Hi, thanks for this video its helped clear some questions for me. For the second example, the two corners on the top right and top left are 2 link members which if no force are acting on those two points those members would just be zero members. How come the truss is still considered statistically determinant when it seems like those 4 extra members are redundant.
Mansour Al Darei hey man thanks for the feedback. This is simply an exercise in determining determancy to be honest, were not really looking at zero force members here. Also we dont know the loading or these trusses, if those points are loaded then they are no longer zero force members. However it's a good point and shows that you're really thinking about and understanding the problems, in this one however it's a very simplistic example to highlight the concept. Hope that helps :)
Thanks a lot, I saw some of the other determinacy videos and realized how much I didn't know especially since we started analysing indeterminate structures. Been a great help!
Yea once you get into indeterminate structures you see how complicated actual structures can really be! Luckily we have software to help us these days :D nice chatting with you!
This analysis is for the members of the Truss. if we solve for the reactions, we would have another criterion? Something like the number of reactions vs the number of equations of equilibrium?
I think it's important to understand how this equation works, then it would make sense how to modify it for fixity. There's a 2 coefficient in front of J because we're assuming these trusses are all pins, and at each joint we have a reaction in x and y with no moment reaction. Thus two equilibrium equations. Around 2:00 we go over this. If we introduce a moment reaction, we now have 3 equilibrium equations per joint. See if from that you can reason out how the equation would change.
mani kanta godi theyre not 4 members connected to each other on the middle, that would kind of defeat the purpose of the bracing. Theyre two members thst arent connected to each other.
nice bro. .the way you explained was really easy to understand..but some trusses are stable according to equation but was actually an unstable structure as you have explained in example 3..please make a video on these cases so that there would be no confusion...thank you
mani kanta godi great, glad to hear it helped! Yea we have alot of video ideas but no time right now unfortunately, hopefully we can get back to the videos soon!
Check out our video on 3D indeterminacy: ua-cam.com/video/LoNBK64WLng/v-deo.html
Wonderful explanation very useful do more videos on structural analysis
Hi, thanks for this video its helped clear some questions for me. For the second example, the two corners on the top right and top left are 2 link members which if no force are acting on those two points those members would just be zero members. How come the truss is still considered statistically determinant when it seems like those 4 extra members are redundant.
Mansour Al Darei hey man thanks for the feedback. This is simply an exercise in determining determancy to be honest, were not really looking at zero force members here. Also we dont know the loading or these trusses, if those points are loaded then they are no longer zero force members. However it's a good point and shows that you're really thinking about and understanding the problems, in this one however it's a very simplistic example to highlight the concept. Hope that helps :)
Thanks a lot, I saw some of the other determinacy videos and realized how much I didn't know especially since we started analysing indeterminate structures. Been a great help!
Yea once you get into indeterminate structures you see how complicated actual structures can really be! Luckily we have software to help us these days :D nice chatting with you!
This analysis is for the members of the Truss. if we solve for the reactions, we would have another criterion? Something like the number of reactions vs the number of equations of equilibrium?
Is there a video for beams and composite structures?
No composite structures yet, we have some beam videos in our concrete section, more to come.
Wouldn't the 3rd problem be a compound truss?
What if it was a rigid joint truss or a truss with some rigid joints? How can we change the formula? Thanks for the video!
I think it's important to understand how this equation works, then it would make sense how to modify it for fixity. There's a 2 coefficient in front of J because we're assuming these trusses are all pins, and at each joint we have a reaction in x and y with no moment reaction. Thus two equilibrium equations. Around 2:00 we go over this. If we introduce a moment reaction, we now have 3 equilibrium equations per joint. See if from that you can reason out how the equation would change.
nice but I didn't get the last example..how the number of members are 21....I thought it was 29
mani kanta godi i think youre counting each brace as two..those braces are single members, so count each cross brace as 1 instead of 2.
but are they not hinged at the middle? they are just left open?
mani kanta godi theyre not 4 members connected to each other on the middle, that would kind of defeat the purpose of the bracing. Theyre two members thst arent connected to each other.
nice bro. .the way you explained was really easy to understand..but some trusses are stable according to equation but was actually an unstable structure as you have explained in example 3..please make a video on these cases so that there would be no confusion...thank you
mani kanta godi great, glad to hear it helped! Yea we have alot of video ideas but no time right now unfortunately, hopefully we can get back to the videos soon!