At y = 5.5 you get 2 x values. x = -2 on the left and x =1 on the right. And then at y = 2.5 you get two values for x. x= -3 and x=0 If you take any y values from the rest of the graph you will get more than two values of x. They want two solutions, so you have to find at which point of y (when drawn horizontally) will intercept with 2 points of the yellow line.
Hii thankss for uploading this paper, really helpful so I can check with the ms before my m/j series p4 on Tuesday, just had my chem, bio p4 and math p2 and by the grace of god, they've gone great. One more thing, u can actually use log function for question 9 b to speed up things by bringing everything to the opposite side and simplifying leaving with just two numbers, 1.018^x = 15/13 and using log1.018(15/13) giving you 8. something and u can round it off to 9 bc that is not a complete year. Cheers
I don't understand for 12 (a), it says calculate perimeter of the REMAINING shaded shape, so why do you need to add the perimeter of the sector that is removed??
One question please, i did not understand how u got the values of k for the quadratic graph in 10 d, why not take the top 2 values of the graph? and how did u get the 5.5?
I didn’t understand Q 10 part(d) can u please explain me briefly .
At y = 5.5 you get 2 x values.
x = -2 on the left and x =1 on the right.
And then at y = 2.5 you get two values for x.
x= -3 and x=0
If you take any y values from the rest of the graph you will get more than two values of x.
They want two solutions, so you have to find at which point of y (when drawn horizontally) will intercept with 2 points of the yellow line.
@@learntodayIGCSEthank you so much ❤
@@RenishanXChris did u get it?
@@learntodayIGCSE yeah I understood 😊❤
@@learntodayIGCSE in addition miss I appreciate you for spending your time to explain me .You earned my sub ☺️
It was really help full thanks
Most welcome and best of luck for the exams !
Hii thankss for uploading this paper, really helpful so I can check with the ms before my m/j series p4 on Tuesday, just had my chem, bio p4 and math p2 and by the grace of god, they've gone great.
One more thing, u can actually use log function for question 9 b to speed up things by bringing everything to the opposite side and simplifying leaving with just two numbers, 1.018^x = 15/13 and using log1.018(15/13) giving you 8. something and u can round it off to 9 bc that is not a complete year. Cheers
I don't understand for 12 (a), it says calculate perimeter of the REMAINING shaded shape, so why do you need to add the perimeter of the sector that is removed??
When are you planning to post 2024 feb march maths other papers?
Hey! when will you do 2024 paper 2 mathematics?
One question please, i did not understand how u got the values of k for the quadratic graph in 10 d, why not take the top 2 values of the graph? and how did u get the 5.5?
can we do 9b 5:48 with log? will they give us the marks.
Absolutely. This was just my way of solving but log is the way to go
Mam I think you made a mistake in the last question of the last part as the square of 12 is 144 but you used 124
310/360 x 12 square = 124
Check again 😊 you should try out the question as well to understand better
12² is 144 but if you use the equation then it's 124 as the answer
your videos nice and all but i feel like you pass through questions too fast because i could'nt understand some questions
Can send the copy ?
drive.google.com/drive/folders/149ljGeSoYrQG1UFt1i5M_hxWFaIkEb5S?usp=drive_link
@@learntodayIGCSEthank you❤
@hcgamer1298 let me know if u manage to find them
@@learntodayIGCSEI find them, but cannot find chemistry P4
PRAY FOR ME MY PAPER IS IN 2 HOURS
Ahaha ok I’ll pray for you ❤️ 👼 best of luck !!
Are you a school teacher ?
🤔 hmmm why
I call her cheating because she is using highlighter and it’s not allowed