*CORRECTION OF ERROR* Our Beloved VIEWERS, Thank you for all your constructive criticisms. It shows that you have our interest at heart and want us to be better. It is much appreciated!🙏 Our attention has been drawn to an error in the solution to the last question in this video, in which we were asked to calculate the amount of silver deposited, and we mistakenly interpreted it as the mass. We sincerely apologize for this error, and take full responsibility. To this end, kindly note that the correct answer to that question is 0.113 mole of Ag which is obtained by dividing the calculated mass of 12.221 g by 108 g/mol, the molar mass of Ag, i.e., number of mol of Ag deposited = 12.221 g /108 g/mol = 0.113 mol. Thank you for your understanding and continued viewership. Regards, The Science Chef Academy Team
You are very correct, @Jerry! While recording this video late in the night, my head processed the information as mass. We are sorry about that. Thanks for your understanding!🙏
Good job, the Science Chef! But in the last, I thought you were asked to calculate the "amount" and not the "mass" of silver deposited. So, the answer should be in moles and not grammes. Please correct that, sir! When should we expect the correction to Q2 - Q5?
Thank you for the observation. We would do the necessary adjustment. Corrections to Q2 - Q5 would be published on/before next week Monday by God's grace!🙏
*CORRECTION OF ERROR*
Our Beloved VIEWERS,
Thank you for all your constructive criticisms. It shows that you have our interest at heart and want us to be better. It is much appreciated!🙏 Our attention has been drawn to an error in the solution to the last question in this video, in which we were asked to calculate the amount of silver deposited, and we mistakenly interpreted it as the mass. We sincerely apologize for this error, and take full responsibility.
To this end, kindly note that the correct answer to that question is 0.113 mole of Ag which is obtained by dividing the calculated mass of 12.221 g by 108 g/mol, the molar mass of Ag, i.e.,
number of mol of Ag deposited = 12.221 g /108 g/mol = 0.113 mol.
Thank you for your understanding and continued viewership.
Regards,
The Science Chef Academy Team
Thank you sir
You are welcome!🙏
❤
Thanks for watching!🙏
Amount means moles, not gram. Amount of silver deposited is 0.113moles
You are very correct, @Jerry! While recording this video late in the night, my head processed the information as mass. We are sorry about that. Thanks for your understanding!🙏
No problem the Science Chef. You're superb!
🙏
But amount of silver I thought should be in moles
Yea, you are right @ChibuzorAgugua. It's an oversight. In my head, I was reading it as mass! So sorry about that!
Good job, the Science Chef! But in the last, I thought you were asked to calculate the "amount" and not the "mass" of silver deposited. So, the answer should be in moles and not grammes. Please correct that, sir!
When should we expect the correction to Q2 - Q5?
Thank you for the observation. We would do the necessary adjustment. Corrections to Q2 - Q5 would be published on/before next week Monday by God's grace!🙏
Thank you sir
It's our pleasure to be of help!🙏