Lecture 1 | Zeros of an Analytic Function | Zeros and Singularities | Complex Analysis

[@nikhil_suryavanshi]

❤

[@PRINCE82100]

Your way of teaching is absolutely preety

[@GargiKiPathshala]

Hi Nidhiji!! In the case of sin(1/z), the zero is 1/n pie where n is any integer EXCEPT ZERO.

[@math-channel]

Since z is non-zero , its reciprocal (1/z) is also a non-zero number, and since 1/z =n pi , n pi is also a non-zero number. whence n is a non-zero integer. So it is understood that n is any integer except zero.
Please correct me if I am wrong.
Feroz.

[@GargiKiPathshala]

@@math-channel You are right. All of us understand this, but when we are dealing with students, we have to smartly mention that n is a non-zero integer.
Anyways, it's really great that we are discussing it positively.

[@math-channel]

When students are taking Complex Analysis, they must be able to reason this. Thank you.

[@gurmeetgouri2871]

Very easy explanation......
Thanks a lot mam 🙏

[@arunkumarsharma4769]

Thank

[@anilchoudhary6946]

Thanku mam 😁

[@abhishekseth6285]

Thanks

[@abdullahzafar3571]

Order of zeroes?

[@bhaskararaoanguru873]

Tq mam