there any conceptual mistake you have made in prob 2 based on faraday law? i certain you have given wrong definition of g eq wt . do reply me.
Hidden gem💎
Kitna aacha padhate ho😊
0:36adv ,7:00,10:24 c,12:15,18:24 c,24:10 imp c,26:40 repeat,27:26 c,30:12 imp c+good q,37:30 imp c,40:28 imp c,42:29 imp,40:44good ques,43:49 imp c,46:47repeat,48:28 imp c,51:52 c
For personal revesion
W=ZQ where w is mass and Z = equivalent weight = molarmass/n factor
Erp(value) prop...= oxidising agent = 1/reducing agent
9:07 W=zq formula
10:24 carefully
11:22 electrolysis
18:30 theory cell
24:10 theory
27:35 carefully
30:06 theory
37:34 carefully
40:41 electrolysis
47:41 electrolysis comparission
48:32theory salt bridge
51:46 properties of salt briudge
35:36
40:28
52:43
28:29
23:08
14:50
8:53
42:44
14:51
8:53
21:41 43:16
When is ur shift?
29:47 answer should be a as in the question srp is given and formula is E = e cathode - e anode
B is correct 💯
Kuch logo ka ahsan bhot bhada hota h
Ty sir
40:14 question repeated in 8 april shift 1 2023
20:46 :-
30:30
16:00
Thanku sir ❤❤❤
sir bohot accha phadaya thank u :)
Best teacher sir ji very nice ❤❤
what a brillinat teacher u are,i usually dont comment but hope this boosts algorithm
Sir please 2022 solu upload kardo electrochemistry and thermodynamics 🙏🙏🙏
@29:48 answer should be (D) as cathode - anode should be taken
Option b hi hoga . Fe reduce ho raha hae . Zn oxidise. Cathode-anode. Fe-zn .
10:48 ans should be A na
Sir ne shi kiya h ans should be d
11:22
25:45 sir jiska jyda reduction potential hota h vo good reducing agent h so vo dusro ko reduce krga naki oxidise so uska answer b hona chaiya
No good oxidizing agent
Exactly.
no ...jiska jada reduction potential hoga wo jada jldi reduce hoga aur jo jada jladi reduce hoga wo dusre ko utna hi jldi oxidise karega therefoe jada acha oxidising agent hoga
sir u r best
THANK YOU SO MUCH SIR
Plz keep uploading 🙏
just know that you are much better and more dedicated than the other educational channels ..this is whats called a real crash course
At 43:35...
Sir i think answer is d as increasing order asked
ya bro i also doubt that
sir bhot zada thank you
29:48 Par sir E°cell=E°cathode-E°anode hoti haina??
Aapne yahan plus kaise kiya??
Smjh nhi aaya mujhe
Plz help 🙏🙏
Oxidation potential me addition hota he
29:44 sir yahan par Eo of cell Eo cathode -Eo anode hoga na to iske hisab se to D option hona chahiye
At 29:33 E (cell) = E (cathode) - E (anode). Toh phir apne add kyun kiya?
Here, I added reduction potential and oxidation potential.
Your formula works when reduction potential for both cathode and anode is used.
I hope you got the idea.
@@AveshChemistry_ Ohh! Standard Oxidation potential diya hua hai, aur Standard Reduction Potential (SRP) = Standard Electrode Potential (SEP), Isiliye 0.76 ki jagah -0.76 liya.
I got it, Thanks a lot!!
Revise 11:52
23:14
❤❤
It really good sir
THE BEST CHANNEL
Aapka koi jawab nhi sir ji ...............................
sir i think there is a small mistake at 46:30 min they said strongest reducing agent and in the answers they gave us the products of the above given rections so for the products the srp values sign will be reversed so the answer will be option d
correct me if i am wrong
anyway you are awesome sir
Strongest reducing agent → High affinity of species to loss electron
THUS , Sign of electrodes potential accordingly becomes opposite , now Zn(s) highest affinity to loose electron and hence is strongest reducing agent
Sir Eo is not additive so how can we add it 29:00.
@Akhauri Kshitiz , @Priya soni --
No. Actually since electrons participating in both half cells are same i.e., 2, we can add them directly.
--> E o (Cell) = [2 × Eo (Zn) +2 × Eo (Fe) ] ÷ 2
--> E o (Cell) = Eo (Zn) +Eo (Fe)
I hope you both got the idea. Actually when electrons participating are different then we may not add them directly.
Sir please chemical equilibrium
Yes sir please
I am saying this again - you are amazing and I love you so much sir.
Respect.
Yes. Me too
@@satyayadav4111 me too sir
Thankyou so much 💕 Sir🙏
Sir 46:40 p and d) hoga kuli zn2+ h hamamra acha reducing agent naki zn
Ha bro m bhi yhi soch rha hu
really what a teaching ur dedication will be literally coming up with bright colours.
Tx a milion sir mere concept clear krne ke liye
🤗🤗😇🤗😇🤗😇
Best video sir 😃😃😀😀🙂🙂🙂🙂🙂
this seems gold mine,thanks a lot sir!!plz dont stop uploading content ,dk why the channel isnt growing but let me assure u this is the best thing ii have seen of youutbe on chemistry thanks a lot!!!
29:14 sir e red to pehle hi diya hai. - to shayad nahi lgana tha
Bahut accha h sir...
Great explanation sir ch b revise ho gya or practice b Thanx sir
more than enough....awesome
I hope your channel gets really famous after my jee exam 😀
your channel will sure achieve new heights very soon because of this quality content.
Sir I have one doubt in the question. Dilute aq Nacl is given soo in anode OH is oxidises in that case it is exceptional but you can say that Cl- is oxidises . At 15:50
Ek batt yaad kr lo jab nacl fuse hoga toh anode pr Na or cathode pr Cl jayegaa
Aur jab aq nacl hogaa toh anode pr H2O aur cathode pr Cl jayegaa
Aur jab nacl dil aq ho toh anode pr H20 and cathode pr bhi H2O jayega
reaction krnee....
💕
Atomic structure plz part 2
Sure.
Sir aise video dalte rahiye, thank you sir very much ,abhi views nahi ayenge ,but bad me jarroor views ayenge, continue this upload of previous year question
Tq sir it is very useful 🙏
This channel's gonna rise much more in the upcoming years. It's really very helpful. Thank you for this series Sir :))
Thanku sir ji............🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Awesome sauce style of teaching
Vry nyc explanation
Superrrrrr
Sir aap mahan hain
great sir u explain questions greatil
Thank u a lot sir❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️
sir itna detail me batate hain bht acche se pardhate hain. sir please NEET series bhi bana dijiye please
Guys share this channel as much as u can....
Thank u sir🙏🙏😊😊
sir plz equilibrium par bhi video bana dijiyega🙏🙏🙏
Next will be from equilibrium only.
@@AveshChemistry_ thank u sir🙏🙏🙏
cannot thank you enough sir!
In Q1 why 1 bar is not converted to Pa?
15:59...ye mere liye lagaya h maine abhi padha nhi tha isme kuch galat nhi h
Sir 46:45 pr Jo ques h uska Cr hona chaiya na ans?
-0.762 chota hai -0.740 se so sir ka answer correct hai
pleasw take more number of questions
Thank you very much sir.......it is really very very helpful vedio.....🙏🙏
THANK YOU SO MUCH ❤💜
Sir you are amazing it’s a time when we need someone to explain the importance of PGA’s
Sir your teaching level is just amazing. Thankyou so much sir .
Keep making this series sir❤️it's really helpful ❤️
Thank you so much sir 🙏🔥
Sir please make new videos
Did all correct except the salt bridge question
thankyou sir this helped a lot
Great work sir
Best way to learn
12:32 sir dilute nacl m anode m cl- nhi OH-lete h aapne conc. Nacl vala bta dia.. Also dilute m nacl act as catalyst..
Yaar dusre channel pe faltu chez padhaye zaati hey tabhi 100- 150 k subscriber hote hey. Haha yitna Aache terh se sir explain karte hey lekin tabhi subscribe Nahi karta channel no Jan se Jan 1m tho hone chaheye Yaar Sab log do subscribe please very quality content is there
Amazing explanation sir
SIR PLEASE COMPLETE EVERY PLAYLIST, I SAW ALL VIDEOS BUT THERE ARE SOME PARTS LEFT 😱😔
did you use it ?
@@rahulshendre7089 I made a video for in this channel so watch that
@@devesharya5184 ??
@@rahulshendre7089 check videos in his playlist
@@devesharya5184 alright, Thank you
i love this nigga!!!
Sir part 2 kb aaega iska????
Aaj ionic equilibrium ka upload ho jaaega, then polymer ka chapter (NEET - helpful for her mains also), then electrochemistry part 2 for sure.
You can join my telegram group also - t.me/Avesh_Chemistry
Thanks sir
1 g eq is weight/eq weight .. thought question can b solved but is there any conceptual mistake you have made in prob 2 based on faraday law? i certain you have given wrong definition of g eq wt . do reply me.
Sir are all questions covered?
amazingly brilliantly explained
to the point and very genuine content ...thank you sir
This is one of the channel where I like the video before it even starts
Sir ye sare questions arihant ke 41 year ke iit jee book mein hai. Book by~Ranjeet shahi
Sr can you please share the question PDF in description
Sir please next part krdiyee jiye uploads ..yeh wlaaa m maaza aa gyaa
sir i am not able to solve ionic and electro problems even after studying them twice what should i do?
leave study and open watermelon tthela, i will also join you, we would be rich 😁
Sir please mujhe apse advanced ke liye padhna hai
Please add 240 p quality also