In the material balance determining R and E, why did you not use the solute for balance and instead use overall, carrier, and solvent balance? I tried it myself and it gave some completely different flow rates of R and E. Is there some sort of rule since the values of flow rates vary depending on which two balances are used?
Thanks for the comment. You should get the same answer if you use a different 3 balances (say, solvent, solute, and overall), but the overall is often used because it is a simpler equation. The other options are sometimes arbitrary. I don't know why you got a different answer.
@@LearnChemE I find this problem odd since you have to average the resulting flow rate (which in this case, the R) from two pairs of balances (overall-solvent and overall-carrier), so I tried the other pair (overall-solute). The balance should obviously reach the same answer but instead it didn't thus I asked. (see 7:29) Anyway, thanks for responding as soon as I asked. Your channel has been a great help for my review so I really appreciate your work.
Thanks for your question. Once you have the mixing point, you draw a tie line through that, and the raffinate and the extract are on either side of the envelope. Then you just read the values from the diagram.
how do you estimate the tie line?
+LearnChemE how did you draw the tie line,once you got the M(mixing point)??
it was an interpolation based off of the tie lines drawn above and below it.
same doubt how are we drawing the tie line through M. can anybody please tell ?
What if we dont have the tie-lines to help us making a parallel line?
how are we drawing the tie line through M. can anybody please tell ?
It is an estimate based on the tie lines above it.
@@LearnChemE ??
@@divyansh1719 The tie line (dotted line) is estimation in parallel with respect to the solid line in equilibrium.
In the material balance determining R and E, why did you not use the solute for balance and instead use overall, carrier, and solvent balance? I tried it myself and it gave some completely different flow rates of R and E. Is there some sort of rule since the values of flow rates vary depending on which two balances are used?
Thanks for the comment. You should get the same answer if you use a different 3 balances (say, solvent, solute, and overall), but the overall is often used because it is a simpler equation. The other options are sometimes arbitrary. I don't know why you got a different answer.
@@LearnChemE I find this problem odd since you have to average the resulting flow rate (which in this case, the R) from two pairs of balances (overall-solvent and overall-carrier), so I tried the other pair (overall-solute). The balance should obviously reach the same answer but instead it didn't thus I asked. (see 7:29)
Anyway, thanks for responding as soon as I asked. Your channel has been a great help for my review so I really appreciate your work.
Man you saved my skin. Thanks a huge lot
how are we drawing the tie line through M. can anybody please tell ?
Yes making parallel line to above lines🕳
@@jahanzaibiqbal3211 NOT PARALLEL LINES, its through interpolation
Hi, please, do you have any book to indicate on this subject? Thank you!
Thanks for the video.
(Play it at 1.25% speed)
how did u get the extract-point above the S?
Thanks for your question. Once you have the mixing point, you draw a tie line through that, and the raffinate and the extract are on either side of the envelope. Then you just read the values from the diagram.