Real Analysis: Contractions and Picard’s Fixed-point Theorem. Lect. 18.

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  • Опубліковано 21 жов 2024
  • Real Analysis:
    Metric Spaces: Contraction on Metric Space.
    Picard’s Fixed-point Theorem: statement and proof.
    In the statement of the Picard’s Fixed-point Theorem, at time stamp 8:54, please read as Let M be a “complete “ metric space.
    Link for playlist of Metric Spaces:
    • Real Analysis: Metric ...
    The book followed is
    Richard R Goldberg: Methods of Real Analysis
    Link for Handwritten notes: (send a request mail, I will share it with you)
    1. Limits in Metric Spaces.
    drive.google.c...
    2. Continuous Functions on Metric Spaces.
    drive.google.c...
    3. Connectedness, Completeness and Compactness. Pages 1 to 19.
    drive.google.c...
    4. Connectedness, Completeness and Compactness. Pages 20 to 25.
    drive.google.c...

КОМЕНТАРІ • 13

  • @evilfairy7460
    @evilfairy7460 2 роки тому

    I really have no words😭 Today i had an exam but i couldn't understand this theorem. Thank God I've found this video. You're really doing a great job sir, even though the views are low keep uploading the videos sir. I wish I could get a teacher like you sir

  • @sahanas4575
    @sahanas4575 Рік тому

    Thank you for all your videos sir... I'm very excited to learn real analysis after watching all your lectures. With a week I have real exam I wish I could found your channel before😿

  • @algorithmo134
    @algorithmo134 3 роки тому

    Hi Sir, you should consider doing a playlist for each real analysis topic which covers everything in the book RR Goldberg. You are excellent in teaching students. Very clear concepts! God bless!

  • @mahalakshmig5232
    @mahalakshmig5232 2 роки тому

    Sir can you explain regarding cauchy criterion for uniform convergence?

  • @viji.d927
    @viji.d927 2 роки тому

    Sir T suffix x or Tx?

  • @jaganraj_r
    @jaganraj_r 2 роки тому

    8:54 complete metric space

    • @BScMathematicsDrSSPhulsagar
      @BScMathematicsDrSSPhulsagar  2 роки тому

      Yes. In the statement of the theorem please read as M be a complete metric space. Thank you for suggesting the correction.