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Very good sir
Nice, many thanks, Sir!∎GFED → GF = FE = DE = GD = a; ∆ ABC → AB = 5; BC = 4; AC = 3; sin(BCA) = 1; ABC = DEC = GDA = δ → sin(δ) = 3/5 → BE = 5a/3 → CE = 4a/5 → 4 = 5a/3 + 4a/5 = 37a/15 → a = 60/37
many thanks, too🥰
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💬Comment
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Very good sir
Nice, many thanks, Sir!
∎GFED → GF = FE = DE = GD = a; ∆ ABC → AB = 5; BC = 4; AC = 3; sin(BCA) = 1; ABC = DEC = GDA = δ →
sin(δ) = 3/5 → BE = 5a/3 → CE = 4a/5 → 4 = 5a/3 + 4a/5 = 37a/15 → a = 60/37
many thanks, too🥰