MUX Tree Basic | 4X1 MUX using 2X1 MUX | Easy Explanation

Digital Electronics: MUX Tree Basic | 4X1 MUX using 2X1 MUX | Easy Explanation
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[@hajsoufi9007]

as a moroccan,for me
the indians always the best in all the sciences (programmation,electronic,math...)

[@RahulMadhavan]

02:21 number of 2x1 mux needed to produce 2^n x 1 mux is (2^n -1) because 2^n/2 + 2^n/4 + 2^n/8 + 2^n/16 + ... = 1 + 2 + 4 + ...2^(n-1) =( 2^n - 1) / (2-1) = ( 2^n - 1).
So to produce 16:1 mux 15 2:1 mux needed, or to produce 4:1 mux 3 2:1 mux needed.

[@obelix_gaul]

very nice of you to explain which was the previous video and which will be the next one, it helps a lot along with the content of the videos, thanks a lot..

[@adityasagar9078]

what were u and where are u now after 5 years?

[@sagar19here]

sir apki job kaise chal rahi h ?

[@Aminakzyzz]

how is life right now G

[@Aminakzyzz]

@@adityasagar9078 how is life now G

[@adityasagar9078]

@@Aminakzyzz since last year nothing much has changed, all fine till now

[@konoharesider5058]

Thanks a lot! You did a great job!

[@negi7735]

Thanx a lot from the bottom of my heart for providing very nice explanations on all topics of digital electronics👍👍

[@jordanramsey7213]

Very good explanation. One small mistake. Its does matter where s1 and s0 go. This Mux would not work with s1 being the first selector used

[@prathmeshkherade7739]

Great channel..!!
Easy to understand.
Doing great work.
Keep it up..

[@hindustanimapper]

How r u after 7 years?

[@prayasnayak7136]

What are you doing broo

[@varadgaming3403]

Jobless May Be So Not Replying 😢​@@prayasnayak7136

[@stable577]

5:00 (Way to determine the select line)

[@iK-7_7]

2nd year anyone 😊

[@kunjavyas7425]

May be one day I will owe my degree to you people😄😄

[@swingstockstrader]

Can you get your degree now.. what are you doing now. 😁

[@kasoneduardo1634]

Instablaster

[@soulfulhuman8724]

What are u doing now? Plz tell me, I wanna know the spoilers for future???
I am in btech 2nd year??

[@khairulislam237]

what are you doing nowwww??

[@UsmanAli-hs8cr]

InshAllah i will take degree in IT from my university

[@subhashchandra2357]

Sir why you took i2 in second multiplexer for {0 select line}.

[@NitishKumar-sd9lg]

Any one in 4th semester

[@princeofdisney230]

Here

[@mihirvora391]

3rd sem diploma in CSE

[@dragonbeats66]

Yes

[@asogwauchenna4081]

Thank you so much for all these teachings, it helps me alot.

[@saraljoshi2495]

This was really helpful, but could you please explain or give reference to why 4/2=2, and 2/1=1 rule works to get the arrangement and number of muxes required?

[@davebacknolaliki1452]

Late reply but may be useful for others. Building it with a 4x1 mux out of 2x1 mux we only have 2 inputs to work with so since we need 4 we divide it by 2. We got the 4 inputs as required right? Well since they’re 2x1 we are getting 2 outputs. But we need a 4x1 mux. If we used only the 2 we would have a 4x2 mux technically. So we divide it by 2 again. We have 1 we are reducing the outputs at each “stage” I guess you could call it until we get to our desired single output. That’s how I think of it at least.

[@ragasudhan1570]

IT was a such a sweet explanation,tq

[@avlav9682]

I need help with MUX and subtractor..I know how to make 1-bit full subtractor with using two mux 4/1, but how to make 4-bit subtr. using those muxes? You are doing great job..very useful channel :)

[@sarthakchoudhury5237]

Only mux mux

[@SujeetKumar-hj4nc]

very good explain i blindly follow it,thanks alot for providing this service

[@BrwaKurdish]

Sujeet Kumar No, i don’t think you should blindly follow anyone, whoever they may be.

[@biniyam05]

Bro tnx very much it help me alot 📍

[@faichalayeva3677]

Thank you sincerely.

[@ganeshchincholkar4331]

Very good and quick tutorial and it would be more nice if the noise in the background of the video is eliminated.

[@Ravi_477]

Always the best platform 🔥

[@info-king]

Thanks bro in my exam time it helped me a lot

[@qtSoph]

you have helped me so much. thank you

[@amanrai6402]

very easy to understand...! thanks alot for this all video...!

[@EjazHazari]

sir i love u your explaination is very awesome

[@shubhamparashar6077]

Sir please can u make the lectures on power electronics... It's a highly obliged request sir
In future I will contribute this for sure. Thank you

[@nagashreey.gy.g5802]

Thanks a lot!!! great explanation..

[@markarthur1083]

5:29 why must both have same selection?

[@srikantakumargouda9561]

You are great sir

[@veekshithrgowdavicky9669]

Superb sir……..fantastic

[@nehashahi7667]

Very nice explanation

[@joaopedro-wv8kp]

Why the select line for first and second MUX must be the same? I saw this question three times on the comment section, I think that is a common question between us

[@manemmaearli4832]

Thank you so much sir

[@mahadevhatti5228]

5:15 DOOR OPENED LOL

[@swapnilrai809]

awesome explanation

[@adityasagar9078]

what were u and where are u now after 5 years?

[@c.m.8146]

thank you so much! your videos are a huge help

[@abhishekchatterjee7789]

Very helpful thanks sir

[@thakermahek2501]

Great content nd teaching skill👌🙌

[@zainabahmed6382]

Ahhhhh why didnt my sir ever tell us that hack for muxes required! 🙄💯

[@UECAshutoshKumar]

Thank you sir

[@mathumitharajan4074]

5:31 , why should that both 2x1 multiplexers have the same select lines?

[@dhanvinprajapati7049]

because we only need four possible combinations of (s0)(s1). 2^2 = 4

[@xiaofeng5559]

can anyone explain how to take selection line i'm pretty confused......

[@pranav288]

if there are 2 inputs, then 1 select line (since 2 to the power 1 is 2 ). If if there are 4 inputs, then 2 select lines (since 2 to the power 2 is 4 ), 3 lines for 8 inputs(2 to the power 3 is 8) , 4 for 16 inputs and so on.. just think what should be the power of 2 so it matches the number of input lines

[@z2173-i2f]

Since it's binary we can make one of two choices with a single select line, if we want to make more than 2, we need log2(n) select lines

[@awaislegend657]

Legend watch 1 day before the exam 😅😅

[@voltackle67]

Set the speed at 1.5 thank me later. Awesome expln. btw!

[@parthvasoya3562]

2 if you're not making notes

[@subhradipbarik2032]

Khapachoda

[@sainadh542]

🔥4:02 😍

[@nevilholmes5900]

Thanks

[@nauraizsubhan01]

Sir thanks a lot... :D

[@gurramsanjeev4084]

hi sir u r lecturer's was awesome
pls i want control systems for gate classes can u provide me

[@vaibhavbansode6942]

1.5x is recommended for those who have exam tomorrow 😊

[@ManikyamAmati]

What about those who are having exam toady😅😅

[@vaibhavbansode6942]

@@ManikyamAmati pls watch on 2x 😊

[@ececse]

thankyou sir

[@weizhao7862]

Thanks a lot !

[@pinkgirl7803]

Thanks a lot

[@learnerashish3490]

In the last part of this lecture you mug up all the things

[@mfaisalhameed6434]

Very helpfull..

[@quocanh2901]

thankiu sir

[@auroshisray9140]

You are awesome

[@yahyaabulhaj909]

I have a question, how it works with just one MUX 2X1 ? with the equation ?

[@suhaybahmed9771]

good job

[@souravdebbarma7685]

if the select line is 0, why I0 is selected

[@vincentcrescente6548]

thank you!!!

[@VivekYadav-hn5ow]

what do we call the initial select lines of 2*1 mux...??????

[@anudeepchowdary4389]

Hello sir you want upload for electrical machine -1 for elecrical enginners pls sir

[@ayushmansingh4834]

I am studying this on 1st January 2024 for my MCA sem exams.

[@vandanatlakhera405]

Thnk u....

[@hari8568]

Enable conditions?

[@Areeb851]

You are best

[@prayanshusinghIITBHU]

After 100th this is 121st lecture. Are 20 lectures missing?

[@nesoacademy]

Some issue with the app of UA-cam. Please watch on the website.

[@prayanshusinghIITBHU]

@@nesoacademy Thank you NA, the issue is solved now ☺

[@GautamKumar-te8gw]

Yes

[@ariap9697]

why there is not enough topic about decoders??!

[@danielolivera2618]

not in advanced logic

[@harshajain3099]

Thanks alot...

[@kedarsatwik6938]

How to design a 2 x 3 mux (2 inputs of 3 bits each) using 2 x 1

[@Edge9404]

Why use 3 2x1 MUX when you can use 2 2x1 MUX with S1 as the enable bit?

[@fardadansari1885]

Great .

[@sunandhmalipedhi2791]

Sir, is there any way to make 5:1 mux by using 2:1 mux

[@saira9130]

5*1 MUX doesn't exist

[@dieselgeezer18]

@@saira9130 i mean, you could take a 6:1 mux and cut the 6th wire off

[@dhanunjay2715]

Please give him noble prize

[@Irtofu]

There is an error in this video, it was noted that (8) 2x1 mux were required for (1) 8x1, while only (7) are required

[@suyashsreekumar3031]

Irtofu if you go by the formula given in the video it comes to as seven and not 8.

[@vamsikrishnaganga115]

from 2024

[@MsREDA1996]

could you translate the videos to spanish please?

[@awaislegend657]

Sir please talk in urdu

[@apnachannel25121]

Share the video

[@AbhinayShankhdhar]

tommorow exam anyone?

[@wajahatkhan9455]

:D Great!

[@sanskarkumar6484]

❣❣

[@adiitya5066]

damn

[@whymurali]

noob

[@amanrai6402]

very easy to understand...! thanks alot for this all video...!

[@adityamore2616]

Thanks