After the step r = d(x,p) > 0 we say that we create an open ball of radius r with center p should be a subset of X - A. I want to ask why have we created a ball of radius r why not K > R? Because if we will create a ball of radius greater than R then the open ball will also contain the singleton set.
If we take a ball with Radius greater than r then it will contain point p, here our target is to find a ball which does not contain p i.e. it should lie in X-A
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Your teaching is fabulous sir
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Nice presentation
After the step r = d(x,p) > 0 we say that we create an open ball of radius r with center p should be a subset of X - A. I want to ask why have we created a ball of radius r why not K > R? Because if we will create a ball of radius greater than R then the open ball will also contain the singleton set.
If we take a ball with Radius greater than r then it will contain point p, here our target is to find a ball which does not contain p i.e. it should lie in X-A
pls make video on compact ms
Sir please upload full bsc 3 rd year mathematics
A={f€C[a,b] ; f(a)=1 } sir ise closed subset prove krna h C[a,b] ka w.r.t supremum metric.
Hi sir,my sister is having supply in this subject,can you pls help her with a tution online.can I have your contact pls.