Lecture07: Impedance Matching with the Smith Chart

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  • Опубліковано 10 січ 2025

КОМЕНТАРІ • 49

  • @nax1807
    @nax1807 4 місяці тому +4

    this channel helped me so much 2 years ago for my HF engineering module learning and applying smith charts to solve impedance matching network problems, thank you so much!

  • @cbarker1496
    @cbarker1496 8 місяців тому +2

    The step by step theory & math calculations directly identify the value of the required physical electronic components. This presentation of the circuit diagram & Smithchart effects genuinely helped my better understand the physics theory AND practical use of a Smithchart. Thank you !

  • @therealtimwarren
    @therealtimwarren 3 роки тому +6

    Thank you for this video! It has cleared up a lot of confusion for me. Very well explained.

  • @ravichandransrinivasan5453
    @ravichandransrinivasan5453 Рік тому

    Very good explanation.Must watch several times and commit to memory.Thanks.

  • @healthbabe2691
    @healthbabe2691 3 роки тому +2

    Hi Dr. Peik. Thanks for all your lectures with many examples in great details.

  • @goofypettiger
    @goofypettiger 3 роки тому +2

    Exceptionally clear and useful. Thank you.

  • @amiltonmanuelpensamento9832
    @amiltonmanuelpensamento9832 2 роки тому +2

    Thank you for explaining! I would like to see how you workout these problems in the non-ZY Smith Chart

  • @user-sajool
    @user-sajool Рік тому

    thank you prof. From Polimi with all my respect :)

  • @PTNLemay
    @PTNLemay 3 роки тому +2

    9:00
    How do you find the values of admittance? I thought admittance was the inverse of the impedance. So wouldn't the admittance be either 1/100 or 1/50, how did you get 0.25?

  • @leot7176
    @leot7176 2 роки тому

    This video is so helpful, you are my hero!!!

  • @maksymkloka7819
    @maksymkloka7819 2 роки тому +1

    Clarified a ton. Great video.

  • @winstonalf
    @winstonalf 4 роки тому +4

    Thank you for this. Please tell me how to convert Z value to actual capacitance and inductance.. for example: 10pF or 1.5nH

  • @diarylee147
    @diarylee147 10 місяців тому

    Thank you so much for this wonderful video..

  • @theodumbrovsky3239
    @theodumbrovsky3239 3 роки тому

    Great explanation! Really clear to comprehend!
    Tks

  • @mustaphaalkhafaaf5512
    @mustaphaalkhafaaf5512 3 роки тому +2

    Thank you Prof Peik , The more brilliant talented people I see who can explain things
    the more I realise how rubbish lecturers are at most of the universities who
    only care about the researches they do and their pockets

  • @jorgerive7335
    @jorgerive7335 4 роки тому +1

    very good explanation. Thank you

  • @ВалентинФаворов

    Danke scho``n fu``r seine Videolektion, es hat mir sehr geholfen!
    von seine russisch Studenten💙

  • @DMain-tb8ye
    @DMain-tb8ye 3 роки тому +1

    Hard to follow when split view is on because I can not see the cursor and where he is pointing.

  • @renatodias1804
    @renatodias1804 10 місяців тому

    Very well explained!

  • @PatAutrey
    @PatAutrey Рік тому

    on the feedlines - are you using the velocity factor when making these calculations?

  • @albinfetahu6411
    @albinfetahu6411 3 роки тому

    This video was helpful. Could you please add in description this smith chart please?

  • @hamidk4772
    @hamidk4772 4 роки тому +1

    Excellent 👌👌👍👍👍

  • @user-su5sq5ib3i
    @user-su5sq5ib3i 2 роки тому

    When you require high current you would always want series L and shunt C ?

  • @victorb22622
    @victorb22622 Рік тому

    Sir is there any simulator to find the matching stub value?

  • @abfig78
    @abfig78 3 роки тому

    So I'm reading about attenuators and they say that sometimes they will use a low value to help with impedance mismatch.
    So in ham radio, let's say my iCom 2m radio. Do they use one on the inside at all? Or is it simply up to using the proper antenna? Or probably there is some kind of matching circuit built in that is working for/with the proper antenna.
    Idk. Just neat stuff. :)

  • @BdFln_uzilya
    @BdFln_uzilya 6 місяців тому

    Danke Sören 👍🏼

  • @victorb22622
    @victorb22622 Рік тому

    Nicely described .for me ,it's 75:25 percent.i have to watch again.i guess from your teaching style that your are professor at college.so you might be doing/teaching student frequently.but, for student(age no bar to learn) like me it's tough to go with you. 😀,So, i must watch again.i came here ,because i have made SlimJim VHF antenna ,and want to tune it, but here you teach about transmission line impedance matching.so, coud you please simplify my case.

  • @mehmetfurkanay9580
    @mehmetfurkanay9580 4 роки тому

    Thank you very much for this lecture.

  • @fenghc1
    @fenghc1 4 роки тому +2

    Lecture 8, please. Thank you very much!

    • @dariuskasen9229
      @dariuskasen9229 3 роки тому

      i realize I'm quite off topic but do anyone know a good place to stream newly released tv shows online?

    • @scottomari1468
      @scottomari1468 3 роки тому

      @Darius Kasen Lately I have been using flixzone. Just search on google for it =)

    • @philipjeremias451
      @philipjeremias451 3 роки тому

      @Scott Omari Yea, I've been using FlixZone for years myself :)

    • @dariuskasen9229
      @dariuskasen9229 3 роки тому

      @Scott Omari Thank you, I signed up and it seems like they got a lot of movies there :) Appreciate it !!

    • @scottomari1468
      @scottomari1468 3 роки тому

      @Darius Kasen happy to help :D

  • @wridhdhisomkarar1633
    @wridhdhisomkarar1633 4 роки тому +2

    Where is lecture 8 ??? Please upload lecture 8

  • @aaronvanrossum2079
    @aaronvanrossum2079 4 роки тому

    Wait aren't the full circles a constant r and the other curves constant x

  • @MrApolloTom
    @MrApolloTom 4 роки тому

    How bad would it be to use resistors, compared to leaving things unmatched?

    • @microwavelabcast2174
      @microwavelabcast2174  4 роки тому +1

      Resistors may be an option. A resistor will match the amplfier, however, it introduces losses. The resistor match will not result in a higher gain as desired. Moreover, resistors add noise to the amplifier.

  • @bou2222
    @bou2222 2 роки тому +1

    Thank you!

  • @טלשוסטרמן
    @טלשוסטרמן 3 роки тому

    hello , can someone please tell me how relevant is this job on the market ? , when I write micro wave engineer in linkedin i do not find many job applications maybe there is a different name to this ?

    • @saintfather7757
      @saintfather7757 3 роки тому +2

      Unfortunately, there are no many jobs in this field.

  • @mehmetdemir5655
    @mehmetdemir5655 2 роки тому +1

    Smiss chart☺️☺️

  • @gauravphalke5311
    @gauravphalke5311 4 роки тому

    22:32

  • @mohamedalzawam
    @mohamedalzawam 2 роки тому

    thanks

  • @MinMax-kc8uj
    @MinMax-kc8uj 9 місяців тому

    Looks a lot like quantum physics to me.

    • @pendalink
      @pendalink 3 місяці тому

      it's nicely geometric in a related way. there's a clifford algebra description of transmission lines where transformations on the smith chart have some riemann sphere/mobius transformation description. or something like that; it's just worth looking up

    • @MinMax-kc8uj
      @MinMax-kc8uj 3 місяці тому

      @@pendalink The Mobius Transformation looks a lot like tangent addition. Then again, the standardization of tangent addition might be wrong, The nature of 'i' in hyperbolic and regular trig might have confused some people a long time ago. Maybe the odd functions (sin and tan) should include the 'i'. But it's fine the way it is. If we want to do hyperbolic geometry, we can just include a negative 'i' in the inverse arc functions. Most people are unaware of the issue, and this might cause them some confusion down the road.