Hey kieno I don’t know if you still Maintain the channel but just wanted to tell you that as a former teacher myself, you have a real gift of explaining and teaching. Your videos have been very helpful and hopefully you’re doing well.
Hello Kieno Thomas. thanks for the video. i was wondering, how would the m.a change if the little brother where to jump from X distance onto the effort arm? i remember there was a question in the PICAT that used that information. any help is greatly appreciated. thank you!
Miguel Magana well for one he would have the downward force of gravity on his side so mass * 9.81m/s^2 * distance That would be a good place to start. This deals with potential energy, if it were kinetic energy (.5 * m * v^2)
This was fantastic! You made it so clear and concise. Thank you!
Hey kieno I don’t know if you still
Maintain the channel but just wanted to tell you that as a former teacher myself, you have a real gift of explaining and teaching. Your videos have been very helpful and hopefully you’re doing well.
I am and thank you for the kind words. I love to teach!!!!
On the soldier and the barrel problem, first you multipr 300lbs.2inch and then divide 600lbs /8ft(aren't supposed to convert ft in to inch)
I was thinking the same thing. Other than that, these videos have been a help. Btw did you ever get and answer?
If you make the 2 inches 2 feet the math seems to check out. I think he mistakenly used inches.
Thank you so much! Simple and very intuitive :)
This is so helpful and you are an awesome teacher! Thank you so much for sharing.
in the video at 11.22 isnt the weight at 4 inches 240 lbs not 210. 840 is for 14 inches, 1 inches is worth 60lbs, 4 times 60 is 240lbs
ur class helps a mass when i try to read the boring guide book, some time i event have to refer to the dict. ＆。＆
great job thomas!
could you divide the lbs as well to find the M.A for any other similar problem?
Hello Kieno Thomas. thanks for the video. i was wondering, how would the m.a change if the little brother where to jump from X distance onto the effort arm? i remember there was a question in the PICAT that used that information. any help is greatly appreciated. thank you!
Miguel Magana well for one he would have the downward force of gravity on his side so mass * 9.81m/s^2 * distance
That would be a good place to start. This deals with potential energy, if it were kinetic energy (.5 * m * v^2)
Is this the first time you taught this?
Great video, thanks for your efforts, it helped a lot.
Thanks!!
ua-cam.com/video/Oe7egRbFe-k/v-deo.html
thank you for the video, but can you work on your writing it would be helpful
get rekt
Rude