It isn't. But it's (3/2) sqrt(6). To get a unit vector in the (-3/2, -3/2, 3) direction, I first multiplied by 2/3 to get (-1, -1, 2), and then divided by the length of (-1, -1, 2), namely sqrt(6). Multiplying by 2/3 isn't necessary --- you can just divide (-3/2, -3/2, 3) by the length of (-3/2, -3/2, 3). But the way I did it makes the computation much easier, since squaring and adding integers is a lot simpler than squaring and adding fractions.
Life saver! This is the first Graham-Schmidt explanation that has made any sense to me
"at the second stage, it kills you."
"can't get it from a store" great line lorenzo my man 10/10
This was the video on the Gram-Schmidt Process online I've seen. Thank you Dr. Sadun!
Thank goodness for this video and for the visual representation of what the Gram-Schmidt process actually does
Very well explained, thank you.
loved it! clear and concise
Thanks a lot. very simple and concise.
thanks i have a paper today and they are gonna ask me this i didn't understand uptil now but now thank you
Bless you sir! 🙏
good explain
Deserves a like
i have no idea why ||(-3/2,-3/2,3)|| would be root(6)??????????
It isn't. But it's (3/2) sqrt(6). To get a unit vector in the (-3/2, -3/2, 3) direction, I first multiplied by 2/3 to get (-1, -1, 2), and then divided by the length of (-1, -1, 2), namely sqrt(6). Multiplying by 2/3 isn't necessary --- you can just divide (-3/2, -3/2, 3) by the length of (-3/2, -3/2, 3). But the way I did it makes the computation much easier, since squaring and adding integers is a lot simpler than squaring and adding fractions.
thank you very much Mr.Lorenzo Sadun
BORAT SACHDEV why is the length of ((2, -i)) , 4.I do not get it.
SAMUEL OPOKU AGYEMANG The length of (2, -i) is sqrt(2^2+|i|^2)=sqrt(5), not 4.
sqrt(6)
i think the length of ((2, -i)) is square root of 6
very well explained, Thanks
thank you
That is all ?
thank you sir
they actually sell orhotonormal basis at the store
Yeahhh... I understant Gram-Schmidth..
0:10 Trying to be funny ??
ı dont know uffff
results are wrong !!! 15/3 is not equal to 5 it's equal to 3 !
good explanation however it would perhaps be wise to use different variables for the bases as it gets confusing with the example