This is actually easy for a Math Olympiad question. Suppose x is one number. The next one would be x+1, and the next one x+2. Now, we can write the sum: x+(x+1)+(x+2)=60. We can simplify the equation to 3x+3=60. Subtracting 3 on both sides, we get 3x=57. We can divide 3 on both sides to get *x=19.* The largest number will be x+2, and if we substitute 19 for x, we get 19+2, which equals *21.* Therefore, *D is the final answer.*
Let the consecutive numbers are x, x+1, x+2 x + (x +1) + (x+2) =60 3x +3 =60 3x= 60 - 3 3x= 57 x= 19 First number = x = 19 Second number = x+1 =19 +1 = 20 Third number =x +2 =19 +2 = 21 ANS 😊
x+1+x+2+x+3 will be our equation like this 3x+6= 60 hence x value will be 18 to be substituted on equation x+1+x+2+x+3 therefore x+1= 19 x+2= 20 x+3= 21 when x value 18 is substituted
Actually There are 2 ways to do this question such as the one the teacher did and if x=19 because x+[x+1]+[x=2]=60 Then 19 plus 1 and 19 plus 2 is equal to 20 and 21 Therefore the largest number is D 21
Let the numbers be x-1,x,x+1. That adds up to 3x=60, x=20. The largest is x+1=21. This should be a pre-k to kindergarten Olympiad question (which doesn’t exist) max since people can guess the numbers easily.
See look at the options DO NOT use traditional methods using x to calculate the value rather if you see the options you can infer that if 21 is the largest other two are 19 and 20 if you add these together you will get 60 so 21 is the correct answer
this is very bad approach to solve these type of questions instead assume the first number be x and x+1,x+2 then x+(x+1)+(x+2)=60 3x+3=60 3x=57 x=19 hence the numbers are 19,20,21
Instead of saying its a bad method, you should say it's a more clever method if you see. Because 20+20+20 is 60 and if you subtract one from one 20 and add that to the other 20 you get 19+20+21 equals 60.
Let the first consecutive number be x So, the second consecutive number is x+1 the third consecutive number is x+2 Equation according to the question - x+x+1+x+2 = 60 3x+3 = 60 3x = 60-3 3x = 57 x = 57/3 x = 19 First consecutive number (x) = 19 Second consecutive number (x+1) = 19+1 = 20 Third consecutive number (x+2) = 19+2 = 21 So the three consecutive numbers whose sum is 60 are 19, 20 & 21. Answer check - 19+20+21 = 60 This is what we needed according to the question so the answer is correct By a 8th grader.... ❤
Let the smallest number be x. x + (x + 1) + (x + 2) = 60 Or, 3x + 3 = 60 Or, 3x = 60 - 3 = 57 Or, x = 19 The largest number is (x + 2) = 19 + 2 = 21 [Option d is correct]
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This question is actually not even school level lmao, u just have to: Suppose the three cons. No. As x-1,x,x+1 X-1+x+1+x=60 3x=60 X=20 Since the largest no is x+1 Then yo answer is 21😊
Great trick to solve this problem. But shouldn’t students know how to solve this problem algebraically? Let x=smallest number , x+1=, middle number and x+2= largest number then x+x+1+x+2=60. 3x+3=60, x=19 largest number is x+2=21 choice d. I look forward to hearing, speaking, and conversing with you. Take care, bye, bye, and have fun!!!😅
No way this is an olympiad question, I don't believe it. a+b+c=60 60/3 since there are 3 numbers. They have to be dancing somewhere around 20. 1 less than it, 1 more than it. 19 ,20, 21. 21 is the largest number of the 3. As you can tell, I didn't really take an algebraic approach but you could also solve it that way. x+x+1+x+2=60 3x+3=60 3x=57 x=19, x+2 is the largest number 19+2=21
Why not 30? Because 60/2 = 30… 30 + 30 = 60 _but_ we need 3 numbers so if we subtract 1 from the first 30 we get: 1+29+30 = 60 Right!? Edit: Why not 1+2+57 = 60 And are we limited to integers? Am I stupid? Idk, I think the question needs to be re-stated because you can literally pick any number of the four options that were given. Edit2: okay, nvm, she meant the mathematical definition of consecutive.
This is NOT what a math olimpiad looks like. It's a lot more difficult. Even the first olimpiad, which is in forth grade from what i remember is a lot more difficult, but if you look at something like 7th, 8th or maybe 9th grade you will find some stuff with solutions almost impossible to find
let the constant be x
a.t.q
x+(x+1)+(x+2)=60
3x+3=60
x=60-3/3
x=19
Number x=19
x+1=19+1=20
x+2=19+2=21
thus the largest number is 21
Correct
You and I agree with the method of attack.
I’ve seen this method used in my algebra classes and I’ve never understood why this works
@@tyronekim3506 very good... But in the math constest.... You will lose
Yeah
This is actually easy for a Math Olympiad question.
Suppose x is one number. The next one would be x+1, and the next one x+2. Now, we can write the sum: x+(x+1)+(x+2)=60.
We can simplify the equation to 3x+3=60. Subtracting 3 on both sides, we get 3x=57. We can divide 3 on both sides to get *x=19.*
The largest number will be x+2, and if we substitute 19 for x, we get 19+2, which equals *21.* Therefore, *D is the final answer.*
Of which class this question is of
@@flexff8265 I think algebra
The problem isn’t that hard, anyone with a basic understanding of algebra should be able to solve this problem.
@@somebody_33 No no no I don't mean that mean of class 8 class 9 or class 10
@@flexff8265 I’m not sure.
@@flexff8265 class 7
We can also write this as
3
Σ (x+n) = 60
n=0
No, the sigma/summation should be from 1 to 3
Let the consecutive numbers are x, x+1, x+2
x + (x +1) + (x+2) =60
3x +3 =60
3x= 60 - 3
3x= 57
x= 19
First number = x = 19
Second number = x+1 =19 +1 = 20
Third number =x +2 =19 +2 = 21
ANS 😊
x+1+x+2+x+3 will be our equation like this 3x+6= 60 hence x value will be 18 to be substituted on equation x+1+x+2+x+3
therefore
x+1= 19
x+2= 20
x+3= 21
when x value 18 is substituted
Ncert class 8 exercise 2.4 question 6
Very nice. I'm not good in math. I love finding answers!
Haha...i calculated that in my mind just in 3 seconds 🤣
woooow
@@joshijoshi1935 19,20,21= 60 just did it in my head
Koi fayda ni h yeh Olympiad ka question hi ni h Sara hua tatti sawal h class 5 kai level ka
@@AyushRaj-lj3dk tatti🤭
@@user-pw1nl6jy8q it's 2th grade for me
Let the three numbers be x-1, x , x+1.
So, (x-1) + (x) + (x+1) = 60
3x = 60
x = 20
Hence, the largest number = x + 1 = 20+1 = 21.
how is this a math olympiad question
Exactly my thought. Grade 6 question.
Exactly
Suuuuu ronaldo
@@nilusingh377 it is... for kindergardeners
I like your handwriting
First of all this is something a 1st grader must know to continue living in Asia…… No drama
Actually There are 2 ways to do this question such as the one the teacher did and if x=19 because x+[x+1]+[x=2]=60
Then 19 plus 1 and 19 plus 2 is equal to 20 and 21
Therefore the largest number is D 21
Let the numbers be x-1,x,x+1. That adds up to 3x=60, x=20. The largest is x+1=21. This should be a pre-k to kindergarten Olympiad question (which doesn’t exist) max since people can guess the numbers easily.
You are giving very nice knowledge to everyone…awesome
X=60÷3+1 since there is 3 consecutive numbers are so the middle is 1 number away from the end and the start thats why we put +1
And 20+1=21 done
See look at the options DO NOT use traditional methods using x to calculate the value rather if you see the options you can infer that if 21 is the largest other two are 19 and 20 if you add these together you will get 60 so 21 is the correct answer
this is very bad approach to solve these type of questions instead assume the first number be x and x+1,x+2 then
x+(x+1)+(x+2)=60
3x+3=60
3x=57
x=19
hence the numbers are 19,20,21
Instead of saying its a bad method, you should say it's a more clever method if you see. Because 20+20+20 is 60 and if you subtract one from one 20 and add that to the other 20 you get 19+20+21 equals 60.
You calculated the smallest number first. Why? The question asked for the "largest number "
so x+(x-1)+(x-2)=60
Let the three numbers be x-1, x , x+1.
So, (x-1) + (x) + (x+1) = 60
3x = 60
x = 20
Hence, the largest number = x + 1 = 20+1 = 21.
@lakshitachoudhary6953 you calculated the middle number why?
Let the first consecutive number be x
So,
the second consecutive number is x+1
the third consecutive number is x+2
Equation according to the question -
x+x+1+x+2 = 60
3x+3 = 60
3x = 60-3
3x = 57
x = 57/3
x = 19
First consecutive number (x) = 19
Second consecutive number (x+1) = 19+1 = 20
Third consecutive number (x+2) = 19+2 = 21
So the three consecutive numbers whose sum is 60 are 19, 20 & 21.
Answer check -
19+20+21 = 60
This is what we needed according to the question so the answer is correct
By a 8th grader.... ❤
Let the smallest number be x.
x + (x + 1) + (x + 2) = 60
Or, 3x + 3 = 60
Or, 3x = 60 - 3
= 57
Or, x = 19
The largest number is (x + 2) = 19 + 2 = 21 [Option d is correct]
That's not a solution. If X is the number you seek, then
X+(X-1)+(X-2) = 60 = 3X -3. Then 3X = 63. So X = 21.
let the middle number be x
x-1+x+x+1=60
=> 3x = 60
=> x = 20
Largest number = x + 1 = 20 + 1 = 21
Let the 2nd no be x so 1st is x-1 then 3rd no is x +1 so sum is x -1+ 1 + x+x = 3x = 60. SO x=20 and the largest no. Is x +1 that is 21.
Bro she shows a 4th class question and says it is an olympiad question. :d
Let the number be x
according to question x+x+1+x+2=60
3x=60-3
3x=57
x=57/3
x=19
Even a ten years old kid can solve this💀💀
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This question is actually not even school level lmao, u just have to:
Suppose the three cons. No. As x-1,x,x+1
X-1+x+1+x=60
3x=60
X=20
Since the largest no is x+1
Then yo answer is 21😊
X + (x-1) +(x+1)=60. 3x=60 and x =20 therefore x+1=21 and d arrived at algebraically
Let three consecutive no. be
(x-1), x, (x+1)
Then by given condition-
(x-1)+x+(x+1) = 60
3x=60
X=20
Then largest no. Is x+1
So, 20+1 =21❤❤❤
cool short especially for the time constraint but this question has the same difficulty as #4 on amc10 so i doubt it's olympiad level status
literally took me 5 SECONDS!
And some think you may be lying.
You are not lying - took me about the same
@@truebeliever5688 maths degeneration. We can't let real education die
Yea me too literally did it in *4 seconds* in my mind
same bro
Same
Instead of this , try all options , that will be easy and not confusing 🤷
Easiest question in the world
Great trick to solve this problem. But shouldn’t students know how to solve this problem algebraically?
Let x=smallest number , x+1=, middle number and x+2= largest number then x+x+1+x+2=60.
3x+3=60, x=19 largest number is x+2=21 choice d. I look forward to hearing, speaking, and conversing with you. Take care, bye, bye, and have fun!!!😅
No way this is an olympiad question, I don't believe it.
a+b+c=60 60/3 since there are 3 numbers. They have to be dancing somewhere around 20. 1 less than it, 1 more than it. 19 ,20, 21. 21 is the largest number of the 3. As you can tell, I didn't really take an algebraic approach but you could also solve it that way. x+x+1+x+2=60 3x+3=60 3x=57 x=19, x+2 is the largest number 19+2=21
Not close enough for Olympiad paper question status. Would make a good first 5 question for a junior challenge paper
You could just do like 21 + the two smaller consecutive numbers bro😭
This actually help's bc im preparing for one and it's tmr
Why not 30? Because 60/2 = 30…
30 + 30 = 60 _but_ we need 3 numbers so if we subtract 1 from the first 30 we get:
1+29+30 = 60
Right!?
Edit:
Why not 1+2+57 = 60
And are we limited to integers?
Am I stupid? Idk, I think the question needs to be re-stated because you can literally pick any number of the four options that were given.
Edit2: okay, nvm, she meant the mathematical definition of consecutive.
The defination of consecutive mathematical or not is still number that are one after other like 1,2,3 😅
@@Kixe_777 I was thinking like items in a list. Where the list can be unordered.
@@Kixe_777 I was thinking like items in a list. Where the list can be unordered. And then you find the sum of three consecutive items in a list.
Super trick
Hi can you solve this math
A🐻B=(a+3)-b
A🐰B=(a+b)+2
27🐰(12🐻2)=?
This is NOT what a math olimpiad looks like. It's a lot more difficult. Even the first olimpiad, which is in forth grade from what i remember is a lot more difficult, but if you look at something like 7th, 8th or maybe 9th grade you will find some stuff with solutions almost impossible to find
Helped A Lot In IMO
Surprise test in grade 8 in my school used to have harder question than this.
Nice
Are you from India
Um at this point I think trial and error is easier and faster with mental calculations
60/3=20 (median)
20+1= 21
Dam thx so much
This is just way too easy - did it in my head
If we add 20 +20+20=“60”it isAlso 60 the answer is 21 not 20
21..
cause 19+20+21=60
this is very easy. we need any difficult q
It is nothing in front of IOQM
If its an Olympiad question then Im Ramanujan.
A2+B3+C4=?
aise question mai bachpan mai karta tha bhai
This is nice
Ya sure
Its really tough 😭😭
Are you sure that this is a Math Olympiad Question?
Can u tell me where did u get that pen?
Thanks
Where did u buy that pen???!!
Teach them to make sentences: X+(x+1)+(x+2)=60
It's called equations 😼
Nice❤❤
So which is not devided by other number is consecutive process 🤟🏼
Where did u buy that pen?
New subscriber ..
I learned this in 7th grade
This is not even close to easiest question of imo
thanks sir 🙏💯
Itne easy question nahi hote olympiad
Nice
good.
21
Very rasy question 😂❤
21 took 5 seconds in mind😂😂😂
❤❤❤❤
Bacha bhi solve karle ma'am
You have to take more questions please my Imo Exam is near
Easy question
D
D (21)
easiest q ever
It is of which class
Who woulf actually divide and do the way he said if ur teacher didnt specifically tell u tp do that 😊
It’s easy ❤
This is math Olympiad for 1st graders??
Answer (c) 20
Aennn ?????
_+_+_=60
60÷3=20
20+20+20=60
Itna karna jaruri tha ki 20 less 19 greater 21 🙂👍🤣🤣🤣
21 wala like karo
What if 1+2+57=60
D 21
19+20+21=60
Ans. 21
It's so easy
this is a 8th-9th grade question
21 no. Wala answer hai
So easy
Hinder”
21 is correct 💯 answer
d. 21.