BAHUT BADHIYA SIRR .... HUM STUDENTS KE BAHUT SAARE CONCEPTS CLEAR NHI HO PAATE JUST BECAUSE OUR TEACHING FACULTY SUCKS... BUT APKE WAJAH SE BAHUT SAARE CRUCIAL CONCEPTS CLEAR HO GAYE HAII 😎😎
You can see that I had taken general terms so it is necesaary to show this condition for all element if anyone of the element fails to do this we say that set is not a subgroup
Thank u sir soo much i have weekly test tomorrow and now i am confident that i will gain complete marks in this unit and sir please request please upload other units also i have main exam in january
I taught lectures in such a way that while watching you can make notes by yourself as most of the things I usually write and this will help you a lot ...but I will try to make handwritten notes and soon be available
He got it wrong. One should check every possible pair of H's elements to see if their binary operation results in an element in H, not just any one pair
@@thetaclasses You said that "Koi zaroorat nahi hai ki aap ye pura long process karne". Picking all the pairs of elements, operating them and verifying them is still a long process, much like the direct method.
You have to take general elements for example in a set of even integers you will take two elements as 2m and 2n and on operating them 2m-2n=2(m-n) which is also a eveb integer
BAHUT BADHIYA SIRR .... HUM STUDENTS KE BAHUT SAARE CONCEPTS CLEAR NHI HO PAATE JUST BECAUSE OUR TEACHING FACULTY SUCKS... BUT APKE WAJAH SE BAHUT SAARE CRUCIAL CONCEPTS CLEAR HO GAYE HAII 😎😎
Ap ki samj100% aty hy
Super sir ji 🙏🙏🙏💪💪🙏
Thanks a lot Sir,after watching many videos my concept is Cristal clear.
Superb sir 👌👌👌👌👌
Thank you sir💞
Nice explanation ❤
Thank you, Sir.
Sir g linear algebra kub pray gy
Sir please complete group theory our course
Yes I will
Sir please group ki bhi sari theorem ke video banaye plese aap bahut axa samjhate hai
Humnble requeste
yes sure i will definitely do this
Thanks sir
In the last example is it necessary to hold the condition for all elements
You can see that I had taken general terms so it is necesaary to show this condition for all element if anyone of the element fails to do this we say that set is not a subgroup
@@thetaclasses thank you 👍
Sir abstract algebra k bi same yhi subgroups test ha na??
What you are referring in abstract algebra
Thank you
Kitna time lgy ga
It will take time to start linear
Mja aa gya
Sir wb slst mathematics subject k liye knsa best practice set book hee
Sir plz tell me
I am unable to understand can you please elaborate?
Sir can you upload pic of the whiteboard after you are done writing!?
Okay from now onwards I will pause after writing so that you all can take screen shot
Thank u sir soo much i have weekly test tomorrow and now i am confident that i will gain complete marks in this unit and sir please request please upload other units also i have main exam in january
I will try to upload other parts also
🎉
Sir aap hum toh chalega but examiner ka kya
I am unable to understand what you are saying
Sir it's a request that you upload PDF of the lecture.
I taught lectures in such a way that while watching you can make notes by yourself as most of the things I usually write and this will help you a lot ...but I will try to make handwritten notes and soon be available
😮
He got it wrong. One should check every possible pair of H's elements to see if their binary operation results in an element in H, not just any one pair
If you listen carefully i said at 7:18 that take any two element not just any one pair
@@thetaclasses You said that "Koi zaroorat nahi hai ki aap ye pura long process karne". Picking all the pairs of elements, operating them and verifying them is still a long process, much like the direct method.
You have to take general elements for example in a set of even integers you will take two elements as 2m and 2n and on operating them 2m-2n=2(m-n) which is also a eveb integer