Synthetic Division with a Quadratic Divisor
Вставка
- Опубліковано 1 жов 2024
- This video shows an example of how to use synthetic division when the denominator or divisor is a quadratic function. It might me easier to use long division for this process, but if you are required to use synthetic division, hopefully this video will help you.
If you want to view all of my videos in a nicely organized way, please visit mathandstatshe... . It is free for anyone to use. Please share with others you know who are struggling with math topics or statistics.
Thank you. I was looking for this... Just one question, please tell me what changes I'd have to make for a non monic quadratic. Also will it help if i factorise the quadratic first and then repeatedly divide.
Wow, this is new to me! Lucky UA-cam recommended this video, thank you for the new knowledge
Very informative, thanks for all the work
correction -6 +(-6) + 8= -4
This doesn't work it's not a monic quadratic right?
How would you do this if the x^2 coefficient was something other than one?
She explained that you would need to divide all coefficients by the leading coefficients
@@johngambino5105 Damn I must have been really tired when I made this comment XD, thanks for replying anyway
not sure but i would guess if the equation is like ax^2 + bx +c then u can write it was a(x^2+b/a*x+c/a) and do it then
Why is there x in the remainder 2x? I got the rest but that one..
The table from left to right goes down in degree, so the second to last one will be of degree 1
If you were to do long division, you would probably be able to see the remainder better. Basically what happens is that you have a remainder in both the linear and constant terms.
It is useful for Bairstow's method
Write it in a loop
how to divide when the power of X in divisor is greater than the dividend?
Math and Stats Help, can you make a video about the addition & subtraction of Integers?
Thank you!!!
what if the divisor is x^2 - 2x -1
You would put the opposite sign on the outside for the linear and constant term. 2 and 1 would be used.
Very nice explanation 😁😁😀
Thank you