Abstract Algebra | Irreducible polynomials

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  • Опубліковано 20 жов 2024

КОМЕНТАРІ • 9

  • @maxdominate2481
    @maxdominate2481 3 роки тому

    So glad to find your channel. I just bought an abstract algebra book and was looking through a proof in the section "Irreducible Polynomials Are Maximal Ideals" and thought I'd type that "section title" into UA-cam to see what would come up...and here you are. I'm looking forward to watching more of your stuff.

  • @rac6040
    @rac6040 4 роки тому +3

    Brother you are doing great work..Love from India 🇮🇳🇮🇳🇮🇳

    • @divya296
      @divya296 3 роки тому +1

      Me too ,from India. Sir, greetings from India

  • @absolutezero6190
    @absolutezero6190 3 роки тому

    5:00 is the cleanest edit

  • @maxdickens9280
    @maxdickens9280 Рік тому

    You can try to prove it yourself and skip ahead to 8:47 to watch the applications.

  • @keyblade134679
    @keyblade134679 Рік тому

    Does this proof extend to the multi variable case ?

    • @kevxjn
      @kevxjn 5 місяців тому

      Technically K[x,y] is isomorphic to (K[x])[y], in the sense that the ring of polyals in two variables x and y, is isomorphic to the one only having one variable but the coefficients into K[x].
      The problem with that is that while K is a field, we know that K[x] is not.
      So that's a nice question.
      But yes, you can prove that every ideal I = (p) where p is an irreducible element inside a Ring is maximal, then the result which involves the quotient R/M, that you can see on the left side of the blackboard, is true without making any assumptions on the qualities R must have.
      So yes, that should estend onto the multi variable case

  • @vindhyachalsingh8217
    @vindhyachalsingh8217 4 роки тому

    Tku