Many parents and “old” people might have had poor quality teaching when they were taught math, so I share this channel with my mom and others who are “bad” at math.
The perimeter (2 eidths + 2 lengths) is 6x +6 =60 if the width ix x & one of the long sides is 2x+2. This makes it easy to solve since every term is divisible by 6, such that x+1=10 making x=9
Greetings. The dimensions are 9 units for the width and 21 units for the length. We Shall assume that the width of the rectangular figure is X. When the width is X units, the length is 3 more than twice this measure. Therefore, the length is (2X +3) units. Moving forward, the perimeter using the dimensions is 2(X+ 2X+3)=2(3X+3)=6X+6 units. We will now equate the values of the perimeters to get 6X+6=60, and 6X=60-6, 6X=54 and X=54/6 =9 units, the width of rectangular figure. The length is twice the value of X +3 = (2×9+3)=18+3=21 units.
If we call the width X that would make the length 2X + 3 and we have been told that 2X + 2(2X + 3) = 60 do the 2(2X + 3) 2X + 4X + 6 = 60 add the Xs together 6X + 6 = 60 subtract 6 from both sides 6X = 54 divide both sides by 6 X = 9 The width is 9 and the length is 9 x 2 + 3 = 21 and to check 9 + 9 + 21 + 21 = 60
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Many parents and “old” people might have had poor quality teaching when they were taught math, so I share this channel with my mom and others who are “bad” at math.
A superb review of algebra basics; essential to retain what some of us learned back just before the last Ice Age.
got it in about 45 sec. good one, thanks. it was fun.
Width is 9; length is 21.
Known:
L = 2W +3
P = 60
2L + 2W = P
2L +2W = 60
Solve:
Substitute (2W + 3) for L
2 (2W+3) + 2W = 60
Distributive property
2*2W + 2*3 + 2W = 60
4W + 6 + 2W = 60
6W + 6 = 60
Subtract 6 on both sides
6W = 60 - 6
6W = 54
Divide by 6 on both sides
W = 9
Solve for L
L = 2*9 +3
L = 18 + 3
L = 21
The perimeter (2 eidths + 2 lengths) is 6x +6 =60 if the width ix x & one of the long sides is 2x+2. This makes it easy to solve since every term is divisible by 6, such that x+1=10 making x=9
9”x21” (figured out in my head in less than a minute)
Took a few tries. But the length is 21 and the width is 9. 2L + 2W = 60 L = length. W = width. P = perimeter.
L = 2W + 3
2(2W + 3) + 2W = 60
4W + 6 + 2W = 60
6W + 6 = 60
6W = 54
W = 9
L = 2W + 3
L = 2(9) + 3
L = 18 + 3
L = 21
Therefore 21x9 rectangle.
2L + 2W = 60.
2(21) + 2(9) = 60
42 + 18 = 60
60 = 60 😊
Greetings. The dimensions are 9 units for the width and 21 units for the length. We Shall assume that the width of the rectangular figure is X. When the width is X units, the length is 3 more than twice this measure. Therefore, the length is (2X +3) units. Moving forward, the perimeter using the dimensions is
2(X+ 2X+3)=2(3X+3)=6X+6 units. We will now equate the values of the perimeters to get 6X+6=60, and
6X=60-6, 6X=54 and X=54/6 =9 units, the width of rectangular figure.
The length is twice the value of X +3
= (2×9+3)=18+3=21 units.
If we call the width X that would make the length 2X + 3
and we have been told that 2X + 2(2X + 3) = 60 do the 2(2X + 3)
2X + 4X + 6 = 60 add the Xs together
6X + 6 = 60 subtract 6 from both sides
6X = 54 divide both sides by 6
X = 9
The width is 9 and the length is 9 x 2 + 3 = 21 and to check 9 + 9 + 21 + 21 = 60
Thank you. What software are you using for this video (for writing), can you tell me, please?
two equations
in
two unknowns
L
W
eq.1: 2L + 2W = 60
eq.2: L = 2W + 3
modifying eq.2 and then putting into eq.1 =>
eq.2: L = 2W + 3
2W = L - 3
eq.1: 2L + 2W = 60
2L + (L - 3) = 60
3L = 63
L = 21
from eq.2
eq.2: L = 2W + 3
21 = 2W + 3
18 = 2W
W = 9
VERIFY:
L=21, W=9
from eq.1
eq.1: 2L + 2W = 60
2(21) + 2(9) =? 60
42 + 18 =? 60
60 =❤ 60✔️
Why use 2 unknowns when 1 will work?
@@terry_willis both length and width are unknowns
9 x 21. Let X equal the width.
Dim 21*9
21 and 9
9 × 21
9 and 22
Length is 22.5
Width is 7.5
Not correct - read the question again.
Length = 21
Width = 9
Width-9
Length-21
9x21
Width=9cm
Length=21cm
Trick question
I liked it until you took 2 minutes to ask us to like it... 😞
17 minutes to explain this? Seriously? It took me 40 seconds to solve this in my head. You must be the most boring math teacher ever.
I got this wrong.
21 and 9
21 ×9