Alkene + HBR + ROOR - Reaction Mechanism

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  • Опубліковано 3 лис 2024

КОМЕНТАРІ • 28

  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  2 роки тому +1

    Organic Chemistry PDF Worksheets: www.video-tutor.net/orgo-chem.html
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  • @ftedg
    @ftedg 4 роки тому +55

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    • @guanchungoh1784
      @guanchungoh1784 3 роки тому +8

      It will be one of the mysteries of the Universe that will remain unsolved. 😢

  • @johnbarto1120
    @johnbarto1120 4 роки тому +30

    Finished taking Organic Chem but still really enjoy watching these videos. Such a good teacher

    • @martinap5921
      @martinap5921 2 роки тому +29

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    • @SweatBloodTears
      @SweatBloodTears 4 дні тому

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    @Dina-he1uc 4 роки тому +57

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      @mr.knowitall5019 3 роки тому +5

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      @hichaeljordan963 2 роки тому

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      @Dina-he1uc Рік тому +3

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  • @Jeremy-sj3pr
    @Jeremy-sj3pr 3 роки тому +4

    Can you please post a video for alkyne reactions with hbr and ROOR?

  • @ndukanwankwo8393
    @ndukanwankwo8393 2 роки тому +1

    Wow explained nicely thanks

  • @019saravanakumark2
    @019saravanakumark2 4 роки тому +4

    Suggestion for A video; please make chemistry videos from the syllabus of IIT JAM exam.. One of the toughest exams in India.. Please..

  • @cdietrich3252
    @cdietrich3252 2 роки тому +2

    What would be the mechanism for
    2H-Br + H202 -> Br2 + 2H20 ? If the solvent is ethanol

  • @YuGansuuhhhhh
    @YuGansuuhhhhh 3 роки тому

    Ty ...now this topic is as clear as glass for me 😁😁

  • @hansenyang4014
    @hansenyang4014 4 роки тому +6

    I've heard that the HBr/ROOR reaction only works for HBr but not other hydrohalic acids. Is this true? If so why?

    • @bluehourcore
      @bluehourcore 3 роки тому +2

      this is due to the fact that the HCl bond is too strong to be broken to produce free radicals ( bond energy is 430.5 KJ/mol) while the bond energy of the HBr bond is 363.7 KJ/mol.
      In case of HI, although the H-I bond is broken pretty easily via homolysis, the iodine atoms so produced immediately react to form iodine molecules instead of attacking the double bond of the carbon atoms in alkene.

  • @KNG8828
    @KNG8828 4 місяці тому

    well explained bro

  • @BrendaPortugal
    @BrendaPortugal Рік тому

    thank you for these videoss

  • @marcodayao4127
    @marcodayao4127 4 роки тому +9

    I'm that one dude in my class who likes Org Chem....

  • @aswitrishu4465
    @aswitrishu4465 3 роки тому +1

    Wowww❤️❤️

  • @kevinkantize844
    @kevinkantize844 2 роки тому

    @Organic Chemistry Tutor, is there not an enantiomeric mixture when alkenes reacts with peroxides just as there was with HBr.

  • @Sanjay-hh9xl
    @Sanjay-hh9xl 4 роки тому +3

    Hi guys

  • @epicentertainment5658
    @epicentertainment5658 4 роки тому +1

    Sir you are explaining about morkonia and anti morkania rule

    • @tawneeens436
      @tawneeens436 2 роки тому +2

      Markovnikov and anti-Markovnikov rules and yes, the more substituted / less hydrogenated carbon gets the Halogen in Markovnikov fashion ( not in presence of peroxide’s ROOR )

  • @taradhippayom8495
    @taradhippayom8495 9 місяців тому

    I want you tobe my sensei @@##😊😊😊

  • @aileenchalen3742
    @aileenchalen3742 Рік тому +1

    Why doesn’t RO-Br form ? 5:37

    • @kanishkraj2709
      @kanishkraj2709 Рік тому +2

      Because we want Br• radical for our next step, where it attacks the alkene. Some of the R-O• and some of the Br• do combine to form R-O-Br, but that is not required for us at the moment for the reaction. Hope it helped