Solving Rational Inequalities Using the Number Line and Test Intervals

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  • Опубліковано 29 вер 2024

КОМЕНТАРІ • 8

  • @Dreamprism
    @Dreamprism 6 місяців тому +3

    Great explanations for any students first learning this watching. This concept will continue to be useful to students even as they go into Calculus, as it's used to analyze derivative functions too.
    I like how you just do the filled in versus open circles at the values where the numerator is zero based on knowing whether you want to solve a strict inequality (less than zero) or a non-strict inequality (less than or equal to zero). It streamlines the process compared to the alternative of specifically marking each value as a spot where the rational expression is zero versus undefined and then later checking whether or not you want to include the endpoint.
    For the sake of variety, I think it would've been good to include an example where there is a squared factor (so that the sign chart does not constantly alternate between plus and minus).
    And I personally like mentioning the shortcut where you check the powers on each factor save massive amounts of time in determining signs (switch signs when crossing over any value corresponding to a factor with an odd power & keep the same sign when crossing over any value corresponding to a factor with an even power). Unfortunately, that may be too difficult to teach from the basics in a 10-minute video, and a lot of teachers wouldn't accept it as showing your work on a test (even though it's mathematically sound if a student can explain why it works).
    I see often you design your UA-cam lessons so the work matches what you expect almost all teachers would accept.

  • @ImMingoooo
    @ImMingoooo 6 місяців тому +1

    Im sorry mario-senpai

  • @vic_you_crazyy9429
    @vic_you_crazyy9429 26 днів тому

    On example 2 when we were looking for the common denominator to get one fraction, why did we treat the 2 as a negative? Also, why did we distribute the -2 it to the (x +1 ) for the numerator but on the denominator we simply stated (x - 3 ) ( x + 1) to set it to 0?

  • @DisneyProduction-zl4oq
    @DisneyProduction-zl4oq Місяць тому

    Hi! Sir actually some inequality includes Square roots which get me into trouble. Plz make a video on this as well.

  • @kingkura
    @kingkura 6 місяців тому +1

    Thanks

  • @RedSytheMMVI
    @RedSytheMMVI 6 місяців тому

    I bumped into this this weekend, and it’s such a coincidence you uploaded this recently lol. Thank you for the explanation :)

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    @ZaibiDesigner 6 місяців тому

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