Pythagoras Triplet का ये खेल Calculation की दुनिया पलट देगा🔥

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सर आप कितना शानदार पढ़ते है मैंने आप से पढ़ कर मैथ्स सिखा है आप ने हमें मैथ्स सब्जेक्ट से अच्छे से रूबरू कराया है मै आप का सदा आभारी रहूंगा | धन्यवाद ! सर MG Concept ❤❤❤❤

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❤
Excellent
EXTRA ORDINARY METHOD.

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Thanks!

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[@nareshkange2978]

A = 2mn
B = m2 - n2
C = m2 + n2
Where m>n
A+C=2mn+(m2 + n2) =m2 +2mn+ n2=(m+n) 2,so √(A+C) =B, when m-n=1
Let another way, example C=29
Adjust C=sum of two square, let C=m×m+n×n=m^2 +n^2=5×5+2×2=5^2+2^2=29
We get m=5 & n=2
So A=2mn=2×5×2=20, B=m×m-n×n=5×5-2×2=25-4=21
So the triplet is (20, 21,29)
In this way get triplet if we got C as the sum of two squarer numbers
Another example
C=97=81+16, so m=9, n=4
So A=2mn=2×9×4=72
B=m2--n2=9×9-4×4=81-16=65
So the triplet is (72, 65,97)
Inthis if we have A or B given,
Then if one of those are even, then divide it by 2, coming number conever in two number products, big number is m & small number is n, or adjust subtracting of two squarer number if odd

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