Hold on on hold on, if something has less electronegativity, then it should be more available to donate electrons not less? Not to mention im pretty certain the only reason why N type semiconductors, conduct, is because the three valence in phosphorus are filled then because silicon still demands one more valence bond, it pushes the remaining phoshorus electron toward a higher electron orbital therefore making it weaker to energy flux's and more reactive. @WeAreRSGroup
Hi Colin, Christopher here. You are absolutely right that a less electronegative material will have lesser tendency to attract electrons and more tendency to donate electrons. However, the problem is that p type materials under room temperature do not have free electrons in the conduction band and hence has no electrons to donate. If there is a free electron generated in the conduction band of the p type material like in a solar cell, then yes, the electron in the p-type material will flow to the n side (upon coming in contact with the more electronegative n type material). This is the entire purpose of a pn junction, which is to have electrons only flow in one direction (p to n). I hope this clears things up for you 🙂
@@BlackRockExecutive ye because as thermal energy is exchanged into electromagnetic energy we raise orbital energy of electrons, raising them into the conduction band, and because phosphorus requires all of its electrons it begins to seek them from weaker valence bonds with electropositive valence shells or does the N side recieve electrons from silicon with no available valence bonds? Basically the same concept as a single atom who hybdrizes its orbital to achieve lowest energy states in valence bonds? Where the energy states are lower it will hybridize, so its thermal conduction will be the same. ..... Basically i would really like to know the order of precedence... N type free electrons conduct first, then free silicon electrons and / or electropositive valence electrons? (Probably not as it would be harmful to the molecular structure), would valence bonded electrons ever reach the conduction band?
Hold on on hold on, if something has less electronegativity, then it should be more available to donate electrons not less? Not to mention im pretty certain the only reason why N type semiconductors, conduct, is because the three valence in phosphorus are filled then because silicon still demands one more valence bond, it pushes the remaining phoshorus electron toward a higher electron orbital therefore making it weaker to energy flux's and more reactive. @WeAreRSGroup
Hi Colin, Christopher here. You are absolutely right that a less electronegative material will have lesser tendency to attract electrons and more tendency to donate electrons. However, the problem is that p type materials under room temperature do not have free electrons in the conduction band and hence has no electrons to donate.
If there is a free electron generated in the conduction band of the p type material like in a solar cell, then yes, the electron in the p-type material will flow to the n side (upon coming in contact with the more electronegative n type material). This is the entire purpose of a pn junction, which is to have electrons only flow in one direction (p to n).
I hope this clears things up for you 🙂
@@BlackRockExecutive ye because as thermal energy is exchanged into electromagnetic energy we raise orbital energy of electrons, raising them into the conduction band, and because phosphorus requires all of its electrons it begins to seek them from weaker valence bonds with electropositive valence shells or does the N side recieve electrons from silicon with no available valence bonds? Basically the same concept as a single atom who hybdrizes its orbital to achieve lowest energy states in valence bonds? Where the energy states are lower it will hybridize, so its thermal conduction will be the same.
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Basically i would really like to know the order of precedence... N type free electrons conduct first, then free silicon electrons and / or electropositive valence electrons? (Probably not as it would be harmful to the molecular structure), would valence bonded electrons ever reach the conduction band?