Sir why cant we use the value of H obtained from the graph from B=0.5T, find the length of the central leg, and use I = (Hxlength)/N to find the current? (part a)
Sir, u said that we divide the center flux density by 2 since there are 2 symmetrical outer legs. But what if it’s not symmetrical, how do we find the flux density of the outer legs?
Thanks a lot! I didn't know why in the solution book they took just 1 side of the outer corner, thanks to you I know!!! Awesome
Thanks dear
Sir why cant we use the value of H obtained from the graph from B=0.5T, find the length of the central leg, and use I = (Hxlength)/N to find the current? (part a)
Give it a try, and let me know what did you find .
Sir, u said that we divide the center flux density by 2 since there are 2 symmetrical outer legs. But what if it’s not symmetrical, how do we find the flux density of the outer legs?
Divide by the cross sectional area of each side.
Sir.. why the solution just took 1 side only? I didnt understand it.
Please let me know the video time, where you have doubt.
@@ElectricalEngineeringAcademy 7:52 here you only took one outer side. Why not both? like multiply by 2
please watch the video again from time 3:50 onward. Try to understand the concept of Vparallel @@aakaashs2310
Greattt