Power Refinement and Spherical Equivalent through Jackson cross cyl

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  • Опубліковано 27 лип 2024
  • OPTOMETRY WITH KHURRAM
    In this video we will learn about the how to refine the cylindrical power with Jackson cross cylinder and how to maintain the spherical equivalent to drag the circle of least confusion on the retina.
    But you have to watch all the videos regarding Jackson cross cylinder link is given below.
    Construction of JCC
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    • How to make Jackson Cr...
    1st step of JCC (Bracketing)
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    • (Bracketing) First ste...
    2nd Step Axis refinement through JCC
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    2nd Step of JCC
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    • Axis Refinement (2nd S...

КОМЕНТАРІ • 27

  • @lorettaekechukwu4145
    @lorettaekechukwu4145 2 роки тому +1

    I truly love your video...really demystifies JCC for me. I would like to know how to get this exact trial frame and JCC.

  • @otiebrown9999
    @otiebrown9999 10 місяців тому

    This was a big help to get to 20/20.
    Thank you for suggesting this.
    Currently perfect, with no glasses.

  • @kartheek4284
    @kartheek4284 3 роки тому +3

    Sir , What's the reason behind to do spherical equivalent after JCC ? Spherical equivalent means we are avoiding cylinder right then after JCC spherical equivalent why cylinder power written?

    • @optometrywithkhurram6867
      @optometrywithkhurram6867  3 роки тому +1

      Diffrence of Spherical equivalent in JCC and actual SPHERICAL equivalent.
      Watch these videos
      You would be clear.
      ua-cam.com/video/jhI0OTVl8iw/v-deo.html

    • @optometrywithkhurram6867
      @optometrywithkhurram6867  3 роки тому +1

      In JCC we perform this spherical equivalent like process due to maintenance of the strums conoid, to drag the circle of least confusion on the retina.

    • @kartheek4284
      @kartheek4284 3 роки тому +1

      @@optometrywithkhurram6867 tq sir

  • @dr.malikaqeel5631
    @dr.malikaqeel5631 3 роки тому +1

    Thank you Sir

  • @nsr2839
    @nsr2839 10 місяців тому

    Hi , sir I have a doubt , what if I found bestvision sphere -0.50 after jcc test I found -1.00cyl . Which is the best prescription ? -0.50 sp -1.00 cyl or -1.00cyl

  • @zaraarif73
    @zaraarif73 Рік тому +1

    In jcc for power refinement why would we put axis of jcc parallel to trail cylinder axis ? And not the handle of jcc for this ?
    Plz ans this
    Thank you

    • @optometrywithkhurram6867
      @optometrywithkhurram6867  Рік тому

      Zara the logic is so simple ...
      In power refinement , we align axis of jcc with axis of trial cyl because we have to find the exact cylindrical power of patient,
      If trial cyl is minus, and when we align minus line of jcc on minus line of trial cyl the power would be doubled so we will do same thing until our patient gets maximum vision.
      And when we need to decrease the power we will align plus line of jcc with minus line of trial cyl until we get maximum vision again.

  • @shadabahmad1445
    @shadabahmad1445 9 місяців тому

    Sir what if patient accept position 2. ???

  • @CHEFSECRET19
    @CHEFSECRET19 Рік тому +1

    Sir how can we differentiate that is patient has minus cylinder or plus cylinder?or we always suggest minus cylinder??

    • @optometrywithkhurram6867
      @optometrywithkhurram6867  Рік тому +1

      A Patient will prefer both axis plus and minus at 90° apart axis ...it's your choice to prescribe him plus cyl at a given axis or minus cyl at 90° apart.
      Minus cyl always preferred globally.

    • @CHEFSECRET19
      @CHEFSECRET19 Рік тому +1

      @@optometrywithkhurram6867 ok i understand, thank you

  • @Mukhtar_jnr
    @Mukhtar_jnr Рік тому +1

    Please sir link for the previous video you mention God bless you.

    • @optometrywithkhurram6867
      @optometrywithkhurram6867  Рік тому

      Please check the description of this video ..all the links regarding JCC videos are given

    • @Mukhtar_jnr
      @Mukhtar_jnr Рік тому

      @@optometrywithkhurram6867 thank you so much sir and please sir i have a question that has been bothering me about hand neutralisation Retinoscopy with plain mirror and concave mirror though concave mirror to me look similar to hand neutralisation if may be you can help me and explain it more clear the similarities between the three and also their differences and the theories behind each i will appreciate it sir thank you once again i am a student of optometrist too.

  • @Jaycycar
    @Jaycycar Рік тому

    So what is the importance of of spherical equivalent here?

  • @zubaidamalik4641
    @zubaidamalik4641 Рік тому

    sir you said add half of cylinder to spherical with OPPOSITE SIGN but in other video title as why spherical equavalent is zero of JCC? you didnt change sign to algebrically add it to sphere........I think we dont change sign of cylinder to algebrically add it to sphere .....and if i am wrong please correct ..thanks for wonderful explanation of JCC

    • @optometrywithkhurram6867
      @optometrywithkhurram6867  Рік тому

      Dear..
      You raised a very good question, at this point students make mistakes,
      Listen carefully
      "ADD HALF OF CYL INTO SPHERICAL" but in case of Spherical equivalent of any prescription we always add half of cyl into spherical buy with same sign.
      And in the PROCEDURE of JCC, in last step of JCC which is called RULE OF THUMB, we always add half of cyl into spherical with opposite sign.
      I have recorded 3 vidoes on this query, you can watch, or if you still didnt understand, I will make a new compiled video.

    • @zubaidamalik4641
      @zubaidamalik4641 Рік тому

      @@optometrywithkhurram6867sir, I corrected my mistake thanks for your precious time

    • @optometrywithkhurram6867
      @optometrywithkhurram6867  Рік тому

      @@zubaidamalik4641 good. I made a new video for you..and I mentioned your comment in my video..video will be uploaded on UA-cam at 6 pm..
      Enjoy.👍
      Have a good day.

    • @optometrywithkhurram6867
      @optometrywithkhurram6867  Рік тому +1

      @@zubaidamalik4641 ua-cam.com/video/9FYkssi-epY/v-deo.html